Jessica, thank you for your reply.
Hi Eik,
thank you VERY for your reply and thorough explanation!
I hadn't understood what arrays are and after receiving your mail I read
more on arrays (and data types, modes, classes etc in general) (and
understood more than a few month ago) and understood thi
Hi Marion,
as stated in the help file ?apply coerces a data.frame object into an
array. Since an array has only one type of data, this coercion turns all
your variables into strings (because this data type can hold all
information given without loss).
If it happens that your data.frame consists on
apply(mydataframe,2,function(x){ print(x);is.factor(x)})
[1] "1" "2" "3" "4"
[1] "16.99" "10.34" "21.01" "23.68"
[1] "1.01" "1.66" "3.50" "3.31"
[1] "Male" "Male" "Male" "Female"
X total_billtipsex
FALSE FALSE FALSE FALSE
> sapply(mydataframe,fu
Dear people,
I am including an example of a dataframe:
mydataframe<-data.frame(X=c(1:4),total_bill=c(16.99,10.34,21.01,23.68),tip=c(1.01,1.66,3.50,3.31),sex=c("Male","Male","Male","Female"))
When I use the sapply function getting the information about the factors
works:
sapply(mydataframe,funct
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