Dear useRs,
Here is my data with two columns and 20 rows.
dput(TT)
structure(c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
20, 24, 48, 72, 96, 120, 144, 168, 192, 216, 240, 264, 288, 312, 336, 360, 384,
408, 432, 456, 480), .Dim = c(20L, 2L), .Dimnames = list(NULL, c(,
Hello,
Try the following.
fun - function(x, r){
if(r 0){
m - length(x) %/% r
y - numeric(m)
for(i in seq_len(m)){
y[i] - sum(x[((i - 1)*r + 1):(i*r)])
}
y
}else{
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Rui Barradas
Sent: Thursday, September 25, 2014 3:34 PM
To: eliza botto; r-help@r-project.org
Subject: Re: [R] adding rows
Hello,
Try the following.
fun - function(x, r){
if(r
To: eliza botto; r-help@r-project.org
Subject: Re: [R] adding rows
Hello,
Try the following.
fun - function(x, r){
if(r 0){
m - length(x) %/% r
y - numeric(m)
for(i in seq_len(m)){
y[i] - sum(x[((i - 1)*r + 1
Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Rui Barradas
Sent: Thursday, September 25, 2014 3:34 PM
To: eliza botto; r-help@r-project.org
Subject: Re: [R] adding rows
Hello,
Try the following.
fun - function(x, r){
if(r 0
HI,
If you want to try other ways:
fun1 - function(mat, rowN) {
dm - dim(mat)[1]
rowN1 - rowN - 1
indx - rep(1:rowN, dm - rowN1) + rep(seq(0, dm - rowN), each = rowN)
indx1 - (seq_along(indx)-1)%/%rowN+1
as.vector(tapply(indx, list(indx1), FUN = function(i) sum(mat[i, ])))
}
Thankyou very much arun. Its always nice to hear from you.
Eliza
Date: Sat, 10 May 2014 03:55:29 -0700
From: smartpink...@yahoo.com
Subject: Re: [R] adding rows
To: r-help@r-project.org
CC: ruipbarra...@sapo.pt; eliza_bo...@hotmail.com
HI,
If you want to try other ways:
fun1
Dear useRs,
I have a matrix, say el of 30 rows and 10 columns, as
el-matrix(sample(1:300),ncol=10)
I want to sum up various sets of three rows of each column in the following
manner
sum(el[c(1,2,3),]) ##adding row number 1, 2 and 3 of each column
sum(el[c(2,3,4),])##adding row number 2, 3 and 4
Hello,
Try the following.
sapply(1:(30 - 2), function(i) sum(el[i:(i+2), ]))
but with number of rows instead of 30.
Hope this helps,
Rui Barradas
Em 09-05-2014 22:35, eliza botto escreveu:
Dear useRs,
I have a matrix, say el of 30 rows and 10 columns, as
el-matrix(sample(1:300),ncol=10)
I
Dear Rui and Murphy,
Thanks for your help.
Eliza
Date: Fri, 9 May 2014 22:55:27 +0100
From: ruipbarra...@sapo.pt
To: eliza_bo...@hotmail.com; r-help@r-project.org
Subject: Re: [R] adding rows
Hello,
Try the following.
sapply(1:(30 - 2), function(i) sum(el[i:(i+2
Amin
Sent: Donnerstag, 23. Mai 2013 07:01
To: r-help@r-project.org
Subject: [R] adding rows without loops
I'm comparing a variety of datasets with over 4M rows. I've solved this
problem 5 different ways using a for/while loop but the processing time
is murder (over 8 hours doing this row by row
to compute.
Even the bigmemory package is causing OOM issues.
-Original Message-
From: Blaser Nello [mailto:nbla...@ispm.unibe.ch]
Sent: Thursday, May 23, 2013 12:15 AM
To: Adeel Amin; r-help@r-project.org
Subject: RE: [R] adding rows without loops
Merge should do the trick. How to best use
Hi Rainer:
Thanks for the reply. Posting the large dataset is a task. There are 8M
rows between the two of them and the first discrepancy in the data doesn't
happen until at least the 40,000th row on each dataframe. The examples I
posted are a pretty good abstraction of the root of the issue.
issues.
-Original Message-
From: Blaser Nello [mailto:nbla...@ispm.unibe.ch]
Sent: Thursday, May 23, 2013 12:15 AM
To: Adeel Amin; r-help@r-project.org
Subject: RE: [R] adding rows without loops
Merge should do the trick. How to best use it will depend on what you
want to do
, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Of Adeel - SafeGreenCapital
Sent: Thursday, May 23, 2013 5:54 AM
To: 'Blaser Nello'; r-help@r-project.org
Subject: Re: [R] adding rows without
, 2013 12:15 AM
To: Adeel Amin; r-help@r-project.org
Subject: RE: [R] adding rows without loops
Merge should do the trick. How to best use it will depend on what you
want to do with the data after.
The following is an example of what you could do. This will perform
best, if the rows
I'm comparing a variety of datasets with over 4M rows. I've solved this
problem 5 different ways using a for/while loop but the processing time is
murder (over 8 hours doing this row by row per data set). As such I'm
trying to find whether this solution is possible without a loop or one in
which
Thanks for the response, and the advice, glmulti looks like it could be quite
a good alternative.
As for the adding to the results table problem from within the loop, this
webpage:
http://ryouready.wordpress.com/2009/01/23/r-combining-vectors-or-data-frames-of-unequal-length-into-one-data-frame/
Hi All,
Its a bit of a beginners question I'm afraid.
I have a looped stepwise regression (using MASS and StepAIC) to take random
predictors out of the total number. For this example a random sample of 5
out of a total of 20. The loop will continue until all combinations of
variables have been
It surely can be done. One way is to keep track of selected variables
in a set. If a new variable is selected, you expand the selected set
and set the frequency to be one, otherwise just increase the freqency
of the selected variable (if... else).
Also, you might want to have a look at glmulti
Dear all,
I have one problem and did not find any solution.
I have attached the question in text file also because sometimes spacing is not
good in mail.
I have a file(file.txt) attached with this mail.I am reading it using this code
to make a data frame (file)-
Hi:
This seems to work:
library(plyr)
# select the variables to summarize:
vars - paste('Case', c('A', 'C', 'G', 'T'), sep = '')
# Alternatively,
# vars - names(df)[grep('Case', names(df))]
# One way: the ddply() function in package plyr in
# conjunction with the colwise() function
ddply(df,
From: Dennis Murphy [djmu...@gmail.com]
Sent: Friday, July 15, 2011 7:38 PM
To: Bansal, Vikas
Cc: r-help@r-project.org
Subject: Re: [R] Adding rows based on column value
Hi:
This seems to work:
library(plyr)
# select the variables to summarize:
vars - paste('Case', c('A', 'C', 'G
[djmu...@gmail.com]
Sent: Friday, July 15, 2011 7:38 PM
To: Bansal, Vikas
Cc: r-help@r-project.org
Subject: Re: [R] Adding rows based on column value
Hi:
This seems to work:
library(plyr)
# select the variables to summarize:
vars - paste('Case', c('A', 'C', 'G', 'T'), sep = '')
# Alternatively
Dear all,
I have one problem and did not find any solution.(I have also attached the
problem in text file because sometimes column spacing is not good in mail)
I have a file(file.txt) attached with this mail.I am reading it using this code
to make a data frame (file)-
?tapply (in base R)
?aggregate ?by (wrapper for tapply)
?ave (in base R -- based on tapply)
Also package plyr (and several others, undoubtedly).
Also google on R summarize data by groups or similar gets many relevant hits.
-- Bert
2011/7/14 Bansal, Vikas vikas.ban...@kcl.ac.uk:
Dear all,
, 2011 4:54 PM
To: Bansal, Vikas
Cc: r-help@r-project.org
Subject: Re: [R] Adding rows based on column value
?tapply (in base R)
?aggregate ?by (wrapper for tapply)
?ave (in base R -- based on tapply)
Also package plyr (and several others, undoubtedly).
Also google on R summarize data by groups
Thanking you,
Warm Regards
Vikas Bansal
Msc Bioinformatics
Kings College London
From: Bansal, Vikas
Sent: Thursday, July 14, 2011 6:07 PM
To: Bert Gunter
Subject: RE: [R] Adding rows based on column value
Yes sir.I am trying.
I am using this-
aggregate
Bansal, Vikas vikas.bansal at kcl.ac.uk writes:
I am using this-
aggregate(x = file[,3:6], by = list(file[,2]), FUN = sum)
Better, although still not reproducible (please *do* read the posting
guide -- it is listed at the bottom of every R list post and is the
*first* google hit for
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
Ben Bolker [bbol...@gmail.com]
Sent: Thursday, July 14, 2011 6:24 PM
To: r-h...@stat.math.ethz.ch
Subject: Re: [R] Adding rows based on column value
Bansal, Vikas vikas.bansal at kcl.ac.uk writes:
I am using
To: r-h...@stat.math.ethz.ch
Subject: Re: [R] Adding rows based on column value
Bansal, Vikas vikas.bansal at kcl.ac.uk writes:
I am using this-
aggregate(x = file[,3:6], by = list(file[,2]), FUN = sum)
Better, although still not reproducible (please *do* read the posting
guide
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf
Of Ben Bolker [bbol...@gmail.com]
Sent: Thursday, July 14, 2011 6:24 PM
To: r-h...@stat.math.ethz.ch
Subject: Re: [R] Adding rows based on column value
Bansal, Vikas vikas.bansal
I'm new to R.
I'm extracting important columns from single table using following code:
File2-file.txt
table2- read.delim(File2, skip=19, sep=;, header=F, na.strings=NA,
fill=T)
#extracting column 7 where rows match ID
col1- table2[grep(ID, table2[,1]),7]
#similarly extracting column 9,11,13,15
Hi!
Would
df- table2[grep(ID,table2[,1]), c(7,9,11,13,15)]
do what you expect?
Ivan
Le 10/21/2010 15:42, amb1networks a écrit :
I'm new to R.
I'm extracting important columns from single table using following code:
File2-file.txt
table2- read.delim(File2, skip=19, sep=;, header=F,
sorry i got clik happy
df2-df1[, c(3,5,7,9,11,13,15)]
df2-df2[grep('ID', df2$Group), ]
--
View this message in context:
http://r.789695.n4.nabble.com/Adding-rows-to-column-tp3005607p3006302.html
Sent from the R help mailing list archive at Nabble.com.
If I understand correctly you want to create a new dataframe with selected
columns which can be achieved this was as well, it will right away create a
new dataframe with column headers
df2-df1[ ,c(3,7,9,11,13,15)]
--
View this message in context:
Dear R users,
Suppose I have the following data.frame:
myID myType myNum1 myNum2 myNum3
a Single 10 11 12
b Single 15 25 35
c Double 22 33 44
d Double4 6 8
and I want
This should get you close:
x - read.table(textConnection(myID myType myNum1 myNum2 myNum3
+ a Single 10 11 12
+ b Single 15 25 35
+ c Double 22 33 44
+ d Double4 6 8),
Thanks much Jim.
On Fri, Dec 5, 2008 at 2:05 PM, jim holtman [EMAIL PROTECTED] wrote:
This should get you close:
x - read.table(textConnection(myID myType myNum1 myNum2 myNum3
+ a Single 10 11 12
+ b Single 15 25 35
+ c
Here is a solution using sqldf
library(sqldf)
DF2 -
structure(list(myID = structure(1:4, .Label = c(a, b, c,
d), class = factor), myType = structure(c(2L, 2L, 1L, 1L), .Label
= c(Double,
Single), class = factor), myNum1 = c(10, 15, 22, 4), myNum2 = c(11,
25, 33, 6), myNum3 = c(12, 35, 44, 8)),
[EMAIL PROTECTED]
Cc: r-help@r-project.org
Date: Fri, 5 Dec 2008 17:50:42 -0500
Subject: Re: [R] adding rows as arithmatic calculation on original rows
Here is a solution using sqldf
library(sqldf)
DF2 -
structure(list(myID = structure(1:4, .Label = c(a, b, c,
d), class = factor), myType = structure
)
- Original message -
From: Gabor Grothendieck [EMAIL PROTECTED]
To: Ferry [EMAIL PROTECTED]
Cc: r-help@r-project.org
Date: Fri, 5 Dec 2008 17:50:42 -0500
Subject: Re: [R] adding rows as arithmatic calculation on original rows
Here is a solution using sqldf
library(sqldf
Greetings everyone,
I'm trying to add a specific table or a specific number of rows (e.g.44) to a
table with no success.
This is my basic table
head(dataA)
yearplot spp prop.BDCA1DCA2DCA3DCA4
1 20001 a1 0.031079 -0.0776 -0.0009 0.0259 -0.0457
2 2000
Greetings everyone,
I'm trying to add a specific table or a specific number of rows (e.g.44) to a
table with no success.
This is my basic table
head(dataA)
yearplot spp prop.BDCA1DCA2DCA3DCA4
1 20001a1 0.031079 -0.0776 -0.0009 0.0259 -0.0457
2
44 matches
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