on 01/16/2009 02:20 PM VanHezewijk, Brian wrote:
I've recently encountered an issue when trying to use the predict.glm
function.
I've gotten into the habit of using the dataframe$variablename method of
specifying terms in my model statements. I thought this unambiguous
notation would
On Jan 16, 2009, at 4:30 PM, Marc Schwartz wrote:
on 01/16/2009 02:20 PM VanHezewijk, Brian wrote:
I've recently encountered an issue when trying to use the predict.glm
function.
I've gotten into the habit of using the dataframe$variablename
method of
specifying terms in my model
Hello everyone!
I'm kind of a new R user and I'm trying to store several arima models (as
arima models not as lists) in something (vector, matrix, whatever)... i've
tried several things but nothing seems to work the way I need. Ideally I
need a vector (or something) whose entries are Arima
on 01/16/2009 03:44 PM David Winsemius wrote:
On Jan 16, 2009, at 4:30 PM, Marc Schwartz wrote:
on 01/16/2009 02:20 PM VanHezewijk, Brian wrote:
I've recently encountered an issue when trying to use the predict.glm
function.
I've gotten into the habit of using the
Does a list of arima models help?
foo - list()
foo[[1]] - arima(...)
foo[[2]] - arima(...)
HTH,
Stephan
diego Diego schrieb:
Hello everyone!
I'm kind of a new R user and I'm trying to store several arima models (as
arima models not as lists) in something (vector, matrix, whatever)... i've
On Fri, Jan 16, 2009 at 3:31 PM, Mattias Brännström
mattias.brannst...@tt.luth.se wrote:
Thank you, David!
I agree and apprechiate your analysis, which definitely will influence my
analysis of this data, but still I would like you to disregard from it(!)
The standard routine in the field is,
On Sat, Jan 17, 2009 at 12:27 AM, Göran Broström
goran.brost...@gmail.com wrote:
On Fri, Jan 16, 2009 at 3:31 PM, Mattias Brännström
mattias.brannst...@tt.luth.se wrote:
Thank you, David!
I agree and apprechiate your analysis, which definitely will influence my
analysis of this data, but
Thanks to Michael for giving a nice solution to Karl's question .
This identified a bug in the psych package winsor function which has
now been fixed in version 1.0.63. (The current development version).
Although my winsor.means function in 1.0..62 (and ealier) worked
correctly, my winsor
Hi,
I have a problem with the R syntax.
It's perhaps pretty simple, but I don't understand it ...
I can extract a column from a data.frame with the following code for
example ...
b$row1[b$row1 == male]
so I see all male-entries.
But I cannot extract all lines of a data.frame depending
You are missing a comma. You are addressing the dataframe as if it
were a matrix and you want to extract all the rows that match:
only.male - b[b$row1 == male,]
On Fri, Jan 16, 2009 at 9:57 PM, Jörg Groß jo...@licht-malerei.de wrote:
Hi,
I have a problem with the R syntax.
It's perhaps
Hi,
I have this variable;
x - c(test_01.log)
and I want to extract the number (01) out of the variable.
So that I get;
x
[1] 1
I tried strsplit, but I don't know how to refer to the result.
Can someone help me with that?
[[alternative HTML version deleted]]
Dear Jörg,
Try this:
gsub(^.*['_']|[.].*$, , test_01.log)
[1] 01
as.numeric(gsub(^.*['_']|[.].*$, , test_01.log))
[1] 1
HTH,
Jorge
On Fri, Jan 16, 2009 at 11:00 PM, Jörg Groß jo...@licht-malerei.de wrote:
Hi,
I have this variable;
x - c(test_01.log)
and I want to extract the
The first one replaces non-numerics with the empty string
and the second one returns numerics directly:
gsub([^0-9], , test_01.log)
# or
library(gsubfn)
strapply(test_01.log, [0-9]+)[[1]]
On Fri, Jan 16, 2009 at 11:00 PM, Jörg Groß jo...@licht-malerei.de wrote:
Hi,
I have this variable;
x
Dear all,
I want to see the source codes for dchisq(x, df, ncp=0, log = FALSE),
but cannot find it.
I input dchisq in the R interface, and then enter, the following message
return:
dchisq
/*/
function (x, df, ncp = 0, log = FALSE)
{
if
101 - 114 of 114 matches
Mail list logo
