tdat[[z]]<-dat2[,sum(get(ColNames[z]))/sum(e),by="a"]
}
do.call(rbind,outputdat)
# a V1
#1: 1 7.00
#2: 2 7.125000
#3: 1 9.090909
#4: 2 10.125000
#5: 1 9.181818
#6: 2 6.25
A.K.
- Original Message -
From: Camilo Mora
To: r-help@r-project.org
Cc:
I would like to clarify my previous email about using data.table.
imagine the following data.frame called "data":
a b c d e
1 12 15 65 6
1 65 85 36 5
2 69 84 35 8
2 45 78 65 8
I want to aggregate the rows of colu
Hi,
On Wed, Mar 13, 2013 at 7:25 PM, Camilo Mora wrote:
> Hi everyone,
>
> I have a data.table called "data" with many columns which I want to group by
> column1 using data.table, given how fast it is.
>
> The problem with looping a data.table is that data.table does not like
> quotations to def
Hi everyone,
I have a data.table called "data" with many columns which I want to
group by column1 using data.table, given how fast it is.
The problem with looping a data.table is that data.table does not like
quotations to define the column names (e.g. "col2" instead of col2).
I found a
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