CTED]
> To: [EMAIL PROTECTED]
> CC: r-help@r-project.org
> Subject: Re: [R] elegant way to minus on each row of a matrix
>
> try this:
>
> mat <- matrix(1:9, 3, 3, TRUE)
> dat <- as.data.frame(mat)
> vec <- 1:3
>
> result.mat <- mat - vec
> re
10
[4,]05 10
[5,]05 10
> Date: Sun, 2 Mar 2008 14:56:22 -0300
> From: [EMAIL PROTECTED]
> To: [EMAIL PROTECTED]
> Subject: Re: [R] elegant way to minus on each row of a matrix
> CC: r-help@r-project.org
>
> Try this:
>
> sweep(mat, 1, vec)
>
t2
[1] 1 2 3 4 5
> apply(t1,2, function(x) x - t2)
[,1] [,2] [,3]
[1,]05 10
[2,]05 10
[3,]05 10
[4,]05 10
[5,]05 10
>
> Date: Sun, 2 Mar 2008 12:51:53 -0500
> From: [EMAIL PROTECTED]
> Subject: RE: [R] elegant way to mi
try this:
mat <- matrix(1:9, 3, 3, TRUE)
dat <- as.data.frame(mat)
vec <- 1:3
result.mat <- mat - vec
result.dat <- dat - vec
result.mat
result.dat
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Ka
Try this:
sweep(mat, 1, vec)
On 02/03/2008, Bo Zhou <[EMAIL PROTECTED]> wrote:
>
> How to do this in an elegant way formatrix/data frame/zoo?
>
> mat=
> 1 2 3
> 4 5 6
> 7 8 9
>
> vector=
> 1
> 2
> 3
>
>
> result=
> 0 1 2
> 2 3 4
> 4 5 6
>
> ie
> 1-1 2-1 3-1
> 4-2 5-2 6-2
> 7-3 8-3 9-3
>
>
How to do this in an elegant way formatrix/data frame/zoo?
mat=
1 2 3
4 5 6
7 8 9
vector=
1
2
3
result=
0 1 2
2 3 4
4 5 6
ie
1-1 2-1 3-1
4-2 5-2 6-2
7-3 8-3 9-3
Thanks in advance.
_
08
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