Re: [R] nproc parameter in efpFunctional

2011-11-07 Thread bonda
Thank you very much, it works now! Best regards, J -- View this message in context: http://r.789695.n4.nabble.com/nproc-parameter-in-efpFunctional-tp3972419p3998747.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org

Re: [R] nproc parameter in efpFunctional

2011-11-04 Thread bonda
The 2006 CSDA paper is really very informative, perhaps, I'm trying to understand the things lying beyond. If we have e.g. k=3, then taking nproc=3 for the functional maxBB we get a critical value (boundary) maxBB$computeCritval(0.05,nproc=3) [1] 1.544421, and this for nproc=NULL (Bonferroni

Re: [R] nproc parameter in efpFunctional

2011-11-04 Thread Achim Zeileis
On Fri, 4 Nov 2011, bonda wrote: The 2006 CSDA paper is really very informative, perhaps, I'm trying to understand the things lying beyond. If we have e.g. k=3, then taking nproc=3 for the functional maxBB we get a critical value (boundary) maxBB$computeCritval(0.05,nproc=3) [1] 1.544421,

Re: [R] nproc parameter in efpFunctional

2011-11-03 Thread bonda
Thank you. I've understood, that it should be k (number of parameters) separate Brownian bridges. Is it possible, to get such separated/disaggregated processes also in function efp()? (one can take gefp(..., family=gaussian), or construct by myself residuals(lm.model)*X, but still interesting).

Re: [R] nproc parameter in efpFunctional

2011-11-03 Thread Achim Zeileis
On Thu, 3 Nov 2011, bonda wrote: Thank you. I've understood, that it should be k (number of parameters) separate Brownian bridges. Well, if you use a process based on OLS residuals, you have always a one-dimensional process even though your model has k parameters. Hence, the two parameters

[R] nproc parameter in efpFunctional

2011-11-02 Thread bonda
Hello all, could anyone explain the exact meaning of parameter nproc? Why different values of nproc give so different critical values, i.e. meanL2BB$computeCritval(0.05,nproc=3) [1] 0.9984853 meanL2BB$computeCritval(0.05,nproc=1) [1] 0.4594827 The strucchange-package description gives integer

Re: [R] nproc parameter in efpFunctional

2011-11-02 Thread Achim Zeileis
On Wed, 2 Nov 2011, bonda wrote: Hello all, could anyone explain the exact meaning of parameter nproc? Why different values of nproc give so different critical values, i.e. meanL2BB$computeCritval(0.05,nproc=3) [1] 0.9984853 meanL2BB$computeCritval(0.05,nproc=1) [1] 0.4594827 The