Does anyone know how to loop in GME using a list of text values. I am trying
to create home ranges for each animal in a point shapefile of locations.
Here is an example of the Command Text I am trying to use:
l-'SGF4037', 'SGF4244';
for (i in ls()){
kde(in=paste(SGF.shp),
Hello,
Sorry, forgot to Cc the list.
Em 01-07-2012 01:24, R. Michael Weylandt michael.weyla...@gmail.com
escreveu:
I might think replicate() is slightly more idiomatic, but I'm not in a position
to check if simplify=FALSE will keep a list.
It does:
class(replicate(20, f(1))) # matrix
Hello
I have a loop to sample 20 samples and I want to put them in one list, how I
can make this??
Regards
Sulafah
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
Instead of a loop you can use the replicate or lapply functions which
will create lists for you.
otherwise you can start with an empty list (mylist - list() )
then add to the list in each iteration of the loop:
for(i in 1:10) {
mylist[[i]] - myfunction(i)
}
On Sat, Jun 30, 2012 at 1:34
.
- Original Message -
From: solafah bh solafa...@yahoo.com
To: R help mailing list r-help@r-project.org
Cc:
Sent: Saturday, June 30, 2012 3:34 PM
Subject: [R] loop in list
Hello
I have a loop to sample 20 samples and I want to put them in one list, how I
can make this??
Regards
Hello,
You can avoid the loop using lapply.
f - function(x) sample(100, 10)
samp.list - lapply(1:20, f)
will choose 20 samples of 10 integers up to 100 and put them in a list.
All you need is to write a function f(). f() must have an argument, even
if it doesn't use it. If you need other
I might think replicate() is slightly more idiomatic, but I'm not in a position
to check if simplify=FALSE will keep a list.
Best,
Michael
On Jun 30, 2012, at 7:13 PM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
You can avoid the loop using lapply.
f - function(x) sample(100, 10)
I didn't know about crantastic actually.
I've looked what it is exactly and it indeed looks interesting, but I
don't really see how I would know that it would help me for the task.
There's a description of what it was built for, but how can I then know
which function from this package can help
Without reading all the details of your question, it looks like maybe
split() is what you want.
split( dataset, paste(dataset$SPECSHOR,dataset$BONE) )
or
split( dataset[,3], paste(dataset$SPECSHOR,dataset$BONE) )
-Don
At 5:12 PM +0100 1/21/10, Ivan Calandra wrote:
Hi everybody!
To use
Great.
If you mean the crantastic r package, sorry I wasn't clear, I meant the
crantastic website http://crantastic.org/.
If you meant the description of plyr then if the description looks useful
then click the link taking you to the package documentation and read it.
Same for any of the
Thanks for your advice, I will work on it then!
Just one last question. In which package can I find the function
data.table?
Ivan
Le 1/22/2010 17:18, Matthew Dowle a écrit :
Great.
If you mean the crantastic r package, sorry I wasn't clear, I meant the
crantastic website
data.table is the package name too. Make sure you find ?[.data.table which
is linked from ?data.table.
You could just do a mean of one variable first, and then build it up from
there e.g. dataset[, mean(epLsar), by=SPECSHOR,BONE].
To get multiple columns of output, wrap with DT() like this
Hi everybody!
To use some functions, I have to transform my dataset into a list, where
each element contains one group, and I have to prepare a list for each
variable I have (altogether I have 15 variables, and many entries per
factor level)
Here is some part of my dataset:
SPECSHORBONE
One way is :
dataset = data.table(ssfamed)
dataset[, whatever some functions are on Asfc, Smc, epLsar, etc ,
by=SPECSHOR,BONE]
Your SPECSHOR and BONE names will be in your result alongside the results of
the whatever ...
Or try package plyr which does this sort of thing too. And sqldf may
14 matches
Mail list logo
