Hi again (, I am the PO from my own email account)
I agree that the word "basically" puts the NA issues aside. But my
point is that R subsetting behavior when there are NAs in a logical
index is quite tricky to say the less, and deserves the trouble of
pointing it out in every place it is
> peter dalgaard
> on Fri, 16 Nov 2018 13:39:27 +0100 writes:
> Well, "Basically, " is an excuse for not being
> accurate. Making the code more complex doesn't really help
> the explanation. It could be better to just add "(except
> for NA handling)" or so.
> -pd
Well, "Basically, " is an excuse for not being accurate. Making the code more
complex doesn't really help the explanation. It could be better to just add
"(except for NA handling)" or so.
-pd
> On 16 Nov 2018, at 11:08 , buzon informatica, ige
> wrote:
>
> The which() function help page
The which() function help page states that, in the default case, what the
function returns is:
" Basically, the result is (1:length(x))[x]."
That would only be true if there are not any NA values in x. I think it would
be more accurate to say:
"Basically, the result is (1:length(x))[!is.na(x) &
Hi Gafar,
As Jeff has pointed out, the median value may not exist within the
dataset. However, this function will give you either the position of
the value that is the median, or the position of the two closest
values if none equal the median. Be aware that this function may fall
victim to the
The median is not always a member of the data set. What do you really want?
I for one would want people to follow the guidance in the footer on every email
on this mailing list.
--
Sent from my phone. Please excuse my brevity.
On June 4, 2016 9:01:41 AM PDT, Gafar Matanmi Oyeyemi
Dear,
I need help on which.min and which.max. functions. Is there a function to
fetch me the point that in vector that gives median value such like the
commands for minimum and maximum values.
Thanks.
[[alternative HTML version deleted]]
__
Hi,
I am using 32-bit R v 2.15.1, on Mac OsX v 10.6.8 with R GUI 1.52 Leopard
build 32-bit (6188). I have also replicated this error on R 2.13.2 on a
windows 7 machine.
In some sequences of numbers, I am unable to use the which() function to
index certain values.It seems to be primarily
It looks like an example of FAQ 7.31 Why doesn't R think these numbers are
equal?
John Kane
Kingston ON Canada
-Original Message-
From: tomasb...@gmail.com
Sent: Wed, 15 Aug 2012 22:37:17 +1000
To: r-help@r-project.org
Subject: [R] which() function not finding certain numbers
FAQ 7.31
?is.equal
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Live: OO#..
On Wed, Aug 15, 2012 at 10:37:17PM +1000, Tom Bird wrote:
Hi,
I am using 32-bit R v 2.15.1, on Mac OsX v 10.6.8 with R GUI 1.52 Leopard
build 32-bit (6188). I have also replicated this error on R 2.13.2 on a
windows 7 machine.
In some sequences of numbers, I am unable to use the which()
Yes, the round(seq( )) sollution does it.
Many thanks to the sender of this (and other similar) solutions.
TB
On Thu, Aug 16, 2012 at 3:45 AM, Petr Savicky savi...@cs.cas.cz wrote:
On Wed, Aug 15, 2012 at 10:37:17PM +1000, Tom Bird wrote:
Hi,
I am using 32-bit R v 2.15.1, on Mac OsX v
Hi
I have data in the following format:
itemsperson1 person2
- - --
car honda,toyotahonda
bikesuzuki suzuki
pant Lee Levis, Lee
shirt Van_housen Hollister
house rented
Hello,
I have a simple question but I don't know which method is best to use for my
problem.
I have the following strings:
str1 - My_name_is_peter
str2 - what_is_your_surname_peter
I would like to apply predefined abbreviations for peter=p and name=n to
both strings
so that the new strings
On Oct 16, 2011, at 12:35 PM, syrvn wrote:
Hello,
I have a simple question but I don't know which method is best to
use for my
problem.
I have the following strings:
str1 - My_name_is_peter
str2 - what_is_your_surname_peter
I would like to apply predefined abbreviations for peter=p and
Hi,
thanks for the tip! I do it as follows now but I still have a problem I do
not understand:
abbrvs - data.frame(c(peter, name, male, female),
c(P, N, m, f))
colnames(abbrvs) - c(pattern, replacement)
str
Note that male comes before female in your data frame.
---
Jeff Newmiller The . . Go Live...
DCN:jdnew...@dcn.davis.ca.us Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer
On Oct 16, 2011, at 1:32 PM, Jeff Newmiller wrote:
Note that male comes before female in your data frame.
---
Jeff Newmiller The . . Go Live...
syrvn ment...@gmx.net wrote:
Hi,
thanks for the tip! I do it as
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David Winsemius
Sent: Sunday, October 16, 2011 1:59 PM
To: Jeff Newmiller
Cc: r-help@r-project.org; syrvn
Subject: Re: [R] Which function to use: grep, replace, substr etc
I have a matrix like this
0.05 0.13 1.2 0 0 0 0 0 red
0 0 0 0 0 0 0 0 white
0 0.06 0 0 0 0 0 0 blue
If only 1 number in the first 8 columns is more than 0, in a new variable I
write 1, if they're all 0 or less, I write 0, so
0.05 0.13 1.2 0 0 0 0 0 red 1
0 0 0
Hi all,
When I detect the spatial point pattern, I want to use the Cramer-von Mises
statistic to assess the curve-wise significance of deviations from null
hypotheses. Who can tell me which function in R package Spatstat can do
this work?
Thanks a lot
Jeff
[[alternative HTML version
Dear group,
Here is a list of elements :
l -
c(100415, 100416, 100419, 100420, 100421, 100422,
100423, 100426, 100427, 100428, 100429, 100430, 100503,
100504, 100505, 100506, 100507, 100510, 100511, 100512,
100513, 100514, 100517, 100518, 100519, 100520, 100521,
100524, 100525, 100526,
The correct line is :
l[(which(100420==l)-1):which(100420==l)]
[1] 100419 100420
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
Sent: Wednesday, June 02, 2010 9:41 AM
To: r-help@r-project.org
Cc: 'arnaud Gaboury'
Subject: which function
Dear group,
Hi Arnaud
Try this
l[((which(100420==l))-1):which(100420==l)]
Regards
Mo
arnaud Gaboury arnaud.gabo...@gmail.com a écrit :
Dear group,
Here is a list of elements :
l -
c(100415, 100416, 100419, 100420, 100421, 100422,
100423, 100426, 100427, 100428, 100429, 100430, 100503,
100504,
Hi,
Try with more parentheses:
l[((which(100420==l))-1):which(100420==l)]
[1] 100419 100420
It was interpreted as 4-(1:4)=3 2 1 0
Ivan
Le 6/2/2010 09:41, arnaud Gaboury a écrit :
Dear group,
Here is a list of elements :
l-
c(100415, 100416, 100419, 100420, 100421, 100422,
100423, 100426,
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