Dear list,
subset has a 'drop' argument that I had often mistaken for the one in
[.factor which removes unused levels.
Clearly it doesn't work that way, as shown below,
d - data.frame(x = factor(letters[1:15]), y = factor(LETTERS[1:3]))
s - subset(d, y==A, drop=TRUE)
str(s)
'data.frame': 5
On Nov 10, 2009, at 10:49 AM, baptiste auguie wrote:
Dear list,
subset has a 'drop' argument that I had often mistaken for the one in
[.factor which removes unused levels.
Clearly it doesn't work that way, as shown below,
d - data.frame(x = factor(letters[1:15]), y = factor(LETTERS[1:3]))
s
On Nov 10, 2009, at 9:49 AM, baptiste auguie wrote:
Dear list,
subset has a 'drop' argument that I had often mistaken for the one in
[.factor which removes unused levels.
Clearly it doesn't work that way, as shown below,
d - data.frame(x = factor(letters[1:15]), y = factor(LETTERS[1:3]))
s -
Neat, I reinvented the wheel! Would that seem like a useful example at
the end of the help page for ?subset ? (it currently has very little
to say about drop).
Thanks also to David for the alternative idea.
Best regards,
baptiste
2009/11/10 Marc Schwartz marc_schwa...@me.com:
On Nov 10,
If you don't want to preserve factor levels when subsetting use
characters. There are very few other differences in behavior.
Hadley
On Tuesday, November 10, 2009, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Dear list,
subset has a 'drop' argument that I had often mistaken for the
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