Hi:
Here's one way:
apply(matrix(var.names, ncol = 2, byrow = TRUE), 1, function(x)
paste(x[1], x[2], sep = ','))
[1] a,b c,d e,f
HTH,
Dennis
On Wed, Nov 16, 2011 at 9:46 PM, B77S bps0...@auburn.edu wrote:
hi,
If i have a list of things, like this
var.names - c(a, b, c, d, e, f)
how can
On 17.11.2011 10:31, Dennis Murphy wrote:
Hi:
Here's one way:
apply(matrix(var.names, ncol = 2, byrow = TRUE), 1, function(x)
paste(x[1], x[2], sep = ','))
[1] a,b c,d e,f
Or for short and slightly faster for huge data use column-wise
operations as in:
apply(matrix(var.names, nrow=2),
hi,
If i have a list of things, like this
var.names - c(a, b, c, d, e, f)
how can i get this:
a, b, c, d, e, f
thanks ahead of time.
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