Yes. Also notice that something fishy seems to be going on in columns 2 and 3
(assuming that the date/time is 1 column).
They appear to be read as character data, even though the content is numeric?
-pd
> On 24 Sep 2023, at 11:58 , Michael Dewey wrote:
>
> Dear David
>
> To get the first 46
A B
1 1 0
2 2 1
3 3 2
4 4 3
5 5 4
6 6 5
7 7 6
8 8 7
9 9 8
-Original Message-
From: R-help On Behalf Of Parkhurst, David
Sent: Saturday, September 23, 2023 6:55 PM
To: r-help@r-project.org
Subject: [R] Odd result
With help from several people, I used file.choose()
For what it's worth the janitor::remove_empty() (which removes all-NA
rows by default, can be set to remove columns instead) can be useful for
this kind of cleanup.
On 2023-09-24 5:58 a.m., Michael Dewey wrote:
Dear David
To get the first 46 rows just do KurtzData[1:43,]
However really
st, David ; r-help@r-project.org
Subject: Re: [R] Odd result
[External Email]
On 23/09/2023 6:55 p.m., Parkhurst, David wrote:
> With help from several people, I used file.choose() to get my file name, and
> read.csv() to read in the file as KurtzData. Then when I print KurtzData,
> the
On 23/09/2023 6:55 p.m., Parkhurst, David wrote:
With help from several people, I used file.choose() to get my file name, and
read.csv() to read in the file as KurtzData. Then when I print KurtzData, the
last several lines look like this:
39 5/31/22 16.0 3411.75525
Dear David
To get the first 46 rows just do KurtzData[1:43,]
However really you want to find out why it happened. It looks as though
the .csv file you read has lots of blank lines at the end. I would open
it in an editor to check that.
Michael
On 23/09/2023 23:55, Parkhurst, David wrote:
With help from several people, I used file.choose() to get my file name, and
read.csv() to read in the file as KurtzData. Then when I print KurtzData, the
last several lines look like this:
39 5/31/22 16.0 3411.75525 0.0201 0.0214 7.00
40 6/28/22 2:00 PM 0.0
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