[R] vlmc - In vlmc(traffic.clusters.stationary, cutoff = i) : alphabet with 1-letter strings; trying to abbreviate

2010-06-30 Thread Constantinos Antoniou
Dear all (copying the package author), I have a question on the vlmc package. I am trying to model a time series, where each element can take one of 11 values (the result of some clustering). When I run the following command (synthetic data to facilitate self-contained example) I get the

Re: [R] vlmc - In vlmc(traffic.clusters.stationary, cutoff = i) : alphabet with 1-letter strings; trying to abbreviate

2010-06-30 Thread Martin Maechler
CA == Constantinos Antoniou constantinos.antoniou.rli...@gmail.com on Wed, 30 Jun 2010 12:07:16 +0300 writes: CA == Constantinos Antoniou constantinos.antoniou.rli...@gmail.com on Wed, 30 Jun 2010 12:07:16 +0300 writes: CA Dear all (copying the package author), CA I have a

Re: [R] vlmc - In vlmc(traffic.clusters.stationary, cutoff = i) : alphabet with 1-letter strings; trying to abbreviate

2010-06-30 Thread Constantinos Antoniou
Dear Martin, Thank you very much for the (reassuring and helpful) response. Best regards, Costas On Jun 30, 2010, at 3:58 PM, Martin Maechler wrote: CA == Constantinos Antoniou constantinos.antoniou.rli...@gmail.com on Wed, 30 Jun 2010 12:07:16 +0300 writes: CA == Constantinos Antoniou