Thankyou very much arun,I worked perfectly.:D
Eliza
Date: Sat, 22 Mar 2014 13:18:21 -0700
From: smartpink...@yahoo.com
Subject: Re: Latest question
To: r-help@r-project.org
CC: eliza_bo...@hotmail.com
HI Eliza,
No problem.
This should be faster:
res2 - matrix(as.vector(
HI Eliza,
No problem.
This should be faster:
res2 - matrix(as.vector( mat1[row.names(mat1) %in% df1$Ry,colnames(mat1) %in%
df1$Rx]),nrow=120, dimnames=list(NULL,colnames(res)))
identical(res,res2)
#[1] TRUE
A.K.
On Saturday, March 22, 2014 4:14 PM, eliza botto eliza_bo...@hotmail.com
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