TYPO on TYPO!
It should be X[,3]
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, Mar 31, 2016 at 9:47 AM, Bert Gunter wrote:
> Inline.
>
> B
Inline.
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Wed, Mar 30, 2016 at 5:37 PM, Ryan Utz wrote:
> Bill, Josh, and Bert,
>
> Thanks for your responses. I
Ryan,
>From "decompose()" source code, two conditions can trigger the error message:
"time series has no or less than 2 periods"
based on the frequency value, specifically:
1. f <= 1
2. length(na.omit(x)) < 2 * f
It appears to me that your reproducible code has got a typo error, it shou
decompose wants frequency(Y) to be more than 1 - it really wants an integer
frequency
so it can return a vector of that length containing the repeating pattern
(the "figure").
frequency(Y) is 1/3600 so you get the error (which might be better worded):
> plot(decompose(Y))
Error in decompose(Y
Bill, Josh, and Bert,
Thanks for your responses. I still can't quite get this when I use actual
dates. Here's an example of what is going wrong:
X=as.data.frame(1:6000)
X[2]=seq.POSIXt(ISOdate(2015,11,1),by='hour',length.out=6000)
X[3]=sample(100,size=6000,replace=T)
Y=xts(X[,3],order.by=X[,2])
You said you specified frequency=96 when you constructed the time
series, but when I do that the decomposition looks reasonable:
> time <- seq(0,9,by=1/96) # 15-minute intervals, assuming time unit is day
> measurement <- sqrt(time) + 1/(1.2+sin(time*2*pi)) +
rnorm(length(time),0,.3)
> plot(decomp
Sorry about not providing code; I didn't think to just simulate dummy code.
Here's a situation where I have <1 year of data, hourly time sampling, and
the error that I get using my actual data:
###
X=as.data.frame(1:6000)
X[2]=seq.POSIXt(ISOdate(2015,11,1),by='hour',length.out=6000)
X[3]=sample(
On Wed, Mar 30, 2016 at 10:29 AM, Bert Gunter wrote:
> I "think" the problem is that you failed to set the "frequency"
> attribute of your time series, so it defaults to 1. A time series with
> one observation per period cannot be decomposed, since the error term
> is confounded with the "seasonal
I "think" the problem is that you failed to set the "frequency"
attribute of your time series, so it defaults to 1. A time series with
one observation per period cannot be decomposed, since the error term
is confounded with the "seasonality", which is essentially your error
message.
Again, a guess
Code please.
Reproducible example?(e.g. 1st 100 values)
"PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code."
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticki
Hello,
I have a time series that represents data sampled every 15-minutes. The
data currently run from November through February, 8623 total readings.
There are definitely daily periodic trends and non-stationary long-term
trends. I would love to decompose this using basic time series analysis.
H
11 matches
Mail list logo
