Yes,. Thanks for the clarification. I tried to indicate this with my
comment about it being used as the "name" argument of ls().
What I should have said is that it is syntactically wrong as a way to
specify an argument of any function -- "myarg != something" does not
specify anything about the
On 14/07/2021 8:21 p.m., Bert Gunter wrote:
Actually fun( param != something..) is syntactically incorrect in the first
place for any function!
You have to be careful with absolute statements:
> f <- function(pattern) cat("It's legal!")
> f(pattern != something..)
It's legal!
"pattern
Thanks Andrew. it works well. --- Kai
On Wednesday, July 14, 2021, 05:22:01 PM PDT, Bert Gunter
wrote:
Actually fun( param != something..) is syntactically incorrect in the first
place for any function!
ls sees "pat != whatever" as the "name" argument of ls() and can't make any
Actually fun( param != something..) is syntactically incorrect in the first
place for any function!
ls sees "pat != whatever" as the "name" argument of ls() and can't make
any sense of it, of course.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
Hello,
First, `ls` does not support `!=` for pattern, but it's actually throwing a
different error. For `rm`, the objects provided into `...` are substituted
(not evaluated), so you should really do something like
rm(list = ls(pattern = ...))
As for all except "con", "DB2", and "ora", I would
Hello List,
I have many data frames in environment. I need to keep 3 data frames only, con
DB2 and ora.
I write the script to do this.
rm(ls(pattern != c("(con|DB2|ora)")))
but it give me an error message:
Error in rm(ls(pattern != c("(con|DB2|ora)"))) :
... must contain names or
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