hi, i'm trying to prepend some plain (i.e. unevalutated) text to a
typographically evaluated R expression in a legend(...) call.
here's a working legend(...) call that is close to what i'd like
(where x and y are returned from an lm(...) call):
legend(topleft, legend = c(bquote(R^2 ==
On Jul 10, 2010, at 8:58 PM, Murat Tasan wrote:
hi, i'm trying to prepend some plain (i.e. unevalutated) text to a
typographically evaluated R expression in a legend(...) call.
here's a working legend(...) call that is close to what i'd like
(where x and y are returned from an lm(...) call):
On Jul 10, 2010, at 10:45 PM, David Winsemius wrote:
On Jul 10, 2010, at 8:58 PM, Murat Tasan wrote:
hi, i'm trying to prepend some plain (i.e. unevalutated) text to a
typographically evaluated R expression in a legend(...) call.
here's a working legend(...) call that is close to what i'd
ok, here's a self-contained example.
topleft legend will plot 1 example of exactly what i want, but only 1
line.
bottomleft legend will plot what i had hoped would work... as it's the
logical extension of the topleft example to two cases.
dev.new()
plot.new()
plot.window(xlim = c(0, 1), ylim =
On Jul 10, 2010, at 11:22 PM, David Winsemius wrote:
On Jul 10, 2010, at 10:45 PM, David Winsemius wrote:
On Jul 10, 2010, at 8:58 PM, Murat Tasan wrote:
hi, i'm trying to prepend some plain (i.e. unevalutated) text to a
typographically evaluated R expression in a legend(...) call.
well, figured it out, apparently placing the bquote results in a
vector doesn't result in a vector of expressions, so you have to
coerce it like so:
dev.new()
plot.new()
plot.window(xlim = c(0, 1), ylim = c(0, 1))
legend(topleft, legend = bquote(paste(foo bar , R^2 == .(2^2))),
fill = red)
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