Niloofar.Javanrouh javanrouh_n at yahoo.com writes:
hello,
i want to differentiate of L with respect to b
when:
L= k*ln (k/(k+mu)) + sum(y) * ln (1-(k/mu+k))
#(negative binomial ln likelihood)
and
ln(mu/(mu+k)) = a+bx #link function
how can i do it in R?
thank you.
hello,
i want to differentiate of L with respect to b
when:
L= k*ln (k/(k+mu)) + sum(y) * ln (1-(k/mu+k)) #(negative binomial ln
likelihood)
and
ln(mu/(mu+k)) = a+bx #link function
how can i do it in R?
thank you.
_
Best Regards
Niloofar.Javanrouh
Ph.D Student of
On Mon, May 5, 2014 at 9:43 AM, Niloofar.Javanrouh
javanrou...@yahoo.com wrote:
hello,
i want to differentiate of L with respect to b
when:
L= k*ln (k/(k+mu)) + sum(y) * ln (1-(k/mu+k)) #(negative binomial ln
likelihood)
and
ln(mu/(mu+k)) = a+bx #link function
how can i do it in
On May 5, 2014, at 6:05 PM, Gabor Grothendieck wrote:
On Mon, May 5, 2014 at 9:43 AM, Niloofar.Javanrouh
javanrou...@yahoo.com wrote:
hello,
i want to differentiate of L with respect to b
when:
L= k*ln (k/(k+mu)) + sum(y) * ln (1-(k/mu+k)) #(negative binomial ln
likelihood)
and
On Mon, May 5, 2014 at 10:16 PM, David Winsemius dwinsem...@comcast.net wrote:
On May 5, 2014, at 6:05 PM, Gabor Grothendieck wrote:
On Mon, May 5, 2014 at 9:43 AM, Niloofar.Javanrouh
javanrou...@yahoo.com wrote:
hello,
i want to differentiate of L with respect to b
when:
L= k*ln
5 matches
Mail list logo
