Hi all,
I have a list of vector of numbers - the reason I used list of vector was
that I each list have different numbers of numbers which I don't know
before run-time.
mylist[[1]] = c(1, 2, 3)
mylist[[2]] = c (3, 4, 5, 6)
...
...
etc.
Could you please tell me if there is a way to dump all
Hi Michael,
Part of me imagines this is overkill, but this should be one option:
## your data
mylist - list(1:3, 3:6)
## open a writeable connection to a file
con - file(test.csv, w)
## first collapse each element of the list to be a comma separated
string, then write each
## element of new
Hi,
If you don't mind having NAs for missing values, try the following,
mylist = list(1:3, 4:7)
library(plyr)
write.csv(do.call(rbind.fill.matrix, lapply(mylist, matrix, nrow=1)), file=)
HTH,
b.
On 6 February 2012 15:01, Michael comtech@gmail.com wrote:
Hi all,
I have a list of vector
michael,
what is the problem you are trying to solve? are you writing it out so you can
read it back in? if so, look at 'save/load' or 'dump/source'. is this the
format required by some other program?
Sent from my iPad
On Feb 5, 2012, at 21:54, baptiste auguie
cat will wrap Josh's overkill approach in one line:
mylist- list(1:3,3:9)
lapply(mylist , cat , sep=',' , fill=T , append=T , file='foo.csv')
Cheers
On Sun, Feb 5, 2012 at 7:42 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
Hi Michael,
Part of me imagines this is overkill, but this should be
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