Re: [R] Populate a matrix

2011-10-06 Thread fernando.cabrera
This last solution is what I was looking for, I was trying to avoid loops. Thanks! -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Rainer Schuermann Sent: 5. oktober 2011 18:29 To: r-help@r-project.org Subject: Re: [R] Populate a

Re: [R] Populate a matrix

2011-10-05 Thread Rainer Schuermann
m <- matrix( rep( y, length( x ) ), length( y ), length( x ) ) On Wednesday 05 October 2011 18:11:18 fernando.cabr...@nordea.com wrote: > Hi guys > > I have vectors x <- c(1,2,3,4) and y <- c(4,3,9) and would like to generate a > matrix which has 3 rows (length(y)) and 4 columns (length(x)), a

Re: [R] Populate a matrix

2011-10-05 Thread R. Michael Weylandt
One more version: somewhere in the middle of the explicitness scale, matrix(rep(y, times = length(x)), nrow=length(y)) On Wed, Oct 5, 2011 at 12:17 PM, R. Michael Weylandt wrote: > matrix(rep(y, each=length(x)), nrow=length(y), byrow=TRUE) > or less explicitly >  matrix(y, nrow=length(y),ncol=l

Re: [R] Populate a matrix

2011-10-05 Thread R. Michael Weylandt
matrix(rep(y, each=length(x)), nrow=length(y), byrow=TRUE) or less explicitly matrix(y, nrow=length(y),ncol=length(x)) Michael On Wed, Oct 5, 2011 at 12:11 PM, wrote: > Hi guys > > I have vectors x <- c(1,2,3,4) and y <- c(4,3,9) and would like to generate a > matrix which has 3 rows (length(y

Re: [R] Populate a matrix

2011-10-05 Thread Samuel Le
org Subject: [R] Populate a matrix Hi guys I have vectors x <- c(1,2,3,4) and y <- c(4,3,9) and would like to generate a matrix which has 3 rows (length(y)) and 4 columns (length(x)), and each row is the corresponding y element repeated length(x) times. 4,4,4,4 3,3,3,3 9,9,9,9 Thanks.

[R] Populate a matrix

2011-10-05 Thread fernando.cabrera
Hi guys I have vectors x <- c(1,2,3,4) and y <- c(4,3,9) and would like to generate a matrix which has 3 rows (length(y)) and 4 columns (length(x)), and each row is the corresponding y element repeated length(x) times. 4,4,4,4 3,3,3,3 9,9,9,9 Thanks. Fernando Álvarez