Hi,
The usual way is
I <- rep(c(0, v), each=10)
Best,
Ista
On Sat, Feb 23, 2013 at 10:56 PM, Jannetta Steyn wrote:
> Hi All
>
> I'm just wondering if there is a quick way of filling a way with the
> following.
>
> I want to declare array I with a specific length and then alternatively
> fill
Hi Josh and Jim
Thanks for your help. With what you have given me I came up with
v<-14
I<-c(rep(c(rep(0,10),rep(v,10)),10))
Which should give me more or less what I want.
Many thanks
Jannetta
On 24 February 2013 04:13, Joshua Wiley wrote:
> Hi Jannetta,
>
> Try this:
>
> rep(c(0, v), each =
Hi Jannetta,
Try this:
rep(c(0, v), each = 10)
See ?rep for details
Cheers,
Josh
On Sat, Feb 23, 2013 at 7:56 PM, Jannetta Steyn wrote:
> Hi All
>
> I'm just wondering if there is a quick way of filling a way with the
> following.
>
> I want to declare array I with a specific length and th
On 02/24/2013 02:56 PM, Jannetta Steyn wrote:
Hi All
I'm just wondering if there is a quick way of filling a way with the
following.
I want to declare array I with a specific length and then alternatively
fill it with 10 zeros and 10 specified values:
v<- 14
I<- c(0,length(t))
But in stead o
Hi All
I'm just wondering if there is a quick way of filling a way with the
following.
I want to declare array I with a specific length and then alternatively
fill it with 10 zeros and 10 specified values:
v<- 14
I <- c(0,length(t))
But in stead of just filling I with 0 I want 10 zeros and the
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