Luc, Eik, Jorge,
thanks to all of you!
Nice to see how many different solutions there are for the same
problem. :)
Best
Henning
Am 07.04.2009 um 22:25 schrieb Jorge Ivan Velez:
>
> Dear Hans,
>
> Try also:
>
> x <- structure(c(2, 1, 2, 1, 3, 2, 4, 1, 4, 3, 4, 3, 5, 2, 5, 1, 6,
> 1), .Dim
Dear Hans,
Try also:
x <- structure(c(2, 1, 2, 1, 3, 2, 4, 1, 4, 3, 4, 3, 5, 2, 5, 1, 6, 1), .Dim
= c(2L, 9L))
tapply(x[2,],x[1,],sum)
#2 3 4 5 6
#2 2 7 3 1
HTH,
Jorge
On Tue, Apr 7, 2009 at 11:06 AM, Hans-Henning Gabriel <
hanshenning.gabr...@gmail.com> wrote:
> Hi,
>
> my problem is as foll
briel"
Cc: r-help@r-project.org
Date: Tue, 07 Apr 2009 17:36:45 +0200
Subject: Re: [R] group by-like statement for 2-row matrix
see ?aggregate
m<-rbind(sample(2:6,9,replace=T),sample(1:3,9,replace=T))
aggregate(m[2,],by=list(m[1,]),sum)
Hans-Henning Gabriel schrieb:
> Hi,
>
> my probl
see ?aggregate
m<-rbind(sample(2:6,9,replace=T),sample(1:3,9,replace=T))
aggregate(m[2,],by=list(m[1,]),sum)
Hans-Henning Gabriel schrieb:
Hi,
my problem is as follows:
I have a matrix of two rows like this:
2 2 3 4 4 4 5 5 6
1 1 2 1 3 3 2 1 1
Can I apply something like "group by" in sql? W
Hi Henning,
Although there might be a better way to do this, I'd suggest (with
my.matrix being the matrix you provided):
complete.vector = rep(my.matrix[1,],my.matrix[2,]) ;
table(complete.vector) ;
Is this what you're looking for?
Cheers,
Luc
Hans-Henning Gabriel wrote:
Hi,
my problem i
Hi,
my problem is as follows:
I have a matrix of two rows like this:
2 2 3 4 4 4 5 5 6
1 1 2 1 3 3 2 1 1
Can I apply something like "group by" in sql? What I want to achieve
is the some of second row for each unique entry of first row:
2 -> 2 (=1+1)
3 -> 2
4 -> 7 (=1+3+3)
5 -> 3 (=2+1)
6 -
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