Good Bless you Duncan. Your explanation is crisp and to the point. Thank you.
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Good Bless you Duncan. Your explanation is crisp and to the point. Thank you.
--
View this message in context:
http://r.789695.n4.nabble.com/efficient-use-of-lm-over-a-matrix-vs-using-apply-over-rows-tp870810p3742043.html
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In that case, using the example data from the prior response all you need
is:
coef(lm(t(mat) ~ x))
On Sun, Oct 5, 2008 at 1:18 PM, Mark Kimpel <[EMAIL PROTECTED]> wrote:
> Sorry for the vagueness of my question, your interpretation, however, was
> spot on. Correct me if I am wrong, but my impres
Sorry, I missed the fact that Duncan had this solution as well at
the end of his response.
On Sun, Oct 5, 2008 at 1:31 PM, Gabor Grothendieck
<[EMAIL PROTECTED]> wrote:
> In that case, using the example data from the prior response all you need
> is:
>
> coef(lm(t(mat) ~ x))
>
>
> On Sun, Oct 5, 2
Sorry for the vagueness of my question, your interpretation, however, was
spot on. Correct me if I am wrong, but my impression is that apply is a more
compact way of a for loop, but that the way R handles them computationally
are the same. In the article I seem to remember, there was a significant
On 05/10/2008 10:08 AM, Mark Kimpel wrote:
I have a large matrix, each row of which needs lm applied. I am certain than
I read an article in R-news about this within the last year or two that
discussed the application of lm to matrices but I'll be darned if I can find
it with Google. Probably usi
I have a large matrix, each row of which needs lm applied. I am certain than
I read an article in R-news about this within the last year or two that
discussed the application of lm to matrices but I'll be darned if I can find
it with Google. Probably using the wrong search terms.
Can someone steer
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