Thank you very much everybody. That worked.
Dana
On Thu, Jan 28, 2010 at 12:23 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try this:
ong-reshape(as.data.frame(dataset), idvar=subject,
v.names=response, varying=list(2:5), direction=long)
or
dataset - cbind.data.frame(y1, y2, y3, y4)
Maybe that's a problem with the RSQLite package , probably detaching
the package help.
detach(package:RSQLite)
HTH, Christian
trying to structure sql to merge two datasets. structure follows:
dbs.possible.combos (all possible combinations of dates and places)
Date Place
1/1/10 N-01
1/1/10
Actually, better sql would likely be:
dbs.final - sqldf(select * from dbs.possible.combos left join
dbs.aggregate using (Date,Place))
but this still doesn't work
--
View this message in context:
http://n4.nabble.com/question-on-sqldf-syntax-tp1289707p1289718.html
Sent from the R help mailing
On 25 Jan., 20:26, GL pfl...@shands.ufl.edu wrote:
Actually, better sql would likely be:
dbs.final - sqldf(select * from dbs.possible.combos left join
dbs.aggregate using (Date,Place))
but this still doesn't work
I'd suspect name mangling to cause the problem:
On Mon, Jan 25, 2010 at 2:17 PM, GL pfl...@shands.ufl.edu wrote:
trying to structure sql to merge two datasets. structure follows:
dbs.possible.combos (all possible combinations of dates and places)
Date Place
1/1/10 N-01
1/1/10 S-02
1/2/10 N-01
1/2/10 S-02
etc...
dbs.aggregate (the
Perhaps using the R merge() function, possibly twice in succession,
will do the job. (merge() does a one to many relational join, but
with only two dataframes at at time).
Or, there is an R package that lets you use the SQL language on
dataframes. I don't recall its name, but a search on R
sqldf, authored by Gabor, if I read your intention correctly.
D.
On Fri, Jan 22, 2010 at 5:00 PM, Don MacQueen m...@llnl.gov wrote:
Perhaps using the R merge() function, possibly twice in succession, will do
the job. (merge() does a one to many relational join, but with only two
dataframes
ang-runif(20,0,2*pi)
x-cos(ang) +0.4
y-sin(ang) +0.8
plot(x,y,ylim=c(-3,3),xlim=c(-3,3))
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Wolfgang Amadeus
Sent: Wednesday, January 20, 2010 5:26 AM
To: r-help
Subject: [R] question on
Oops forgot to include the radius
ang-runif(200,0,2*pi)
x-cos(ang)*.1 +0.4
y-sin(ang)*.1 +0.8
plot(x,y)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Wolfgang Amadeus
Sent: Wednesday, January 20, 2010 5:26 AM
To: r-help
Subject:
Alfredo's solution will provide n (=200 in his case) points
uniformly distributed along the *circumference* of the circle.
Wolfgang_Amadeus(!), you wanted them *in* a circle.
If what you mean is uniformly distributed over the area within
the circle, then you also need to generate the radii at
You have redefined the plot function somewhere. Check your saved
environment.
mario
On 20-Jan-10 15:36, khaz...@ceremade.dauphine.fr wrote:
Hello all
My computer is MacBook and I want to draw a plot in R, for example for
x- c(1,3,6,9,12)
y- c(1.5,2,7,8,15)
I use
Ted, Alfredo, et al: Please stop doing this expletive deleted
jerk's homework for him!!!
cheers,
Rolf Turner
##
Attention:\ This e-mail message is privileged and confid...{{dropped:9}}
While I agree that this is someone's homework, it occur to me that we
can mess him up a little more.
He asked for 200 points *uniformly* distributed on (or in) a circle.
Well, he did NOT say uniform random distribution.
So in fact the plot, on a circle would be
theta -seq(0,2*pi, by =
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of hongwei
Sent: Wednesday, January 20, 2010 2:38 PM
To: r-help@r-project.org
Subject: [R] Question about many-to-one merge
I have spent a whole afternoon searching for the
On Jan 20, 2010, at 5:37 PM, hongwei wrote:
I have spent a whole afternoon searching for the solution, but got
nothing so
far. It should be a simple problem.
I have two datasets to merge. The first one just contains two ID
columns and
it looks like:
FromID ToID
1 2
1
Oh, yes, my bad. Merge works! I guess the reordering automatically made by
Merge made me confused.
I wrote my code using Merge several months ago, and just didn't feel it
right today.
Thanks anyway!
--
View this message in context:
btw, the re-order and swap make it much clearer, so thanks again!
--
View this message in context:
http://n4.nabble.com/Question-about-many-to-one-merge-tp1018811p1037860.html
Sent from the R help mailing list archive at Nabble.com.
__
On Jan 20, 2010, at 11:10 PM, Erin Hodgess wrote:
Dear R People:
I'm sure that this is a very silly question, but I'm reading the
Software for Data analysis book by John Chambers, and I can't find the
Declination data that he refers to on page 15 in the book.
I did all of the usual stuff:
On Jan 19, 2010, at 10:21 AM, khaz...@ceremade.dauphine.fr wrote:
--
Hello all
My computer is MacBook and I want to draw a plot in R, for example for
x - c(1,3,6,9,12)
y - c(1.5,2,7,8,15)
I use this command plot(x,y).
Hello,
parse just parse the text into an expression.
parse(text=a-a*10; b-2:6)
expression(a-a*10, b-2:6)
attr(,srcfile)
text
If you want to evaluate the expression, you need to call eval
y - within(x, eval(parse(text=a-a*10; b-2:6)))
y
a b
1 10 2
2 20 3
3 30 4
4 40 5
5 50 6
Or you can
Dear Gabor Henrique,
Thanks for your suggestions on the above problem. The following is more
traditional and unfanciful but it works. Suitable for a prodige like myself...
m - matrix(1:3,3,3)
x1 - list(m, m+1, m+2, m+3, m+4)
out - list()
for (i in 1:4){
t[[i]] - Reduce(+, x1[c(i:i+1)])
}
That gives an error when I run it. I think you want this:
m - matrix(1:3,3,3)
x1 - list(m, m+1, m+2, m+3, m+4)
out - list()
for(i in 1:4) out[[i]] - (x1[[i]] + x1[[i+1]]) / 2
On Thu, Jan 7, 2010 at 12:28 PM, Muhammad Rahiz
muhammad.ra...@ouce.ox.ac.uk wrote:
Dear Gabor Henrique,
Thanks
Yes, should be
1. out[[i]], instead of t[[i]].
2. x1[c(i:(i+1))] # For this case, I was trying out the rolling sum.
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Stephan, Patrick Carl,
Thanks very much for your help...and during the holidays no less!
Putting my function within a try() worked perfectly!!
Happy New Year,
Stephanie
On Sat, Dec 26, 2009 at 1:38 PM, Stephan Kolassa stephan.kola...@gmx.de wrote:
Hi Stephanie,
it sounds like R's exception
Thanks Gabor,
It works alright. But is there alternative ways to perform rollmean
apart from permutating the data?
Possibly combining the Reduce and rollmean functions?
The easiest but traditional way is
(x[[1]]+x[[2]]) / 2
(x[[2]]+x[[3]]) / 2
Muhammad Rahiz | Doctoral Student in
This is due to the non-idempotent nature of apply. Instead of apply,
you can use
- aaply in the plyr package
http://tolstoy.newcastle.edu.au/R/devel/06/06/5687.html
- or the idempotent apply (iapply) posted here by Hadley Wickham:
and in either case you won`t have to permute the result.
For this example try this:
lapply(lapply(list('head', 'tail'), do.call, list(x, n = -1)),
function(x)Reduce('+', x)/2)
On Mon, Jan 4, 2010 at 1:54 PM, Muhammad Rahiz
muhammad.ra...@ouce.ox.ac.uk wrote:
Thanks Gabor,
It works alright. But is there alternative ways to perform rollmean apart
Here is a variation which also uses head and tail:
mapply(function(x, y) (x + y)/2, tail(x, -1), head(x, -1), SIMPLIFY = FALSE)
On Mon, Jan 4, 2010 at 12:37 PM, Henrique Dallazuanna www...@gmail.com wrote:
For this example try this:
lapply(lapply(list('head', 'tail'), do.call, list(x, n =
Dear M.Rahiz,
Unfortunatelly I can't reproduce your example.
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
bests
milton
On Sat, Jan 2, 2010 at 9:26 AM, Muhammad Rahiz muhammad.ra...@ouce.ox.ac.uk
wrote:
Hello useRs,
Let me rephrase;
Given x as
x
[[1]]
V1 V2 V3
[1,] 1 1 1
[2,] 2 2 2
[3,] 3 3 3
[[2]]
V1 V2 V3
[1,] 4 4 4
[2,] 5 5 5
[3,] 6 6 6
[[3]]
V1 V2 V3
[1,] 7 7 7
[2,] 8 8 8
[3,] 9 9 9
I'd like to calculate the moving average (interval = 2) i.e.
( x[[1]] + x[[2]] )
Try apply:
library(zoo) # rollmean
# test data
m - matrix(1:3, 3, 3)
x - list(m, m+3, m+6)
# convert to array
a - array(unlist(x), c(3, 3, 3)); a
# apply rollmean and permute to desired form
aa - apply(a, 1:2, rollmean, k = 2)
aperm(aa, c(2, 3, 1))
The last line outputs:
aperm(aa, c(2, 3,
Hi Stephanie,
it sounds like R's exception handling may help, something like this:
foo - try(eblest(i, dir5, sterr5, weight5, aux5))
if ( class(foo) == try-error ) next
Take a look at ?try.
HTH,
Stephan
Stephanie Coffey schrieb:
Hi all,
I'm running R version 2.9.2 on a PC.
I'm having a
Sounds like what you want is either try() or trycatch() -- check out
the documentation. Basically, putting your eblest() function inside a
try() call allows you to return an error message if eblest crashes
without crashing your main loop.
BTW, for debugging purposes, I'd recommend
Waverley @ Palo Alto wrote:
Hi,
I have a list of IPI gene IDs. I want to find out whether there is a
package which can map the gene ontology to these IPIs, and plot the
pie chart to demonstrate the molecular function distributions.
The input is like the following gene IPI IDs:
, December 21, 2009 2:31:26 PM
Subject: Re: [R] Question About Repeat Random Sampling from a Data Frame
On Dec 21, 2009, at 1:01 PM, Bert Gunter wrote:
Didn't read this thread in detail, so the following suggestion may just be
nonsense... (caveat emptor), but:
To sample from an data frame
On Mon, Dec 21, 2009 at 4:12 PM, Adam Carr adamlc...@yahoo.com wrote:
Good Morning:
I've read many, many posts on the r-help system and I feel compelled to
quickly admit that I am relatively new to R, I do have several reference
books around me, but I cannot count myself among the fortunate
On Dec 21, 2009, at 10:12 AM, Adam Carr wrote:
Good Morning:
I've read many, many posts on the r-help system and I feel compelled
to quickly admit that I am relatively new to R, I do have several
reference books around me, but I cannot count myself among the
fortunate who seem to strong
the time to respond. The discussion and suggestions are
very helpful.
Adam
From: David Winsemius dwinsem...@comcast.net
Cc: r-help@r-project.org
Sent: Mon, December 21, 2009 11:23:43 AM
Subject: Re: [R] Question About Repeat Random Sampling from a Data Frame
On Dec 4, 2009, at 9:02 AM, khaz...@ceremade.dauphine.fr wrote:
Hi
I want to generate from invers gamma distribution truncated but when
I use
the rinvegamma() function, the system can not find this function.
Is ther someone to help me please?
Check your spledding.
thanks
soleiman
Stephanie Cooke wrote:
Is there a place to find the code for R functions like lsoda? Thanks
Yes, all code is in the source version of the package that contains that
function.
Best,
Uwe Ligges
__
R-help@r-project.org mailing list
Yep! just do
RSiteSeqarch(lsoda)
-Ista
On Thu, Dec 3, 2009 at 5:26 PM, Stephanie Cooke
cooke.stepha...@gmail.com wrote:
Is there a place to find the code for R functions like lsoda? Thanks
__
R-help@r-project.org mailing list
http://search.r-project.org/cgi-bin/namazu.cgi?query=lsodamax=100result=normalsort=scoreidxname=functionsidxname=Rhelp08idxname=views
On Dec 3, 2009, at 5:26 PM, Stephanie Cooke wrote:
Is there a place to find the code for R functions like lsoda? Thanks
As Ben Bolker has indicated, I am working on various improvements to the
functionality of optim() along with others, esp. Ravi Varadhan and Kate
Mullen.
With relevance to the posts by Sebastien Bihorel and Ben Bolker about
output of point/function value information on each evaluation, I am
Have you searched your computer?
Rhome/library/splines
It's one of the packages automatically installed with R.
-Peter Ehlers
Alan Swanson wrote:
Dear R gurus,
I am using the gbm library under R version 2.10.0, which depends on the
splines library. I have searched the various repositories
On Nov 30, 2009, at 6:47 PM, Alan Swanson wrote:
Dear R gurus,
I am using the gbm library under R version 2.10.0, which depends on
the splines library. I have searched the various repositories and
can't seem to locate any current version of the splines library.
This is strange because
Phil and Peter, thanks - figured it was something obvious. I had
uninstalled splines to check the behavior of some other code. I just
reinstalled R 2.10.0 and it shows up. Thanks! Alan
Peter Ehlers wrote:
Have you searched your computer?
Rhome/library/splines
It's one of the packages
Sébastien Bihorel pomchip at free.fr writes:
Dear R-users,
I am trying to port to R something that I wrote in Matlab to perform model
parameter optimization using the Nelder-Mead simplex method (fminsearch). I
read the help on ?optim (which seems to be the way to go) as well as a bunch
Hi all,
I am encountering the same error Error in if (any(co)) { : missing value
where TRUE/FALSE needed
when i run:model - svm(databctrain, classesbctrain)
I am not sure what this error means . is it some problem with the dataset ?
Could i get some help ?
Thanks,
Akshatha
losemind wrote:
On Nov 25, 2009, at 7:54 PM, akal wrote:
Hi all,
I am encountering the same error Error in if (any(co)) { : missing
value
where TRUE/FALSE needed
when i run:model - svm(databctrain, classesbctrain)
I am not sure what this error means . is it some problem with the
dataset ?
How do you
PS. All class names were upper-case, I messed up while copying the
code, but it has no effect on the result. Thanks for help.
--Hun
On Mon, 23 Nov 2009 10:28:37 +0100 Hun S. Tesatte
hunsynte...@hush.com wrote:
Dear R-ers,
I don't understand the following, maybe someone will help me
explain:
## You can do this with the qr functions.
tmp - rnorm(4)
tmp.qr - qr(tmp)
tmp.complete - qr.Q(tmp.qr, complete=TRUE)
tmp.complete[,1] / tmp
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Copied form the R-help messages' footer:
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Uwe Ligges
Waverley @ Palo Alto wrote:
Hi,
I am using the function heatmap(stats) to draw a microarray
You should be able to do this effectively in 1 line:
my.data - lapply( paste( 'data', 1:N, '.dat', sep='' ), read.table )
Then everything is in my.data, if you want them named then do a second line:
names(my.data) - paste( 'data', 1:N, '.dat', sep='' )
Doing the same analysis on each dataset
The first step is to make Weather a factor. Then the levels would be displayed
in the strip labels.
The second step would be to change the level values to the actual strings
you want to see.
tmp - data.frame(Weather=1:3, x=rnorm(3), y=rnorm(3))
xyplot(y ~ x | Weather, data=tmp)
tmp$Weather -
Tena koe Jeff
Try something like:
for (i in 1:n)
{
assign(paste('data', i, sep=''), read.table(paste('data', i, '.dat',
sep=''), header=F))
.
.
.
}
HTH
Peter Alspach
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf
On Mon, 02 Nov 2009 06:29:54 -0500 Phil Smith
philipsm...@alumni.albany.edu wrote:
I want to take the difference in two dates:
dt2 - dt1.
But, I want the answer in months between those 2 dates.
What do you mean by 'months'? The number of days in a month vary, so the
number of months
Since months have different lengths the difference in months is not
well defined but lets define it as the difference between the first of
the month of two dates. In that case we can use as.yearmon of the zoo
package. It converts to year/months, dropping days, using an internal
representation of
On Mon, 2 Nov 2009, Phil Smith wrote:
Hi R Community:
I want to take the difference in two dates:
dt2 - dt1.
But, I want the answer in months between those 2 dates.
Can you advise me?
How long is a month?
difftime() can give you an answer in days, which might suffice if you
define a
On Thu, 29 Oct 2009 11:45:19 -0500 David Kaplan
dkap...@education.wisc.edu wrote:
asd[is.na(asd)] - mean(asd,na.rm=TRUE)
This has worked quite well in the past. Now, however, I am getting the
following error messsage.
Error in `[-.data.frame`(`*tmp*`, is.na(asd), value =
On Thu, 29 Oct 2009 18:12:34 +0100 Karl Ove Hufthammer k...@huftis.org
wrote:
rhs is the wrong length for indexing by a logical matrix
An inspection of the data set reveals no value of the sort give above.
Any thoughts?
I would venture to guess that your 'asd' object is not of the
On Wed, Oct 21, 2009 at 11:06 AM, Peter Flom
peterflomconsult...@mindspring.com wrote:
...
I have a longitudinal data set, with data on schools and their test scores
over a four year period. I have centered year, and run the following
m1.mod1 - lme(fixed = math_1 ~ I(year-2007.5)*TFC_,
Lucky Strike wrote:
hi everybody, I'm a student, and I'm new using R!
I'm looking for statistical
help hoping somebody can answer me!
This is my problem:
I have 2 temporal
series. The firstone is a series of mesured data (height of monitorated
points), the second is a series
On Oct 1, 2009, at 4:33 AM, hassan paylakhi wrote:
hi
I am going to crazy.I want to use beadarray package in R, but I cant.
when I want install it, I encounter to this message Loading required
package: hwriter
Loading required package: sma
Error in library(pkg, character.only = TRUE,
hassan paylakhi wrote:
hi
I am going to crazy.I want to use beadarray package in R, but I cant.
when I want install it, I encounter to this message Loading required
package: hwriter
Loading required package: sma
Error in library(pkg, character.only = TRUE, logical.return = TRUE, lib.loc
=
Sunghee Kim sunghee0701 at gmail.com writes:
Dear All,
As you know, glmmADMB package use ML method for estimation.
Is it possible to use REML estimation method for zero-inflated Poisson
distribution?
For ML method,
poi_ML - glmm.admb(los ~ psihigh + trt.mod + trt.high +
The suggestions from others to use lattice's xyplot, or ggplot2 are good.
If you want an explicit loop you can do something like:
for ( nm in unique(mydat$Name) ) {
with( subset( mydf, Name==nm) ,
{
plot(Time, Value, title=nm)
readline('CR to continue ')
}
)
}
At
Chris Li wrote:
Hi all,
I am new to R and I have got a question in regards to factors.
Say I have a simple dataset like the following:
Name Time Value
a 1:00 1.25
a 2:00 1.26
b 1:00 1.29
b 2:00 1.28
c 1:00 1.21
On Mon, Sep 14, 2009 at 5:19 AM, Schalk Heunis
schalk.heu...@enerweb.co.zawrote:
Chris
try this (assume your dataset is in a dataframe called ms):
library(lattice)
xyplot(Value~Time|Name,data = ms)
HTH
Schalk
On Mon, Sep 14, 2009 at 2:19 AM, Chris Li chri...@austwaterenv.com.auwrote:
A parametric version is:
require(Design)
dd - datadist(predprob); options(datadist='dd')
f - lrm(event ~ rcs(qlogis(predprob), 3))
plot(f, predprob=NA, fun=plogis)
Frank
Noah Silverman wrote:
Hello,
Frank was nice enough to point me to the val.prob function of the Design
library.
It
Thanks Frank,
Two quick questions:
1) I see you calculating datadist, but then not using it in the
subsequent entries. Is that for a different application.
2) I'm less concerned with plotting than the values that were plotted.
As mentioned in my original message, The line plotted from the
Noah Silverman wrote:
Thanks Frank,
Two quick questions:
1) I see you calculating datadist, but then not using it in the
subsequent entries. Is that for a different application.
That's just to set default plotting limits.
2) I'm less concerned with plotting than the values that were
[cc'd to list]
You may need
coda::HPDinterval(as.mcmc(fit),prob=0.9)
SATRAJIT ROYCHOUDHURY wrote:
Dear Ben,
coda::HPDinterval(fit,prob=0.9)
This command is keep giving me error message as;
Error in HPDinterval(fit) : no applicable method for HPDinterval
Can you pls tell me what
coda::HPDinterval(fit,prob=0.9)
SATRAJIT ROYCHOUDHURY-2 wrote:
Dear
I am trying to find a 90% credible interval. I am using the following
code.
fit-bugs(
model.file=BUGScode,
data=data,
inits = list(geninits1,geninits2),
parameters.to.save=keepers,
On Aug 5, 2009, at 5:45 PM, Noah Silverman wrote:
In my continuing quest to generate some summary data, I've come
across some useful suggestions in pasts posts.
The apply operation returns an error, and I can't figure out why.
Can someone help me fix this?
testlogdata - cbind(testlogdata,
Hello,
Isn't it totally counter-intuitive that if you penalize the error less
the tree finds it?
See:
experience - as.factor(c(rep(good,90), rep(bad,10)))
cancel - as.factor(c(rep(no,85), rep(yes,5),
rep(no,5),rep(yes,5)))
foo - function( i ){
tmp - rpart(cancel ~ experience,
Hello,
If you do
my.tree - rpart(cancel ~ experience)
and then you check
my.tree$frame
you will note that the complexity parameter there is 0.
Check ?rpart.object to get a description of what this output means. But
essentially, you will not be able to break the leaf unless you set a
2009/7/27 Robert Smith robertpsmith2...@gmail.com
Hi,
I am using rpart decision trees to analyze customer churn. I am finding
that
the decision trees created are not effective because they are not able to
recognize factors that influence churn. I have created an example situation
below.
: |
|
|
|Re: [R] Question regarding sqldf
|
|
|
| Subject: |
|
|
|Re: [R
Hi Rizzi,
how about a reproducible example/data.frame?
:-)
milton
On Thu, Jul 30, 2009 at 1:46 PM, rizzo.mich...@epamail.epa.gov wrote:
Hello,
I am having a problem using sqldf. I'm trying to choose a subset of
observations from a data set based on the date and maximum value of a
: |
|
|
|Re: [R] Question regarding sqldf
How about update R/sqldf?
require(sqlf)
Loading required package: sqlf
Warning message:
In library(package, lib.loc = lib.loc, character.only = TRUE, logical.return
= TRUE, :
there is no package called 'sqlf'
testframe-data.frame(sdate=rep(paste
+
I just answered essentially the same question from another person offline
within the last day. Anyways:
Date class variables are stored as numbers, i.e. days since
the Epoch, in R and when transferred to sqlite get transferred
as numbers. Try this:
library(sqldf)
DF - data.frame(a =
Thanks a lot for the reply.
1. How I compare the lars v.s. lm
Your understand is correct.
2. Answer to my question.
I guess in each step of lars, the coeff are not the same as the lm function
returns using the same model, because the coeff of lars are the
accumulated steps towards the
Hi,
On Jul 22, 2009, at 6:18 PM, lulu9797 wrote:
The returned values of lars function include R squares along the
variable
selection path.
Correct.
However, such values are always slightly different from the
R squares returned by the regression function lm using the same
models.
try this,
library(ggplot2)
ggplot() + geom_histogram(aes(x=rnorm(100), fill=..count..))+
xlab(NULL)+
scale_y_continuous()+
opts(legend.position=none)
HTH,
baptiste
2009/7/22 RON70 ron_michae...@yahoo.com
I have following code on qplot :
library(ggplot2)
ggplot() +
VG == Vikneswaran Gopal vikn...@stat.ufl.edu
on Fri, 17 Jul 2009 08:51:55 -0700 writes:
VG It usually gets uploaded within a day if it passes all
VG the checks run by Kurt Hornik. Then the Windows version
VG gets built within the next 24 hours as well. Vik Jim
usually, yes
hey,
On Sat, Jul 18, 2009 at 01:52:34AM -0700, RON70 wrote:
Hi, suppose I have following codes :
library(zoo); library(ggplot2)
dat - matrix(rnorm(500*2), 500); dat - zooreg(dat, start =
as.Date(01/01/01, %m/%d/%y), frequency=1); plot(dat)
head(dat); month.no - format(index(dat), %m);
the plots I am getting is here :
http://www.2shared.com/file/6739681/d4c6c9d3/plot.html
and
http://www.2shared.com/file/6739673/bd50b430/plot.html
How you are getting transposed one?
smu-2 wrote:
hey,
On Sat, Jul 18, 2009 at 01:52:34AM -0700, RON70 wrote:
Hi, suppose I have following
Although there is no explicit support for ggplot2 in zoo
currently (hopefully there will be in the future) both your
qplot commands do work for me using:
packageDescription(ggplot2)$Version
[1] 0.8.3
packageDescription(zoo)$Version # devel version
[1] 1.6-0
R.version.string # Windows Vista
[1]
Also get the expected behavior with:
R version 2.9.1 Patched (2009-07-04 r48897)
x86_64-apple-darwin9.7.0 #run as 64-bit GUI version under Mac OX X
10.5.7
ggplot2_0.8.2 #installed as CRAN binary
zoo_1.5-5 #imstalled as CRAN binary
chron_2.3-30
lattice_0.17-25
--
DW
On Jul 18,
I have updated the ggplot2 package as well as R, how got some new error.
qplot(x, z)
Error in get(new, env = FacetGrid, inherits = TRUE)(FacetGrid, ...) :
could not find function is.formula
I cannot understand what is happening with my system. Here I am providing
the details of my system
When I try:
?is.formula
I find that that one version is in package plyr. Perhaps you did not
install the dependencies for ggplot2, or they weren't loaded?
sessionInfo() ## ?
--
DW.
sessionInfo()
R version 2.9.1 Patched (2009-07-04 r48897)
x86_64-apple-darwin9.7.0
locale:
Suggest you update everything. Your ggplot2 is still not the most
recent. Use the Packages | Update Packages menu and then
try again.
On Sat, Jul 18, 2009 at 2:32 PM, RON70ron_michae...@yahoo.com wrote:
I have updated the ggplot2 package as well as R, how got some new error.
qplot(x, z)
Ah..now it is working as expected :) Package plyr was not loaded
automatically. Is it a bug for ggplot2? All other dependencies like proto,
grid, and reshape are loaded automatically.
Thanks,
David Winsemius wrote:
When I try:
?is.formula
I find that that one version is in
On Jul 18, 2009, at 3:13 PM, RON70 wrote:
Ah..now it is working as expected :) Package plyr was not
loaded
automatically. Is it a bug for ggplot2? All other dependencies
like proto,
grid, and reshape are loaded automatically.
Before throwing in the bug flag, you should start a
It usually gets uploaded within a day if it passes all the checks run by
Kurt Hornik. Then the Windows version gets built within the next 24
hours as well. Vik Jim Lemon wrote:
Gates, Michael wrote:
...
Members,
I recently submitted my first package to the submissions ftp site on
Gates, Michael wrote:
...
Members,
I recently submitted my first package to the submissions ftp site on CRAN
(7.3.09). The package has remained on the server since with no action? Do
package review/updates occur monthly? When I submitted, I sent an email to CRAN
to let them know about the
Gates, Michael wrote:
Members,
I recently submitted my first package to the submissions ftp site on CRAN
(7.3.09). The package has remained on the server since with no action? Do
package review/updates occur monthly? When I submitted, I sent an email to
CRAN to let them know about the
Kurt Hornik is currently out of office and will be back soon.
Moreover, CRAN was also unmanned in repspect to all other issues since
all other CRAN maintainers have been attending useR! and/or DSC conferences.
Just a bit more patience, CRAN will be in regular duty soon.
Best,
Uwe Ligges
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