Hello,
In addition to my question a few days ago,
Now I have a matrix of the coefficients,
how can I see all the P.Values (Pr(|z|)) of the covariates from the 1000
iterations?
I tried names(log_v) and couldn'n find it.
Thank you,
Sigalit.
On 11/13/07, Julian Burgos [EMAIL PROTECTED] wrote:
Excuse me, but I think your code deserves some comments. Unfortunately,
the history of postings is in reverse order, so I'll address your
first question first:
The simulation looks like this:
z - 0
x - 0
y - 0
aps - 0
tiss - 0
for (i in 1:500){
z[i] - rbinom(1, 1, .6)
summary(log_v)
Julian
sigalit mangut-leiba wrote:
Hello,
In addition to my question a few days ago,
Now I have a matrix of the coefficients,
how can I see all the P.Values (Pr(|z|)) of the covariates from the 1000
iterations?
I tried names(log_v) and couldn'n find it.
Thank you,
Sigalit.
Thank you for all your comments,
Sigalit.
On 11/15/07, Johannes Hüsing [EMAIL PROTECTED] wrote:
Excuse me, but I think your code deserves some comments. Unfortunately,
the history of postings is in reverse order, so I'll address your
first question first:
The simulation looks like this:
From: sigalit mangut-leiba [EMAIL PROTECTED]
Date: Nov 15, 2007 3:24 PM
Subject: Re: [R] a repetition of simulation
To: r-help [EMAIL PROTECTED]
Hello,
In addition to my question a few days ago,
Now I have a matrix of the coefficients,
how can I see all the P.Values ( Pr(|z|)) of the covariates
I want to repeat the simulation 600 times and to get a vector of 600
coefficients for every covariate: aps and tiss.
Sigalit.
On 11/13/07, Julian Burgos [EMAIL PROTECTED] wrote:
And what is your question?
Julian
sigalit mangut-leiba wrote:
Hello,
I have a simple (?) simulation problem.
Thank you, I changed that and it's much more efficient.
Sigalit.
On 11/13/07, Phil Spector [EMAIL PROTECTED] wrote:
You can use the replicate function to do your simulation. First,
put the code to do one repetition in a function:
dosim0 = function(n=500){
x - 0
y - 0
z - 0
aps
Well, the obvious (but perhaps not the most elegant) solution is put
everything in a loop and run it 600 times.
coefficients=matrix(NA,ncol=3,nrow=600)
for (loop in 1:600){
[all your code here]
coefficients[loop,]=coef(log_v)
}
That will give you a matrix with the coefficients of each model
Hello,
I have a simple (?) simulation problem.
I'm doing a simulation with logistic model and I want to reapet it 600
times.
The simulation looks like this:
z - 0
x - 0
y - 0
aps - 0
tiss - 0
for (i in 1:500){
z[i] - rbinom(1, 1, .6)
x[i] - rbinom(1, 1, .95)
y[i] - z[i]*x[i]
if (y[i]==1) aps[i] -
Dear Sigalit,
On Nov 12, 2007 2:18 PM, sigalit mangut-leiba [EMAIL PROTECTED] wrote:
Hello,
I have a simple (?) simulation problem.
I'm doing a simulation with logistic model and I want to reapet it 600
times.
The simulation looks like this:
z - 0
x - 0
y - 0
aps - 0
tiss - 0
for (i
Thank you,
Sigalit.
On 11/13/07, Moshe Olshansky [EMAIL PROTECTED] wrote:
Hi,
Look at names(log_v) in your notation to see what you
really need.
Then you could do something like:
results - list(600)
for (ij in 1:600) {
do what you did
results[[ij]] - log_v
}
So now you have a list
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