Carlos Nasher via R-help r-project.org> writes:
>
[snip]
> I need to evaluate the Hypergeometric Function of the 2nd kind (Tricomi
> confluent hypergeometric function). Therefore I'm using the kummerU
> function from the fAsianOptions package. It seems to me that kummerU is
> giving wrong resul
Hello R helpers,
I need to evaluate the Hypergeometric Function of the 2nd kind (Tricomi
confluent hypergeometric function). Therefore I'm using the kummerU
function from the fAsianOptions package. It seems to me that kummerU is
giving wrong results. Here's an example:
library("fAsianOptions")
ku
r=0,upper=.51,H=0.7)
Error in integrate(Gauss2F1, lower = 0, upper = 0.51, H = 0.7) :
non-finite function value
>
jlu...@ria.buffalo.edu
Sent by: r-help-boun...@r-project.org
06/17/2014 10:24 AM
To
Xuse Chuse ,
cc
r-help , r-help-boun...@r-project.org
Subject
Re: [R] hypergeomet
1.028055 1.019653
1.013143 1.007920 1.003618
[11] 1.00
#whereupon you find your second problem.
#Joe
Xuse Chuse
Sent by: r-help-boun...@r-project.org
06/17/2014 08:32 AM
To
r-help ,
cc
Subject
[R] hypergeometric integral
Dear all,
I am trying to make a numerical integral of a Hyp
Dear all,
I am trying to make a numerical integral of a Hypergeometrical function 2F1
but it is not working. I dont know how to pass the arguments to my
function. Thank you beforehand.
Chuse.
Here is my code:
H <- 0.7;
t <- 1;
s <- seq(0,t,0.1);
x <- 1-t/s;
library(gsl)
Gauss2F1 <- function(H,
On 19-03-2012, at 16:54, statfan wrote:
> Thanks for your advice. I actually meant to ask about the "pmvt" for the
> distribution function. Viewing the source code "pmvt" uses the function
> "mvt" which uses the function "probval" which sources the fortran code:
>
No it doesn't "source". It
Thanks for your advice. I actually meant to ask about the "pmvt" for the
distribution function. Viewing the source code "pmvt" uses the function
"mvt" which uses the function "probval" which sources the fortran code:
Fortran("mvtdst", N = as.integer(n), NU = as.integer(df),
LOWER = as.d
To view the source of (most) functions, simply type funcname without
parentheses: here, you get
> dmvt
function (x, delta, sigma, df = 1, log = TRUE, type = "shifted")
{
if (df == 0)
return(dmvnorm(x, mean = delta, sigma = sigma, log = log))
if (is.vector(x)) {
x <- matrix
Is there any way to know how the "dmvt" function computes the hypergeometric
function needed in the calculation for the density of multivariate t
distribution?
--
View this message in context:
http://r.789695.n4.nabble.com/hypergeometric-function-in-mvtnorm-tp4483730p4483730.html
Sent from the
"or an incompetent"
Such harsh words Peter. You're not making this a friendly environment for
people to ask questions. Is there a less competent attribute mailing list so
that some of us don't offend you with our questions?
On Aug 13, 2010, at 2:11 PM, Peter Dalgaard wrote:
Andrea Franceschini
Andrea Franceschini wrote:
> I ask the question also because I found this line in Wikipedia:
> "The test (see above) based on the hypergeometric distribution
> (hypergeometric test) is identical to the corresponding one-tailed
> version of Fisher's exact test".
>
> Is this wrong ? May I kindly as
I ask the question also because I found this line in Wikipedia:
"The test (see above) based on the hypergeometric distribution
(hypergeometric test) is identical to the corresponding one-tailed
version of Fisher's exact test".
Is this wrong ? May I kindly ask a friendly explanation for
not-exper
On Aug 13, 2010, at 3:47 PM, Andrea Franceschini wrote:
>
> Dear R team,
> I have a simple question.
>
> I tried this command:
> phyper(17,449,19551,181, FALSE)
> [1] 1.47295e-07
>
> and then I tried this command:
> (fisher.test(matrix(c(17,449,181,19551),2,2),
> alternative='greater'))$p.valu
Dear R team,
I have a simple question.
I tried this command:
phyper(17,449,19551,181, FALSE)
[1] 1.47295e-07
and then I tried this command:
(fisher.test(matrix(c(17,449,181,19551),2,2),
alternative='greater'))$p.value
[1] 3.693347e-06
Shouldn't be identical the results of the two commands ?
Wh
Arnau Mir uib.es> writes:
>
> Hello.
>
> Somebody knows how to compute generalized hypergeometric series in R?
> (see
> http://functions.wolfram.com/HypergeometricFunctions/HypergeometricPFQ/02/
> to understand what I mean)
library(sos)
findFn("generalized hypergeometric function")
-> see
Hello.
Somebody knows how to compute generalized hypergeometric series in R?
(see
http://functions.wolfram.com/HypergeometricFunctions/HypergeometricPFQ/02/
to understand what I mean)
Thanks in advance,
Arnau.
__
R-help@r-project.org mailing list
The hypergeo package should be able to deal with this,
although the function you specify below looks like a degenerate case
(if I understand it correctly) so the convergence rate
is likely to be slow.
Let me know how you get on
best wishes
Robin (author of hypergeo)
Jarle Brinchmann wrote:
The dhyper etc deal with the hypergeometric _distribution_ while what
you appear to want have is the hypergeometric special function (the
connection is that the regular hypergeometric function is the
generating function for the hypergeometric distribution if I recall
correctly).
Anyway, what you
Hi,
I hope somebody can help me on how to use the hypergeometric function.
I did read through the R documentation on hypergeometric but not really
sure what it means.
I would like to evaluate the hypergeometric function as follows:
F((2*alpha+1)/2, (2*alpha+2)/2 , alpha+1/2, betasq/etasq).
Hi,
I hope somebody can help me on how to use the hypergeometric function. I did
read through the R documentation on hypergeometric but not really sure what it
means.
I would like to evaluate the hypergeometric function as follows:
F((2*alpha+1)/2, (2*alpha+2)/2 , alpha+1/2, betasq/etasq).
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