Thank you Petr!
On Tue, Jan 31, 2023 at 11:58 AM PIKAL Petr wrote:
> Hi Konstantinos
>
> Not exactly derivative but
> > diff(df[,2])
> [1] -0.01 -0.01 -0.01 -0.01 0.00 0.01 -0.02 -0.03 -0.02
>
> May be enaough for you.
>
> Cheers
> Petr
>
> >
> > -Original Message-
> > From: R-help
Hi Ivan!
Thank you for your valuable insights! I look forward to learning more about
numerical differentiation and about this subject.
The pracma package and the fornberg() function is impressive. I got some
really good approximations on my derivatives.
Thank you!
Kostas
On Tue, Jan 31, 2023
В Tue, 31 Jan 2023 11:16:21 +0200
konstantinos christodoulou
пишет:
> How can I find the derivatives of the atmospheric measurements at each
> altitude?
Welcome to the world of finite difference methods! If you can find a
good textbook on them, it may be a good idea to skim it.
Hi Konstantinos
Not exactly derivative but
> diff(df[,2])
[1] -0.01 -0.01 -0.01 -0.01 0.00 0.01 -0.02 -0.03 -0.02
May be enaough for you.
Cheers
Petr
>
> -Original Message-
> From: R-help On Behalf Of konstantinos
> christodoulou
> Sent: Tuesday, January 31, 2023 10:16 AM
> To:
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