Hi,
So I just took an intro to R programming class and one of the lectures was on
Regular Expressions. I've been playing around with various R functions that use
Regular Expressions.
But this has me stumped. This was part of a quiz and I got it right through
understanding the syntax. But when
On Tue, Oct 29, 2013 at 1:13 PM, Lopez, Dan lopez...@llnl.gov wrote:
grep(^([a-z]+) +\1 +[a-z]+ [0-9],lines)
Your expression has a typo:
R grep(^([a-z]+) +\\1 +[a-z]+ [0-9],lines)
[1] 2
--
Sarah Goslee
http://www.functionaldiversity.org
__
Please read and follow the Posting Guide, in particular re plain text email.
You need to keep in mind that the characters in literal strings in R source
have to make it into RAM before the regex code can parse it. Since regex needs
a single backslash to escape normal parsing and interpret 1 as
College Station, TX 77840-4352
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Lopez, Dan
Sent: Tuesday, October 29, 2013 12:13 PM
To: R help (r-help@r-project.org)
Subject: [R] Regular Expression returning unexpected results
Hi,
So I
To: Lopez, Dan; R help (r-help@r-project.org)
Subject: Re: [R] Regular Expression returning unexpected results
Please read and follow the Posting Guide, in particular re plain text email.
You need to keep in mind that the characters in literal strings in R source
have to make it into RAM before
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