It is a printing problem - the default number of digits in print.summary.aov
is max(3L, getOption(digits) - 3L). Set options(digits=7) instead of
your current 6 (?) or try print(summary(fit.Y), digits=7) to see more
digits.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, Apr 14, 2015 at
Li Li -
I belive it's a rounding error -- try setting
options(digits=8)
before displaying the output:
summary(fit.Y)
Df Sum Sq Mean Sq F value Pr(F)
sample.Y 3 2203 734 190706 2e-16 ***
Residuals8 0 0
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01
Hi all,
I have following data. When I perform an anova, the residual sum of
square returns to be zero.
But this is wrong, since we can hand calculate the RSS to be around 0.0308.
Did anyone come across the same problem before? Any suggestions?
Thanks.
Hanna
ydata
Y sample.Y
1
See in-line
On 14/04/2015 18:23, li li wrote:
Hi all,
I have following data. When I perform an anova, the residual sum of
square returns to be zero.
But this is wrong, since we can hand calculate the RSS to be around 0.0308.
Did anyone come across the same problem before? Any suggestions?
0.003725088 is the mean square error.
2015-04-14 13:44 GMT-04:00 Michael Dewey li...@dewey.myzen.co.uk:
See in-line
On 14/04/2015 18:23, li li wrote:
Hi all,
I have following data. When I perform an anova, the residual sum of
square returns to be zero.
But this is wrong, since we
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