Unfortunately, I have the same error message.
lapply(rowsplit, function(x)mean(x[,sapply(x, is.numeric)])) works but not
with median.
Strange, isn't it?
Any other idea?
Thanks in advance,
Ptit Bleu.
Henrique Dallazuanna wrote:
Try this:
lapply(l, function(x)median(x[,sapply(x,
You can provide a example of your data?
On Fri, Nov 7, 2008 at 9:14 AM, Ptit_Bleu [EMAIL PROTECTED] wrote:
Unfortunately, I have the same error message.
lapply(rowsplit, function(x)mean(x[,sapply(x, is.numeric)])) works but not
with median.
Strange, isn't it?
Any other idea?
Thanks in
I haven't looked at the detail, but I guess the answer is that mean works on
a data frame while median doesn't.
?mean
snip
For a data frame, a named vector with the appropriate method being applied
column by column.
-
I guess to use median you'll need nested '[l/s]apply's, the
Hello,
I have a list of data.frame
rowsplit : List of 15
$ (0,0.025] :'data.frame': 169 obs. of 7 variables:
$ (0.025,0.05]:'data.frame': 174 obs. of 7 variables:
$ (0.05,0.075]:'data.frame': 92 obs. of 7 variables:
$ (0.075,0.1] :'data.frame': 76 obs. of 7 variables:
$
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