Hello,
If you mean replacing 0 by the average of non-zero values, I guess one way is:
a[a==0] - mean(a[a!=0])
Maybe some senior user might correct it.
Regards,
Pascal
On 6 February 2014 12:05, ce zadi...@excite.com wrote:
Dear all,
My data is :
a -
You seem to be treating zeroes as unknown values. Perhaps you should consider
setting them to NA and using the na.approx function from the zoo package.
---
Jeff NewmillerThe . . Go
proposed na.approx function , I didn't know it, looks promising , I will
look into it .
ce
-Original Message-
From: Pascal Oettli [kri...@ymail.com]
Date: 02/05/2014 10:20 PM
To: ce zadi...@excite.com
CC: r-help r-help@r-project.org
Subject: Re: [R] replacing zeros with above/below numbers
Yes , indeed this is what I am looking for :
a[ a == 0.0 ] = NA
na.approx(a,na.rm=FALSE)
Thanks a lot.
-Original Message-
From: Jeff Newmiller [jdnew...@dcn.davis.ca.us]
Date: 02/05/2014 10:35 PM
To: ce zadi...@excite.com, r-help@r-project.org
Subject: Re: [R] replacing zeros
HI,
May be this helps:
a1 -a
indx - which(c(0,diff(a!=0)) 0)
indx1 - which(c(0,diff(a!=0)) 0)
a[a==0] - rep( rowMeans(cbind(a[indx-1],a[indx1])),indx1-indx)
a
# [1] 0.97210 0.97220 0.97300 0.97230 0.97145 0.97145 0.97145 0.97060 0.96980
#[10] 0.97040 0.97100 0.96990
#Another option is
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