Just for fun
This small program gives negative Sum of Sq in anova (with R versions
2.9.2 and 2.10.0) (linux 32 kernel 2.6.29.6-smp slackware 13.0) :
y = c(3.6, 5.0, 5.0, 4.6, 4.5, 4.3, 4.5, 5.1, 4.5, 4.3)
trans = as.factor(c(NT,NT,NT,NT,NT,T,T,T,T,T))
lc = lm(y ~ trans)
l1 = lm(y ~ 1)
It might be a good idea not to use an outdated version of R.
I don't see your problem in R 2.12.0.
Peter Ehlers
On 2010-12-01 05:44, jean.cour...@math.u-psud.fr wrote:
Just for fun
This small program gives negative Sum of Sq in anova (with R versions
2.9.2 and 2.10.0) (linux 32 kernel
On Dec 1, 2010, at 9:18 AM, Peter Ehlers wrote:
It might be a good idea not to use an outdated version of R.
I don't see your problem in R 2.12.0.
Furthermore isn't it a bit something to be asking why the sign on a
number that is effectively zero happens to be negative? I would think
On Wed, Dec 1, 2010 at 9:02 AM, Ben Bolker bbol...@gmail.com wrote:
Peter Ehlers ehlers at ucalgary.ca writes:
It might be a good idea not to use an outdated version of R.
I don't see your problem in R 2.12.0.
Peter Ehlers
On 2010-12-01 05:44, Jean.Coursol at math.u-psud.fr wrote:
Hello,
I have a dataframe named myMatrix with the structure
TreatmentTimeCrmIb ...
Being the treatment and time the predictors and Cr, mIb and so on the
response variables. When I call
Cr.aov - aov(Cr~Treatment, data=myMatrix)
I got this error:
Error in storage.mode(y) - double
Dani
I have a dataframe named myMatrix with the structure
If it really is a dataframe, why is it called myMatrix :-) I guess you
actually have a factor matrix. From the message below, Cr would appear to be a
factor.
There are some fundamental distinctions in R (such as between a matrix and
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