[R] builtin to filter a list?

I know it's easy to write a simple loop to do this, but in the spirit of lapply, I thought I would ask if there is a builtin to filter or take a subset of a list based on a predicate in a similar way to the Erlang lists:filter/2 function: http://www.erlang.org/doc/man/lists.html#filter-2

Re: [R] builtin to filter a list?

Try: ?Filter e.g. Filter(function(x) x 0, x1) or using gsubfn's fn library(gsubfn) fn$Filter(~ x 0, x1) On Wed, Oct 29, 2008 at 9:06 AM, Whit Armstrong [EMAIL PROTECTED] wrote: I know it's easy to write a simple loop to do this, but in the spirit of lapply, I thought I would ask if

Re: [R] builtin to filter a list?

?Filter ... how did I miss that one? Thanks, Gabor. -Whit On Wed, Oct 29, 2008 at 9:37 AM, Gabor Grothendieck [EMAIL PROTECTED] wrote: Try: ?Filter e.g. Filter(function(x) x 0, x1) or using gsubfn's fn library(gsubfn) fn$Filter(~ x 0, x1) On Wed, Oct 29, 2008 at 9:06 AM,