I would like to cumulatively sum rows in a matrix, in which each row has 1
NA value. The usual na.rm=TRUE does not seem to work with the command
cumsum. Is there another way to ignore the NAs or do I need to figure out a
different way to do this?
Here's an example matrix of title proportion:
Hi Tracy,
What do you want the program to do with the missing values? If you
want to treat them as zeros, you could use
cum.na - function(x) {
x[which(is.na(x))] - 0
return(cumsum(x))
}
cumsums - apply(proportion, 1, cum.na)
-Ista
On Sat, Nov 21, 2009 at 2:34 PM, Tracy Bowerman
I would like to cumulatively sum rows in a matrix, in which each row has 1
NA value, which I do NOT want to treat as 0s. The NAs are placeholders
where there is actually no data, which is not the same as a 0. The usual
na.rm=TRUE does not seem to work with the command cumsum. Is there
another
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Tracy Bowerman
Sent: Saturday, November 21, 2009 12:19 PM
To: r-help
Subject: [R] how to ignore NA when using cumsum WHILE retaining NAs?
I would like to cumulatively sum rows
Try this:
apply(proportion, 1, function(x)cumsum(na.exclude(x)))
On Sat, Nov 21, 2009 at 5:34 PM, Tracy Bowerman
tracy.bower...@aggiemail.usu.edu wrote:
I would like to cumulatively sum rows in a matrix, in which each row has 1
NA value. The usual na.rm=TRUE does not seem to work with the
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