On Dec 1, 2012, at 01:00 , David Winsemius wrote:
On Nov 30, 2012, at 1:05 PM, jaybell wrote:
sorry, I repost the question again
Why? This was already answered.
a=c(0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9)
b=c(0.9, 0.8, 0.7, 0.6, 0.5, 0.4, 0.3, 0.2, 0.1)
cor(a,b)= -1
a=c(0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9)
b=c(0.9, 0.8, 0.7, 0.6, 0.5, 0.4, 0.3, 0.2, 0.1)
cor(a,b)= -1
a'=qbinom(a, 1, 0.5)
b'=qbinom(b, 1, 0.5)
why cor(a',b') becomes -0.5 ?
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On Fri, Nov 30, 2012 at 9:47 AM, jaybell stephe...@yahoo.com.tw wrote:
a=c(0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9)
b=c(0.9, 0.8, 0.7, 0.6, 0.5, 0.4, 0.3, 0.2, 0.1)
cor(a,b)= -1
a'=qbinom(a, 1, 0.5)
b'=qbinom(b, 1, 0.5)
why cor(a',b') becomes -0.5 ?
On my computer the correlation is
sorry, I repost the question again
a=c(0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9)
b=c(0.9, 0.8, 0.7, 0.6, 0.5, 0.4, 0.3, 0.2, 0.1)
cor(a,b)= -1
pa=qbinom(a, 1, 0.5)
pb=qbinom(b, 1, 0.5)
cor(pa,pb)=-0.8
but when
pa=qbinom(a,10,0.5)
pb=qbinom(b,10,0.5)
cor(pa,pb) becomes -1 again
On Nov 30, 2012, at 1:05 PM, jaybell wrote:
sorry, I repost the question again
Why? This was already answered.
a=c(0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9)
b=c(0.9, 0.8, 0.7, 0.6, 0.5, 0.4, 0.3, 0.2, 0.1)
cor(a,b)= -1
pa=qbinom(a, 1, 0.5)
pb=qbinom(b, 1, 0.5)
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