Dear all,
I have some trouble understanding the chisq.test function.
Take the following example:
set.seed(1)
A - cut(runif(100),c(0.0, 0.35, 0.50, 0.65, 1.00), labels=FALSE)
B - cut(runif(100),c(0.0, 0.25, 0.40, 0.75, 1.00), labels=FALSE)
C - cut(runif(100),c(0.0, 0.25, 0.50, 0.80, 1.00),
: Tuesday, September 27, 2011 12:45
To: r-help@r-project.org
Subject: [R] Pearson chi-square test
Dear all,
I have some trouble understanding the chisq.test function.
Take the following example:
set.seed(1)
A - cut(runif(100),c(0.0, 0.35, 0.50, 0.65, 1.00), labels=FALSE)
B - cut(runif(100),c
Sent: Tuesday, September 27, 2011 13:28
To: Michael Haenlein; r-help@r-project.org
Subject: Re: [R] Pearson chi-square test
Not sure what you want to test here with two matrices, but reading the
manual helps here as well:
y a vector; ignored if x is a matrix.
x and y are matrices
To: Michael Haenlein; r-help@r-project.org
Subject: RE: [R] Pearson chi-square test
Just for completeness: the manual calculation you'd want is most likely
sum((x-y)^2 / (x+y))
(that's one you can find on the Wikipedia link you provided). To get the
same from chisq.test, try something
-project.org
Cc: Meyners, Michael
Subject: RE: [R] Pearson chi-square test
Dear Michael,
Thanks very much for your answers!
The purpose of my analysis is to test whether the contingency table x is
different from the contingency table y.
Or, to put it differently, whether there is a significant difference
5 matches
Mail list logo
