В Wed, 15 Feb 2023 14:20:16 +
Nick Wray пишет:
> how to get the p values for changepoints in the "changepoint"
> package?
The documentation of this package is not always precise in describing
what the code actually does. It's possible to find out by reading the
source code that with
Hello Does anyone know how to get the p values for changepoints in the
"changepoint" package? There is guidance in the CRAN vignette
https://cran.r-project.org/web/packages/changepoint/changepoint.pdf but I
can't make it work to get the p value out... Thanks Nick Wray
[[alternative HTML
Hello,
It seems to be right.
You have Chi-squared = 23.724, df = 8, p-value = 0.002549. So try the R
function ?pchisq:
pchisq(23.724, df = 8, lower = FALSE)
[1] 0.002549054
Hope this helps,
Rui Barradas
Em 23-05-2017 13:08, Dhivya Narayanasamy escreveu:
Hi,
I am working with bivariate
Hi,
I am working with bivariate time series data. I used VAR model to fit and
forecast.
But the "*p*" value from seria.test (Portmanteau Test) gives values *p<<
0.05*. Is that okay?
> var1 = VAR(datax.ts, p= 8)
> serial.test(var1, lags.pt=10, type = "PT.asymptotic")
Portmanteau Test
Dear all,
I have a question concerning the p-value. When running log-rank test I get
a p-value = 0.
What is it mean? Can this be true? Why aren´t there decimal points? Is
there a way to find out the exact p-value?
Here is the output:
> survdiff(Surv(tempo2,status)~tphist, data=base,rho=0)
Call:
Hello,
How can I print out the p-value or the t-test value for coefficients estimated
from a likelihood function.
Thanks
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
My table having 40 raw and 4 columns, in that 4 columns first column belongs
to one group and the remaining constitute the other group. using following
commands for calculating jaccard's index
x - read.csv(file name,header=T, sep= )
jac - vegdist(x,method=jaccard)
from this out file(jac) how can
Hi Peter,
That was my first port of call before I posted this thread. Unfortunately,
it does not seem to explicitly state which test is used or how the p-value
is calculated.
Thanks,
Rob.
--
View this message in context:
On 16 Feb 2015, at 00:31 , Rob Wood robert.w...@adelphigroup.com wrote:
Hi all,
When using the match command from the matching package, the output reports
the treatment effect, standard error, t-statistic and a p-value. Which test
is used to generate this p-value, or how us it generated?
Hi all,
When using the match command from the matching package, the output reports
the treatment effect, standard error, t-statistic and a p-value. Which test
is used to generate this p-value, or how us it generated?
Thanks,
Rob.
--
View this message in context:
Thanks Michael.
I have read the original article and I guess whether the following formula
could resolve my question?
*for adjusted HR of each BMI category,*
fit-coxph(Surv~factor(BMI-category)+..+covariates)
*for trend, *
fit-coxph(Surv~as.numeric(BMI-category)+..+covariates)
*# p trend may be
Thanks peter.
*Yao Zhu*
*Department of UrologyFudan University Shanghai Cancer CenterShanghai,
China*
2014/1/5 peter dalgaard pda...@gmail.com
On 04 Jan 2014, at 13:56 , zhu yao mailzhu...@gmail.com wrote:
Thanks for the suggestion.
The results is presented in following table. The
On 1/4/2014 12:39 AM, zhu yao wrote:
Dear Sir
Many papers calculated the p value of trends for odds ratios of ordered
category variables. I have found the tabodds command in Stata. But how to
do it in R?
Thanks
*Yao Zhu*
If what you are looking at is a 2 x 2 x k table, where you want the odds
On 04.01.2014 06:39, zhu yao wrote:
Dear Sir
Many papers calculated the p value of trends for odds ratios of ordered
category variables. I have found the tabodds command in Stata. But how to
do it in R?
Depends on the method you want to use ... and most ladies and gents on
this list won't
On 04 Jan 2014, at 12:53 , Uwe Ligges lig...@statistik.tu-dortmund.de wrote:
On 04.01.2014 06:39, zhu yao wrote:
Dear Sir
Many papers calculated the p value of trends for odds ratios of ordered
category variables. I have found the tabodds command in Stata. But how to
do it in R?
On 04 Jan 2014, at 13:56 , zhu yao mailzhu...@gmail.com wrote:
Thanks for the suggestion.
The results is presented in following table. The authors calculated p value
for linearity and trend and they stated in the methods:
Linear and nonlinear trends of BMI associated with each mortality
Dear Sir
Many papers calculated the p value of trends for odds ratios of ordered
category variables. I have found the tabodds command in Stata. But how to
do it in R?
Thanks
*Yao Zhu*
*Department of UrologyFudan University Shanghai Cancer CenterShanghai,
China*
[[alternative HTML
Rosario Garcia Gil M.Rosario.Garcia at slu.se writes:
Hello
I have run an anova analysis for
the fallowing model: H_obs=mu+REGION+MANAGEMENT + e
When I run it in ASRelm I get the p-value for mu, and,
of course also for the two dependent variables (REGION
and MANAGEMENT)
When I run
Hello
I have run an anova analysis for the fallowing model:
H_obs=mu+REGION+MANAGEMENT + e
When I run it in ASRelm I get the p-value for mu, and, of course also for the
two dependent variables (REGION and MANAGEMENT)
When I run it in R, I do not get the pvalue for mu.
Can some one help me
Hello R-users,
I am trying to plot P value discrepancy plots as describe by Russell
Davidson and James G. MacKinnon in Graphical Methods for Investigating the
Size and Power of Hypothesis Tests (1998).
I know ecdf () to obtain the empirical cumulative distribution frequencies
and knots() to
On 09/06/2012 05:00 AM, r-help-requ...@r-project.org wrote:
Hi, R experts
I am currently using lmekin() function in coxme package to fit a
mixed effect model for family based genetic data. How can I extract the p
value from a lmekin object? When I print the object in R console, I can
Hi All,
when using the linear model lm() to fit data of the form y = k * x +
b, is it possible to know the p-value for the parameters k and b? i.e.
can we find the result of the form (k, Δk; b, Δb)?
Thanks in advance!
Li Sun
__
R-help@r-project.org
On 24.06.2012 17:47, Li SUN wrote:
Hi All,
when using the linear model lm() to fit data of the form y = k * x +
b, is it possible to know the p-value for the parameters k and b? i.e.
can we find the result of the form (k, Δk; b, Δb)?
If you explain what Δk means in a linear model, we may be
Sorry for the confusion.
Let me state the question again. I missed something in my original statement.
When using the linear model lm() to fit data of the form y = k * x +
b, where k, b are the coefficients to be found, and x is the variable
and has an error bar (uncertainty) Δx of the same
On Jun 24, 2012, at 1:21 PM, Li SUN wrote:
Sorry for the confusion.
Let me state the question again. I missed something in my original
statement.
When using the linear model lm() to fit data of the form y = k * x +
b, where k, b are the coefficients to be found, and x is the variable
and
On 24/06/2012 18:39, David Winsemius wrote:
On Jun 24, 2012, at 1:21 PM, Li SUN wrote:
Sorry for the confusion.
Let me state the question again. I missed something in my original
statement.
When using the linear model lm() to fit data of the form y = k * x +
b, where k, b are the
Thanks David and Brian.
But what if x is exact while y has some uncertainty Δy, in the
relation y = k * x + b?
Now I need to fit some data like
x = 1, 2, 3, 4, 5
y±Δy = 1.1±0.1, 2.0±0.2, 3.1±0.2, 4.1±0.1, 5.0±0.2
Is there any mechanism to pass x, y and
On 24.06.2012 20:35, Li SUN wrote:
Thanks David and Brian.
But what if x is exact while y has some uncertainty Δy, in the
relation y = k * x + b?
Now I need to fit some data like
x = 1, 2, 3, 4, 5
y±Δy = 1.1±0.1, 2.0±0.2, 3.1±0.2, 4.1±0.1, 5.0±0.2
2012/6/24 Uwe Ligges lig...@statistik.tu-dortmund.de:
On 24.06.2012 20:35, Li SUN wrote:
Thanks David and Brian.
But what if x is exact while y has some uncertainty Δy, in the
relation y = k * x + b?
Now I need to fit some data like
x = 1, 2, 3, 4,
Dear Li Sun:
You appear to have a good deal of statistical confusion. R-help is not a
statistical consulting service. You should consult a local statistician or,
if that's not possible,post on a statistical help list like
stats.stackexchange.com
-- Bert
On Sun, Jun 24, 2012 at 12:04 PM, Li SUN
But what if x is exact while y has some uncertainty Δy, in the
relation y = k * x + b?
Again, no: this is not a linear model. Assumption in a linear model is
that the errors are identically distributed.
Surely not; errors in a linear model do not need to be homoscedastic. lm
handles
Dear All,
Thanks for all your explanations and sorry for the confusion. I will
need to consult some statistician for help.
Sincerely,
Li Sun
2012/6/24 S Ellison s.elli...@lgcgroup.com:
But what if x is exact while y has some uncertainty Δy, in the
relation y = k * x + b?
Again, no: this
It is possible to calculate the c-index for time dependent outcomes (such
as disease) using the
survivalROChttp://cran.r-project.org/web/packages/survivalROC/survivalROC.pdf
package
in R. My question is : is it possible to produce a p-value for the c-index
that is calculated (at a specific point
Hi
How does mlogit count the p-values of the variables?
Ville
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hello,
I have to compute the pooled z-value and I would like to know which way is
more appropriate
b - c( -0.205,1.040,0.087)
s - c(0.449,0.167,0.241)
n - c(310, 342, 348)
z - b/s
Z - sum(z)/sqrt(length(n))
P - 2*(1-pnorm(abs(Z)))
P
w - sqrt(n)
Zw - sum(w * z)/sqrt(sum(w^2))
Pw - 1 -
On Wed, Mar 14, 2012 at 3:41 AM, cheba meier cheba.me...@googlemail.com wrote:
Hello,
I have to compute the pooled z-value and I would like to know which way is
more appropriate
b - c( -0.205,1.040,0.087)
s - c(0.449,0.167,0.241)
n - c(310, 342, 348)
z - b/s
Z - sum(z)/sqrt(length(n))
Dear Peter,
Many thanks for the reply.
Sure, this is just an example and it makes zero sense!
Regards,
Dunia
2012/3/4 peter dalgaard pda...@gmail.com
On Mar 4, 2012, at 12:21 , Dunia Scheid wrote:
Dear all,
I am fitting a GLM similar to
library(MASS)
anorex.1 -
Dear all,
I am fitting a GLM similar to
library(MASS)
anorex.1 - glm(Treat~Postwt+Prewt,family = binomial, data = anorexia)
I have found two ways of computing the p-value of the fitted model:
pval1 - 1-pchisq(anorex.1$deviance,anorex.1$df.residual)
pval2 - 1-pchisq(anorex.1$null.deviance -
On Mar 4, 2012, at 12:21 , Dunia Scheid wrote:
Dear all,
I am fitting a GLM similar to
library(MASS)
anorex.1 - glm(Treat~Postwt+Prewt,family = binomial, data = anorexia)
I hope that's just for an example. The actual analysis makes zero sense to me...
I have found two ways of
did) seems reasonable to me at least to ask.
Cheers,
Josh
Best,
Thierry
- Ursprüngliche Mail -
Von: Joshua Wiley jwiley.ps...@gmail.com
An: Thierry Julian Panje tpa...@stanford.edu
CC: r-help@r-project.org
Gesendet: Samstag, 10. Dezember 2011 13:53:00
Betreff: Re: [R] p
Hi,
I'm new to R and using it for Cox survival analysis. Thanks to this great forum
I learned how to compute the HR with its confidence interval.
My question would be: Is there any way to get the p-value for a hazard ratio in
addition to the confidence interval?
Thanks,
Thierry
--
Hi Thierry,
Could you give us an example of what exactly you are doing
(preferablly reproducible R code)? I may be misunderstanding you, but
if you are fitting cox proportional hazard models using the coxph()
function from the surival package, summary(yourmodel) should give the
SE, p-value based
) seems reasonable to me at least to ask.
Cheers,
Josh
Best,
Thierry
- Ursprüngliche Mail -
Von: Joshua Wiley jwiley.ps...@gmail.com
An: Thierry Julian Panje tpa...@stanford.edu
CC: r-help@r-project.org
Gesendet: Samstag, 10. Dezember 2011 13:53:00
Betreff: Re: [R] p-value
The p-value as I understand it, is the probability of seeing a phenomenon at
least as extreme as the one which you observed assuming the null hypothesis
is true. In other words, if you assume there is no difference (which is the
NULL for you here I believe), and there is an 81% chance of seeing
Thanks for your help. I was not familiar with this form of notating the p
value.
--
View this message in context:
http://r.789695.n4.nabble.com/p-value-in-R-beginners-question-tp3915873p3918140.html
Sent from the R help mailing list archive at Nabble.com.
Dear all,
i have done some regression analyses but i do not understand the p value.
These are the results
t-value p value
geno.1 -0.229 0.978 -0.234 8.15e-01
geno.50.647 1.146 0.565 5.73e-01
stress:geno.5-1.337 1.022 -1.307
This is just scientific notation, so
8.15e-01 is the same as:
8.15*10^-1
[1] 0.815
niki wrote:
Dear all,
i have done some regression analyses but i do not understand the p value.
These are the results
t-value p value
geno.1
Hello,
I want to understand how to tell if a model is significant.
For example I have vectX1 and vectY1.
I seek first what model is best suited for my vectors and
then I want to know if my result is significant.
I'am doing like this:
model1 - lm(vectY1 ~ vectX1, data= d),
model2 - nls(vectY1
Tatiana:
It sounds like you are in way over your head statistically. This is
not a statistics tutorial site (though sometimes good folks do help
witjh this). I suggest you try http://stats.stackexchange.com/ .
Better yet, work with your local statistician.
Cheers,
Bert
On Thu, Sep 15, 2011 at
On 11-02-07 19:21, Sascha Vieweg wrote:
Hello, knowing that some index y, with y(341)=2, SE=3, is t-distributed, I
(think I) can find an appropriate (left/one-sided) p-value with
R: y - 2
R: yse - 3
R: (p - 1-pt(y/yse, df=341))
Now, some simulation resulted in the non-parametric
Hello, knowing that some index y, with y(341)=2, SE=3, is
t-distributed, I (think I) can find an appropriate
(left/one-sided) p-value with
R: y - 2
R: yse - 3
R: (p - 1-pt(y/yse, df=341))
Now, some simulation resulted in the non-parametric distribution,
Y, of my index, y:
R: Y -
On Mon, Jan 31, 2011 at 09:42:27PM +0100, moleps wrote:
Dear all,
Given
rr-data.frame(r1-rnorm(1000,10,5),r2-rnorm(1000,220,5))
Hello.
There is already an answer to your question. However, i think
that the above command works in a different way than you
expect. The embedded assignments
My terminology is probably way off. I´ll try again in plain english.
I´d like to generate a scatter plot of r1 r2 and color code each pair
according to the probability of observing the pair given that the two samples
(r1 r2) are drawn from two independent normal distributions.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of moleps
Sent: Tuesday, February 01, 2011 11:32 AM
To: Peter Ehlers
Cc: r-help@r-project.org
Subject: Re: [R] p value for joint probability
My terminology is probably way off
Date: Tue, 1 Feb 2011 12:10:31 -0800
From: nord...@dshs.wa.gov
To: r-help@r-project.org
Subject: Re: [R] p value for joint probability
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of moleps
Sent: Tuesday
On Feb 1, 2011, at 2:31 PM, moleps wrote:
My terminology is probably way off. I´ll try again in plain english.
I´d like to generate a scatter plot of r1 r2 and color code each
pair according to the probability of observing the pair given that
the two samples (r1 r2) are drawn from two
On Tue, Feb 01, 2011 at 08:31:57PM +0100, moleps wrote:
My terminology is probably way off. I´ll try again in plain english.
I´d like to generate a scatter plot of r1 r2 and color code each pair
according to the probability of observing the pair given that the two samples
(r1 r2) are
Allright.. Appreciate the input on non-zero terminology (:-). What I wanted was:
rr-data.frame(r1=rnorm(1000,10,5),r2=rnorm(1000,220,5))
with(rr,plot(r1,r2))
r3-kde2d(r1,r2,lims=c(2,18,200,240))
filled.contour(r3)
//M
On 1. feb. 2011, at 21.26, David Winsemius wrote:
On Feb 1, 2011, at
Dear all,
Given
rr-data.frame(r1-rnorm(1000,10,5),r2-rnorm(1000,220,5))
How can I add a column (rr$p) for the joint probability of each r1 r2 pair?
I know how to add the column.. I just dont know how to compute the p value for
joint probabilities given the two samples.
//M
On 2011-01-31 12:42, moleps wrote:
Dear all,
Given
rr-data.frame(r1-rnorm(1000,10,5),r2-rnorm(1000,220,5))
How can I add a column (rr$p) for the joint probability of each r1 r2 pair?
If you take the values in each pair to be observations
from two independent Normal distributions, it's
Hi, does anyone know if there is a way to easily extract p-values from
the regsubsets() function?
Thanks,
James Stegen
--
James C. Stegen
NSF Postdoctoral Fellow in Bioinformatics
University of North Carolina
Chapel Hill, NC
919-962-8795
ste...@email.unc.edu
10, 2010 8:31 AM
To: r-help@r-project.org
Subject: [R] p-value from regsubsets
Hi, does anyone know if there is a way to easily extract p-values from
the regsubsets() function?
Thanks,
James Stegen
--
James C. Stegen
NSF Postdoctoral Fellow in Bioinformatics
University of North Carolina
Hello,
I'm trying to generate a p.value directly from the output of a fisher
exact test odds ratio statistic without resorting to performing
another test on the 2x2 table itself. The motivation for this stems
from a need to modify the test statistic before calculating it's new p-
value.
I've
Here is my dataframe with 1000 rows:
employee_id weigth p-value
100 150
101 200
102 300
103 180
.
My question:
how can I calculate the p-value in R for each employee? the
What is your null hypothesis? What is your alternate hypothesis? What
is the test statistic? Why do you want a p-value?
Hadley
On Thu, Jul 22, 2010 at 5:40 PM, jd6688 jdsignat...@gmail.com wrote:
Here is my dataframe with 1000 rows:
employee_id weigth p-value
100
103180 0.6722391
(You might want to think about the spelling of 'weigth' a bit more.)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of jd6688
Sent: Friday, 23 July 2010 8:41 AM
To: r-help@r-project.org
Subject: [R] p-VALUE
-project.org
Subject: Re: [R] p value
runif(1)
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On
Behalf Of Soham
Sent: Saturday, May 15, 2010 9:05 AM
To: r-help@r-project.org
Subject: [R
How to compute the p-value of a statistic generally?
--
View this message in context:
http://r.789695.n4.nabble.com/p-value-tp2217867p2217867.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Hi Soham,
I don't feel your question is well defined.
But an equally ill defined answer would be:
Through a permutation test.
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com
runif(1)
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Soham
Sent: Saturday, May 15, 2010 9:05 AM
To: r-help@r-project.org
Subject: [R] p value
How to compute the p-value
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Leon Yee
Sent: Tuesday, November 10, 2009 11:23 PM
To: R help
Subject: [R] p-value calculation on a joint distribution
Dear all,
I am trying to use SAMr-library(samr), it gives me p-value = 1.001, any idea
why?
Many thanks,
Amor
__
z gegen Massenmails.
[[alternative HTML version deleted]]
__
amor Gandhi wrote:
Dear all,
I am trying to use SAMr-library(samr), it gives me p-value = 1.001, any idea
why?
Well, the package maintainer might be a better place to ask. (Bring an
example if you do.)
However, as a generic matter, the result is obviously nonsensical, and
could be due to
the p-value of 0.004332?
Sorry for these questions.
Best wishes,
Amor
--- Peter Dalgaard p.dalga...@biostat.ku.dk schrieb am Fr, 13.11.2009:
Von: Peter Dalgaard p.dalga...@biostat.ku.dk
Betreff: Re: [R] p-value 1
An: amor Gandhi amorigan...@yahoo.de
CC: r-h...@stat.math.ethz.ch
Datum
Dalgaard p.dalga...@biostat.ku.dk schrieb am Fr, 13.11.2009:
Von: Peter Dalgaard p.dalga...@biostat.ku.dk
Betreff: Re: [R] p-value 1
An: amor Gandhi amorigan...@yahoo.de
CC: r-h...@stat.math.ethz.ch
Datum: Freitag, 13. November 2009, 15:24
amor Gandhi wrote:
Dear all,
I am trying to use SAMr
Dear R users,
For a uni-variable distribution represented in a numerical vector,
we can obtain a distribution function using 'ecdf', and then calculate
corresponding p-values. But if I have a 2-column dataframe representing
a bi-variable joint distribution, given a pair of values, how can
Hi R community
I have a question. I'll explain my situation. I have to build a climate model
to obtain monthly and annual temperature from 2004 to 2008 from a specif area
in Almeria (Spain). To build this climate model, I will use Multiple
regression. My dependant variable will be monthly and
Lucas
This problem is very old --- older than keypunches. There are several
methods for selecting variables (forward, backwards, both, all subsets)
using a variety of criteria (p-values, R^2, adjusted R^2, Cp, AIC, BIC,
and more). Be sure you understand the methods, especially the tendency to
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von Lucas Sevilla García
Gesendet: Thursday, September 24, 2009 8:49 AM
An: r-help@r-project.org
Betreff: [R] P-value and R-squared variable selection criteria
Dear List,
is there an easy and fast way to compute the p value from a given F
value and given degrees of freedom for an effect and the dfs for the
residuals? I think of a function like this:
compute.p(F.value, numerator.dfs, denominator.dfs)
which returns the p value.
Thanks,
Sascha
Hi Sascha,
Take a look at ?pf
HTH,
Jorge
On Wed, Sep 23, 2009 at 11:34 AM, Sascha Wolfer wrote:
Dear List,
is there an easy and fast way to compute the p value from a given F value
and given degrees of freedom for an effect and the dfs for the residuals? I
think of a function like this:
Dear All,
I decided to use an AR(1) model for the residual series and trying to find the
p-value for each parameter by using arima command in R, but i never find it
from the output. The output gives me the parameter and mean's value, its
standard error, estaimated variance, AIC and
Dear all,
I have a question concerning the p-value. When running coxph I get a p-value
= 0. :confused:
Can this be true? Why aren´t there decimal points? Is there a way to find
out the exact p-value?
Here is the output:
Because your test statistics (z=-9.16) is too small. (well, z 1.96 or
Z -1.96 is p=0.05)
If you really want the exact p, you can try
pnorm(-9.16)
if I were you I will quote p0.001 as well as the test statistics. (if
you are going to submit it to medical journals)
C
On Thu, Oct 30, 2008 at
On Thu, 30 Oct 2008, GSt wrote:
Dear all,
I have a question concerning the p-value. When running coxph I get a p-value
= 0. :confused:
Can this be true? Why aren??t there decimal points? Is there a way to
find out the exact p-value?
The p-values are rounded, and of course they are not
On Fri, 2008-07-04 at 21:14 -0700, Michael Denslow wrote:
Dear R-helpers,
I am running metaMDS in the vegan package, which uses isoMDS in MASS,
to perform Nonmetric Multidimentional Scaling (NMDS).
I have seen some authors report a p-value for the NMDS ordination
based on randomization of
Dear R-helpers,
I am running metaMDS in the vegan package, which uses isoMDS in MASS, to
perform Nonmetric Multidimentional Scaling (NMDS).
I have seen some authors report a p-value for the NMDS ordination based on
randomization of the dataset. As I understand it this is meant to compare the
July 2008 2:14 PM
To: r-help@r-project.org
Subject: [R] p-value for Nonmetric Multidimentional Scaling?
Dear R-helpers,
I am running metaMDS in the vegan package, which uses isoMDS in MASS, to
perform Nonmetric Multidimentional Scaling (NMDS).
I have seen some authors report a p-value for the NMDS
Dear R User,
say I have this sample of data ( attach with). What i'm going to do is to
test whether this data is uniformly distributed or not by finding the p-value.
I've tried using the punif command but it gave me the value of 1 of all the
data. Any suggestion on R command to find the
Here's a sample:
unif_rand_1 - runif(1000);
unif_rand_2 - runif(1000);
ks.test(unif_rand_1,unif_rand_2);
Two-sample Kolmogorov-Smirnov test
data: unif_rand_1 and unif_rand_2
D = 0.021, p-value = 0.9802
alternative hypothesis: two-sided
So in your case:
ks.test( runif( length(
(midpoint)
HTH,
Patrick
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of mohamed nur
anisah
Sent: Thursday, June 12, 2008 9:56 AM
To: r-help@r-project.org
Subject: [R] p-value
Dear R User,
say I have this sample of data ( attach with). What i'm going
Not sure if this is what you are looking for but you can get
the p-value with something like this:
# Create a vector
mydata-
c(132968364, 135945080, 156539568, 157817896, 162399496,
168344072, 173146584, 176302744, 182878168, 183946152,
Dear R-helpers,
I would like to do a Spearman rank order test, and used the cor() function
with the method spearman.
It gives me a number (correlation coefficient?) , but how can I get the
p-value?
Thank you for the help in advance!
Regards,
Anne-Katrin
--
[[alternative HTML
On Thu, 2008-02-28 at 16:17 +0100, Anne-Katrin Link wrote:
Dear R-helpers,
I would like to do a Spearman rank order test, and used the cor() function
with the method spearman.
It gives me a number (correlation coefficient?) , but how can I get the
p-value?
Thank you for the help in
On 2/28/08, Anne-Katrin Link [EMAIL PROTECTED] wrote:
I would like to do a Spearman rank order test, and used the cor() function
with the method spearman.
It gives me a number (correlation coefficient?) , but how can I get the
p-value?
You're probably looking for rcorr() from Hmisc. It
--
-Ursprüngliche Nachricht-
Von: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Im
Auftrag von Anne-Katrin Link
Gesendet: Thursday, February 28, 2008 10:17 AM
An: r-help@r-project.org
Betreff: [R] p-value in Spearman rank order
Dear R-helpers,
I would like to do a Spearman rank order test, and used the cor
Dear R-users,
I am currently trying to switch from SAS to R, and am not very familiar with R
yet, so forgive me if this question is irrelevant.
If I try to find the significance of the fixed factor spikes in a generalized
linear mixed model, with site nested within zone as a random factor, I
The lme4 package is still in development. I can't guarantee the
evaluation of the deviance for the quasipoisson family. There is a
certain amount of mystery about the role of the dispersion parameter
and the null deviance in families like quasipoisson and quasibinomial.
For the time being don't
How can i print only the P-Value of the kolmogorov smirnov test?
ks.test(VeriSeti1, VeriSeti2)
Two-sample Kolmogorov-Smirnov test
data: VeriSeti1 and VeriSeti2
D = 0.5, p-value = 0.4413
alternative hypothesis: two-sided
This expression gives me the whole test results, i need only
ks.test(x,y)[2]
On 10/3/07, Emre Unal [EMAIL PROTECTED] wrote:
How can i print only the P-Value of the kolmogorov smirnov test?
ks.test(VeriSeti1, VeriSeti2)
Two-sample Kolmogorov-Smirnov test
data: VeriSeti1 and VeriSeti2
D = 0.5, p-value = 0.4413
alternative hypothesis:
1 - 100 of 101 matches
Mail list logo
