Thank you to Ozgur, who gave me the hints for an easy solution.
There are the commands that work for my case:
mean(my_dataframe$Freq[my_dataframe$month == 5 my_dataframe$day %in% c(1:7)])
mean(my_dataframe$Freq[my_dataframe$month == 5 my_dataframe$day %in% c(8:14)])
...
Stefano Sofia PhD
Hello,
I'm glad you have a solution that works.
Maybe you could do the same without hard-coding the values 1:7, 8:14.
$
library(chron)
dat - with(my_dataframe, paste(month, day, year, sep=/))
week - cut(chron(dat), breaks=weeks)
head(week)
tapply(my_dataframe$Freq, week, mean)
Hope this
2 matches
Mail list logo
