I want to do the following: if a string does not contain a colon (:),
no change is needed; if it contains one or more colons, break the
string into multiple strings using the colon as a separator. For
example, happy: becomes
happy :
:sad turns to
: sad
and happy:sad changes to
happy : sad
strsplit(split=:) does almost what you want, but it omits the colons from
the output. You can use perl zero-length look-ahead and look-behind
operators in the split argument to get the colons as well:
strsplit(c(:sad, happy:, happy:sad), split=(?=:)|(?=:),
perl=TRUE)
[[1]]
[1] : sad
[[2]]
Actually, the zero-length look-ahead expression is enough to get the job
done:
strsplit(c(:sad, happy:, happy:sad, :happy:sad:subdued:),
split=(?=:), perl=TRUE)
[[1]]
[1] : sad
[[2]]
[1] happy :
[[3]]
[1] happy : sad
[[4]]
[1] : happy : sad : subdued :
Bill
Hi ,
Is there any inbuilt functions to check whether a substring is present in a
string and give the result as boolean
Thanks
--
View this message in context:
http://r.789695.n4.nabble.com/String-Manipulation-in-R-tp4633104.html
Sent from the R help mailing list archive at Nabble.com.
grepl
Michael
On Tue, Jun 12, 2012 at 8:51 AM, anjali jeevi...@gmail.com wrote:
Hi ,
Is there any inbuilt functions to check whether a substring is present in a
string and give the result as boolean
Thanks
--
View this message in context:
?grepl
Note that this function uses regular expressions, in which certain characters
have special meanings, so depending on what string you are looking for you may
have to know something about regex patterns to get it to work.
Hello,
Yes, there is. See ?grepl or help('grepl').
Hope this helps,
Rui Barradas
Em 12-06-2012 14:51, anjali escreveu:
Hi ,
Is there any inbuilt functions to check whether a substring is present in a
string and give the result as boolean
Thanks
--
View this message in context:
Or use 'fixed=TRUE' as an argument to grepl to avoid the regular
expression matching (but learning regular expressions will be a useful
tool in the long run).
On Tue, Jun 12, 2012 at 9:15 AM, Jeff Newmiller
jdnew...@dcn.davis.ca.us wrote:
?grepl
Note that this function uses regular
Hi Chris,
why not using routines for dates
dates - c(09/10/2003, 10/22/2005)
format(strptime(dates,format=%m/%d/%Y),%Y)
or take just the last 4 chars from dates
gsub(.*([0-9]{4})$,\\1,dates)
cheers
Am 29.09.2011 16:23, schrieb Chris Conner:
Help-Rs,
I'm doing some string manipulation in a
Help-Rs,
I'm doing some string manipulation in a file where I converted a string date in
mm/dd/ format and returned the date .
I've used regexpr (hat tip to Gabor G for a very nice earlier post on this
function) in steps (I've un-nested the code and provided it and an example of
Chris Conner wrote on 09/29/2011 09:23:02 AM:
Help-Rs,
I'm doing some string manipulation in a file where I converted a
string date in mm/dd/ format and returned the date .
I've used regexpr (hat tip to Gabor G for a very nice earlier post
on this function) in steps (I've
Message-
From: Steven Kennedy [mailto:stevenkennedy2...@gmail.com]
Sent: Friday, 26 August 2011 11:31 AM
To: Henrique Dallazuanna
Cc: Lorenzo Cattarino; r-help@r-project.org
Subject: Re: [R] string manipulation
You can split your string, and then only take the first 4 digits after
that (this is only
On Thu, Aug 25, 2011 at 9:51 PM, Lorenzo Cattarino
l.cattar...@uq.edu.au wrote:
Apologies for confusion. What I meant was the following:
mytext - I want the number 2000, not the number two thousand
and the problem is to select 2000 as the first four digits after the word
number. The
.* is greedy... might want regex number[^0-9]*([0-9] {4}) to avoid getting
1999 from I want the number 2000, not the number 1999.
---
Jeff Newmiller The . . Go Live...
DCN:jdnew...@dcn.davis.ca.us Basics: ##.#. ##.#.
On Fri, Aug 26, 2011 at 7:27 AM, Jeff Newmiller
jdnew...@dcn.davis.ca.us wrote:
.* is greedy... might want regex number[^0-9]*([0-9] {4}) to avoid
getting 1999 from I want the number 2000, not the number 1999.
If such inputs are possible we could also do this where we have added
a ? after the *
I R-users,
I am trying to find the way to manipulate a character string to select a 4
digit number after some specific word/s. Example:
mytext - I do not want the first number 1234, but the second number 5678
Is there any function that allows you to select a certain number of digits (in
this
Try this:
gsub(.*second number , , mytext)
On Thu, Aug 25, 2011 at 8:00 PM, Lorenzo Cattarino
l.cattar...@uq.edu.au wrote:
I R-users,
I am trying to find the way to manipulate a character string to select a 4
digit number after some specific word/s. Example:
mytext - I do not want the
You can split your string, and then only take the first 4 digits after
that (this is only an improvement if your numbers might not be at the
end of mytext):
mytext - I do not want the first number 1234, but the second number 5678
sstr-strsplit(mytext,split=second number )[[1]][2]
To be on the safe side in case there are other characters at the end
of the string, use:
mytext - I do not want the first number 1234, but the second number
5678sadfsadffdsa
# make sure you get 4 digits
sub(^.*second number[^[0-9]]*([0-9]{4}).*, \\1, mytext)
[1] 5678
On Thu, Aug 25, 2011
-
From: Steven Kennedy [mailto:stevenkennedy2...@gmail.com]
Sent: Friday, 26 August 2011 11:31 AM
To: Henrique Dallazuanna
Cc: Lorenzo Cattarino; r-help@r-project.org
Subject: Re: [R] string manipulation
You can split your string, and then only take the first 4 digits after
that (this is only
Dear all, I have following kind of character vector:
Vec - c(344426, dwjjsgcj, 123sgdc, aagha123, sdh343asgh, 123jhd51)
Now I want to split each element of this vector according to numeric and string
element. For example in the 1st element of that vector, there is no string
element. Therefore
On Sun, Jun 26, 2011 at 10:54 AM, Megh Dal megh700...@yahoo.com wrote:
Dear all, I have following kind of character vector:
Vec - c(344426, dwjjsgcj, 123sgdc, aagha123, sdh343asgh,
123jhd51)
Now I want to split each element of this vector according to numeric and
string element. For
On Jun 26, 2011, at 10:54 AM, Megh Dal wrote:
Dear all, I have following kind of character vector:
Vec - c(344426, dwjjsgcj, 123sgdc, aagha123, sdh343asgh,
123jhd51)
Now I want to split each element of this vector according to numeric
and string element. For example in the 1st element
On Sun, Jun 26, 2011 at 11:00 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Sun, Jun 26, 2011 at 10:54 AM, Megh Dal megh700...@yahoo.com wrote:
Dear all, I have following kind of character vector:
Vec - c(344426, dwjjsgcj, 123sgdc, aagha123, sdh343asgh,
123jhd51)
Now I want to
Dear [R] people
Could you please help with following
How to convert a vector
'ac','ac','c','ac','ac','c'
into a single string
'ac2_c_ac2_c'
Thank you in advance
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Try this:
x - c('ac','ac','c','ac','ac','c')
rle(x)
Run Length Encoding
lengths: int [1:4] 2 1 2 1
values : chr [1:4] ac c ac c
z - rle(x)
paste(z$values, ifelse(z$lengths == 1, '', z$lengths), collapse='_', sep = '')
[1] ac2_c_ac2_c
On Tue, Mar 8, 2011 at 6:33 PM, Denis Kazakiewicz
Dennis,
If I understand you correctly (your example does not point unambiguously
to one unique solution...)
you could try:
dummy- c('ac','ac','c','ac','ac','c')
dummy.rle-rle(dummy)
result - paste(dummy.rle$values,dummy.rle$lengths,collapse='_',sep='')
You may need to remove the '1' in
Grothendieck
Cc: r-help@r-project.org
Subject: Re: [R] String manipulation
Hi Gabor, thanks (and Jim as well) for your suggestion. However this is not
working properly for following string:
MyString - ABCFR34564IJVEOJC3434.36453
strapply(MyString, (\\D+)(\\d+)(\\D+)(\\d file://d+)(//d+)(//D+)(//d
Please consider following string:
MyString - ABCFR34564IJVEOJC3434
Here you see that, there are 4 groups in above string. 1st and 3rd groups
are for english letters and 2nd and 4th for numeric. Given a string, how can
I separate out those 4 groups?
Thanks for your time
[[alternative
On Sun, Feb 13, 2011 at 10:27 AM, Megh Dal megh700...@gmail.com wrote:
Please consider following string:
MyString - ABCFR34564IJVEOJC3434
Here you see that, there are 4 groups in above string. 1st and 3rd groups
are for english letters and 2nd and 4th for numeric. Given a string, how can
I
If you have an indeterminate number of the patterns in the string, try
the following:
MyString - ABCFR34564IJVEOJC3434
# translate to the pattern sequences
x - chartr('ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789'
+ , '0011'
+ , MyString
+
On Sun, Feb 13, 2011 at 4:42 PM, Megh Dal megh700...@gmail.com wrote:
Hi Gabor, thanks (and Jim as well) for your suggestion. However this is not
working properly for following string:
MyString - ABCFR34564IJVEOJC3434.36453
strapply(MyString, (\\D+)(\\d+)(\\D+)(\\d+), c)[[1]]
[1] ABCFR
Just add '.' to the pattern specifier:
MyString - ABCFR34564IJVEOJC3434.16ABC123.456KJHLKJH23452345AAA
# translate to the pattern sequences
x - chartr('ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789.'
+ , '00111'
+ , MyString
+ )
x.rle -
Hi Gabor, thanks (and Jim as well) for your suggestion. However this is not
working properly for following string:
MyString - ABCFR34564IJVEOJC3434.36453
strapply(MyString, (\\D+)(\\d+)(\\D+)(\\d file://d+)(//d+)(//D+)(//d+),
c)[[1]]
[1] ABCFR 34564 IJVEOJC 3434
Therefore there is decimal
Dear community,
I have a problem with a string conversion:
text
[1]and\xc1d\xe1m
[4] graphical interface MLP
[7] Nagy networks Networks
[10] neural Neural RBF
[13] sod...@yahoo.com user
See
?Encoding and ?iconv:
iconv(\xc1d\xe1m, from = '', to = 'latin1')
On Sat, May 8, 2010 at 11:05 AM, Webby mailing-l...@gmx.net wrote:
Dear community,
I have a problem with a string conversion:
text
[1]and\xc1d\xe1m
[4] graphical
On May 8, 2010, at 10:05 AM, Webby wrote:
Dear community,
I have a problem with a string conversion:
text
[1]and\xc1d\xe1m
[4] graphical interface MLP
[7] Nagy networks Networks
[10] neural Neural
I am currently attempting to split a long list of strings (let's call it
string.list) that is of the format:
1234567.z3.abcdef-gh.12
I have gotten it to:
1234567 z3 abcdef-gh 12
by use of the strsplit function.
This leaves me with each element of string.list having a split string of
the
Does this help:
x -
c(1234567.z3.abcdef-gh.12,1234567.z3.abcdef-gh.12,1234567.z3.abcdef-gh.12)
y - strsplit(x, '[.]')
y
[[1]]
[1] 1234567 z3abcdef-gh 12
[[2]]
[1] 1234567 z3abcdef-gh 12
[[3]]
[1] 1234567 z3abcdef-gh 12
y.1 - sapply(y, '[[', 1)
y.1
[1]
On Fri, Feb 5, 2010 at 9:29 AM, jim holtman jholt...@gmail.com wrote:
Does this help:
x -
c(1234567.z3.abcdef-gh.12,1234567.z3.abcdef-gh.12,1234567.z3.abcdef-gh.12)
y - strsplit(x, '[.]')
Here's another way with the stringr package:
library(stringr)
x -
Yes, that was perfect! Thank you so much!
Just to clarify, since I'm kind of new to string manipulation-- is that '[['
in the sapply function what is designating splits/elements within the
string? So that's the part that says I want this particular element and
the 1 or 2 or number is what
The '[[' is just the index access to an object. type:
?'[['
to see the help page.
Actually I should have used '[' in this case:
sapply(y, '[', 1)
[1] 1234567 1234567 1234567
is equivalent to:
sapply(y, function(a) a[1])
[1] 1234567 1234567 1234567
So set a value based on the first
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