Re: [R] Pass an operator to function

On 30/11/2010 9:54 PM, randomcz wrote: Hi guys, How to pass an operator to a function. For example, test- function(a, , b) { return(ab) #the operator is passed as an argument } Thanks, It's much simpler than the other suggestions. Just pass the operator, and treat it as a

[R] Pass an operator to function

Hi guys, How to pass an operator to a function. For example, test - function(a, , b) { return(ab) #the operator is passed as an argument } Thanks, -- View this message in context: http://r.789695.n4.nabble.com/Pass-an-operator-to-function-tp3066627p3066627.html Sent from the R help

Re: [R] Pass an operator to function

Here's one way that works with *some* operators (I do not believe you actually could generalize to *every* operator because some are unary and some are binary (see example cases). test - function(a, op, b) { foo - match.fun(FUN = op) return(foo(a, b)) } test(5, , 4) test(5, , 4) test(5, +,

Re: [R] Pass an operator to function

On Nov 30, 2010, at 9:54 PM, randomcz wrote: Hi guys, How to pass an operator to a function. For example, test - function(a, , b) { return(ab) #the operator is passed as an argument } I think you have just requested the definition of do.call() although you infix positioning is a

Re: [R] Pass an operator to function

Here is one way... f - function(a, b, op===) {  call - call(op, a, b)  result - eval(call)  # possibly do other stuff  result } f(1, 2) [1] FALSE f(1, 2, ) [1] TRUE Michael On 1 December 2010 13:54, randomcz rando...@gmail.com wrote: Hi guys, How to pass an operator to a function. For

Re: [R] Pass an operator to function

Thanks, that helps. -- View this message in context: http://r.789695.n4.nabble.com/Pass-an-operator-to-function-tp3066627p3066696.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list

Re: [R] Pass an operator to function

If you only want to deal with the less than or greater than operation a cheap trick would be: test - function(a, b, sign) { foo - (a*sign b*sign); return(foo); } might have to tweak the syntax. The idea behind this is that 53: TRUE -5-3: FALSE (i.e. I've multiplied both sides by sign(-1))