Hello, I'm using the fArma package to estimate Hurst exponent by R/S method. I've some measurements in the following format: Call_number Call_duration
I'm using the following steps. Am new to R, so it would help if someone could please confirm if my steps are correct. Further, this method seems to give a value H ~= 0.8 (> 0.5). Is the use of R/S method to estimate H OK? > head(data, n=10) X1 X5402 1 2 1876 2 3 7653 3 4 2969 4 5 6215 5 6 2596 6 7 2434 7 8 1380 8 9 937 9 10 2047 10 11 712 > > rsFit(data[,2]) Title: Hurst Exponent from R/S Method Call: rsFit(x = data[, 2]) Method: R/S Method Hurst Exponent: H beta 0.8030667 0.8030667 Hurst Exponent Diagnostic: Estimate Std.Err t-value Pr(>|t|) X 0.8030667 0.05039722 15.93474 4.643595e-17 Parameter Settings: n levels minnpts cut.off1 cut.off2 227656 50 3 5 316 Description: Sun May 6 22:07:43 2012 by user: There were 14 warnings (use warnings() to see them) -- Thanks, Barun Saha JPA IIT, Kharagpur http://pothi.com/pothi/book/barun-saha-swapner-kheya http://delay-tolerant-networks.blogspot.com/p/one-tutorial.html [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.