Hi
suppose I have a factor 'x':
x - as.factor(c(rep(a,3),b,d))
table(x)
x
a b d
3 1 1
But this is not what I want because
I need to include the fact that the count of c is zero.
I can't just change the levels of x:
levels(x) - c(a,b,c,d)
table(x)
x
a b c d
3 1 1 0
because this
On Tue, 2010-06-29 at 11:59 +0100, Robin Hankin wrote:
Hi
suppose I have a factor 'x':
x - as.factor(c(rep(a,3),b,d))
table(x)
x
a b d
3 1 1
But this is not what I want because
I need to include the fact that the count of c is zero.
I can't just change the levels of x:
You could try
x- factor(c(rep(a,3),b,d), levels=letters[1:4])
table(x)
# x
# a b c d
# 3 1 0 1
Hope this helps
Allan
On 29/06/10 11:59, Robin Hankin wrote:
Hi
suppose I have a factor 'x':
x - as.factor(c(rep(a,3),b,d))
table(x)
x
a b d
3 1 1
But this is not what I want because
I need
Just use factor(), not levels(); you can pass a factor to factor() too.
x - factor(c(rep(a,3),b,d), levels = letters[1:5])
table(x)
x
a b c d e
3 1 0 1 0
Cheers,
-Felix
On 29 June 2010 20:59, Robin Hankin rk...@cam.ac.uk wrote:
Hi
suppose I have a factor 'x':
x -
thanks everyone.
I think the motto should be always specify the levels of a factor when
you create it
if you possibly can.
best wishes
Robin
On 06/29/2010 12:39 PM, Felix Andrews wrote:
Just use factor(), not levels(); you can pass a factor to factor() too.
x-
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