jholtman wrote:
>
> Working code would help. I would probably use 'lapply' since it
> appears that you want to return a variable number of items for each
> condition.
>
> On Tue, Jul 8, 2008 at 2:23 PM, hesicaia <[EMAIL PROTECTED]> wrote:
>>
>> Hello,
>> The quick version of my question is h
Working code would help. I would probably use 'lapply' since it
appears that you want to return a variable number of items for each
condition.
On Tue, Jul 8, 2008 at 2:23 PM, hesicaia <[EMAIL PROTECTED]> wrote:
>
> Hello,
> The quick version of my question is how can I extract a matrix instead o
On Tue, 8 Jul 2008, hesicaia wrote:
Hello,
The quick version of my question is how can I extract a matrix instead of
a vector using tapply()? I would like to be able to access both the results
of tapply() and also the index variables.
In case further explanation would help: I am analyzing a
Hi,
How about using "subset"?
x1<-tapply(subset(years, length(area)>20), function(x) length(unique(x)))
I hope this works
Chunhao
Quoting hesicaia <[EMAIL PROTECTED]>:
Hello,
The quick version of my question is how can I extract a matrix instead of
a vector using tapply()? I would like to
Hello,
The quick version of my question is how can I extract a matrix instead of
a vector using tapply()? I would like to be able to access both the results
of tapply() and also the index variables.
In case further explanation would help: I am analyzing a large (3million
rows x 9 columns) spa
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