If you return the value as named list, you get your answer
using unlist(res, recursive=F):
res - lapply(1:2, function(i) {val - list(i);
names(val) - paste(Hugo, i, sep=_); return(val)})
unlist(res, rec=F)
$Hugo_1
[1] 1
$Hugo_2
[1] 2
Antje wrote:
Oh true, this would solve the problem
Hi there,
I have a very simple question. If I execute the following code:
test - function(x) {
name - paste(x,info_within_function)
c(1,2,3,4,5)
}
ret - lapply(1:10, test)
, I end up with a list and each entry is just numbered [[1]], [[2]], ... [[10]]
How can I force the
On Fri, 2008-07-18 at 13:45 +0200, Antje wrote:
Hi there,
I have a very simple question. If I execute the following code:
test - function(x) {
name - paste(x,info_within_function)
c(1,2,3,4,5)
}
Here your test is returning c(1,2,3,4,5), and is doing nothing with
name,
Hi Gavin,
thanks a lot for your answer.
Maybe I did not explain very well what I want to do and probably chose a bad
example. I don't mind spaces or names starting with a number. I could even name it:
Hugo1, Hugo2, ...
My biggest problem is, that not only the values are calculated/estimated
On Fri, 2008-07-18 at 14:19 +0200, Antje wrote:
Hi Gavin,
thanks a lot for your answer.
Maybe I did not explain very well what I want to do and probably chose a bad
example. I don't mind spaces or names starting with a number. I could even
name it:
Hugo1, Hugo2, ...
My biggest
Thanks a lot for your help!
I know that I cannot directly access the list created, I just was not sure if
there is any format of the return value which could provide additionally a
name for the returned list.
I tried to return the values as list with the appropriate name but then I end
up
Oh true, this would solve the problem too :-)
Thanks a lot for the suggestions!
Antje
Martin Morgan schrieb:
Antje [EMAIL PROTECTED] writes:
Thanks a lot for your help!
I know that I cannot directly access the list created, I just was not
sure if there is any format of the return value
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