You loaded "lubridate" so using Erin's approach
library(lubridate)
st <- c("1961-01","1961-04","1983-02")
dat1 <- ymd(paste( st, "01", sep ="-"))
On Monday, August 20, 2018, 1:15:56 a.m. EDT,
wrote:
Thanks Erin and Jim. You have indeed solved my problem.
Philip
Quoting Erin
Nice one!
On Tue, Aug 21, 2018 at 6:14 PM John Kane wrote:
> You loaded "lubridate" so using Erin's approach
>
> library(lubridate)
> st <- c("1961-01","1961-04","1983-02")
> dat1 <- ymd(paste( st, "01", sep ="-"))
>
>
> On Monday, August 20, 2018, 1:15:56 a.m. EDT, <
>
Thanks Erin and Jim. You have indeed solved my problem.
Philip
Quoting Erin Hodgess :
Hi Philip:
Here is something to consider:
#potential solution:
sta <- paste(st,"-01",sep="")
st1 <- as.Date(sta, format=("%Y-%m-%d"))
print(st1)
[1] "1961-01-01" "1961-04-01" "1983-02-01"
Hope this
Hi Phillip,
Jose has the correct answer. You probably missed this sentence in the
"Note" section of the help page:
"If the date string does not specify the date completely, the returned
answer may be system-specific."
In your case, the function throws up its hands and returns NA as you
haven't
On Sun, Aug 19, 2018 at 05:20:29PM -0400, phili...@cpanel1.stormweb.net wrote:
> Why the heck am I getting three NAs instead of three Dates?I have
> studied the R documentation for as.Date() and it has not turned on
> the light bulb for me.
I haven't encountered this problem before, but in my
Hi Philip:
Here is something to consider:
> #potential solution:
> sta <- paste(st,"-01",sep="")
> st1 <- as.Date(sta, format=("%Y-%m-%d"))
> print(st1)
[1] "1961-01-01" "1961-04-01" "1983-02-01"
Hope this helps!
Erin
Erin Hodgess, PhD
mailto: erinm.hodg...@gmail.com
On Sun, Aug 19, 2018 at
I am having trouble with what must be a very simple problem. Here is a
reproducible example:
library(lubridate)
st <- c("1961-01","1961-04","1983-02")
print(st)
#[1] "1961-01" "1961-04" "1983-02"
st1 <- as.Date(st, format=("%Y-%m"))
print(st1)
#[1] NA NA NA
Why the heck am I getting three NAs
Hi,
I have some problems with as.Date function.
After I applied as.Date for my data, 2010 changed to 2020 as below
Where am I wrong?
Thanks
Wonjae
x=c(11/16/2010,11/17/2010,11/18/2010,11/19/2010)
x=as.Date(x,%m/%d/%y)
x
[1] 2020-11-16 2020-11-17 2020-11-18 2020-11-19
my R veision is
as.Date(x,%m/%d/%Y)
[1] 2010-11-16 2010-11-17 2010-11-18 2010-11-19
Notice the Y (four digit date).
Dennis
On Sun, Apr 17, 2011 at 6:34 AM, Wonjae Lee wjlee2...@naver.com wrote:
Hi,
I have some problems with as.Date function.
After I applied as.Date for my data, 2010 changed to 2020 as
On Sun, 17 Apr 2011, Wonjae Lee wrote:
Hi,
I have some problems with as.Date function.
After I applied as.Date for my data, 2010 changed to 2020 as below
Where am I wrong?
You used %y (two-digit year, here: 20 and then expanded to 2020)
instead of %Y (four-digit year, here 2010).
Using
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