Andrea Franceschini wrote:
I ask the question also because I found this line in Wikipedia:
The test (see above) based on the hypergeometric distribution
(hypergeometric test) is identical to the corresponding one-tailed
version of Fisher's exact test.
Is this wrong ? May I kindly ask a
Colleagues,
I am using nls successfully (2.11.1, OS X) but I am having difficulties
retrieving part of the output - residual sum of squares. I have assigned the
output to FIT:
FIT
Nonlinear regression model
model: NEWY ~ PMESOR + PAMPLITUDE * cos(2 * pi * (NEWX - POFFSET)/PERIOD)
On Fri, Aug 13, 2010 at 5:21 PM, Dennis Fisher fis...@plessthan.com wrote:
Colleagues,
I am using nls successfully (2.11.1, OS X) but I am having difficulties
retrieving part of the output - residual sum of squares. I have assigned the
output to FIT:
FIT
Nonlinear regression model
Hi, Dennis,
Does this give what you want?
sum(resid(FIT)^2)
Jun
Senior Pharmacokineticist
Seventh Wave Labs
On Fri, Aug 13, 2010 at 4:21 PM, Dennis Fisher fis...@plessthan.com wrote:
Colleagues,
I am using nls successfully (2.11.1, OS X) but I am having difficulties
retrieving part of the
On Fri, Aug 13, 2010 at 5:32 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Fri, Aug 13, 2010 at 5:21 PM, Dennis Fisher fis...@plessthan.com wrote:
Colleagues,
I am using nls successfully (2.11.1, OS X) but I am having difficulties
retrieving part of the output - residual sum of
Hello all,
due to unexplained differences between statistical results from
collaborators and our lab that arose in the same large proteomics
dataset we reevaluated the t.test() function. Here, we found a weird
behaviour that is also reproducible in the following small test
dataset:
Hello,
I need to plot the means of some outcome for two groups (control vs
intervention) over time (discrete) on the same plot, for various subsets
such as gender and grade level. What I have been doing is creating all
possible subsets first, using the aggregate function to create the means
over
Installing rJava fails consistently, whether installed via
the command line as below, or through install.packages(
'rJava' ), and whether 0.84 or 0.85 is used, with the
message :-
checking JNI data types... configure: error: One or more
JNI types differ from the corresponding native type. You may
Thanks for the clear example. However, if there is a bug it is only that
t.test.formula doesn't throw an error when given the paired=TRUE option.
The documentation says The formula interface is only applicable for the 2-sample
tests., but there probably should be an explicit check -- I
Thank you for the fast reply! Although I have read the help page for
t.test over and over again I have obviously overlooked the relevant
sentence. The workaround that I have planned seems to be the
correct use.
Thanks again,
J. W. D.
At 15:31 Uhr -0700 13.08.2010, Thomas Lumley wrote:
I think it would be helpful if you could clarify youre question - do you want
distinct sets - maybe use
unique()
but why (5,20) when its (5,10) in the row in youre example? What criteria do
you want the function to select the sets by and what kind of output do you
need?
Maybe it's just me
I too think I worded it incorrectly...
so the second two columns of the matrix are the start and end of an interval
however, because some of the intervals overlap, I want to limit the number
of intervals I have to deal with.
So therefore,
(5 10)should merge with(7 18) making
I figured it out myself, here it is: control=rpart.control(cp=.001))
Thank you!
On Fri, Aug 13, 2010 at 12:58 PM, Olga Shaganova olga.sha...@gmail.comwrote:
My decision tree grows only with one split and based on what I see in
E-Miner it should split on more variables. How can I adjust
Neither you nor your responder have continued the eamil chain very
well so let me put things back together:
on Aug 13, 2010; 03:54pm fishkbob wrote subj = merge function in R?
So I have a bunch of c(start,end) points and want to consolidate
them into as few c(start,end) as possible.
For
Other terms for Kalman filtering, prediction and smoothing are
state space modeling and dynamic linear models.
Consider the following extension of Ben Bolker's suggestion to
use the 'sos' package:
library(sos)
k - ???Kalman
ss - findFn('state space')
dlm - findFn('dynamic
Hi Thomas,
I'm not too sure about your interpretation. Consider:
set.seed(54321)
X - rnorm(10) ; Y - rnorm(10)
XY - c(X,Y); group-c(rep(0,10),rep(1,10))
t.test(X,Y,paired=TRUE)
# Paired t-test
# data: X and Y
# t = -1.5265, df = 9, p-value = 0.1612
# 95 percent
(Ted Harding) wrote:
Johannes' original query was about differences when there
are NAs, corresponding to different settings of na.action.
It is perhaps possible that 'na.action=na.pass' and
'na.action=na.exclude' result in different pairings in the
case paired=TRUE. However, it seems to me
I have a plot produced by function bplot (package = rms) that is
really a lattice plot (class=trellis). It is similar to this plot
produced by a very minor modification of the first example on the
bplot help page:
requiere(rms)
n - 1000# define sample size
set.seed(17) # so can
Please,when i export the output from R to excel.I am not getting all the
15,000 observations but only 2000.Thank you
--
View this message in context:
http://r.789695.n4.nabble.com/help-tp2323542p2324459.html
Sent from the Export many data to Excel 2007 mailing list archive at Nabble.com.
So I have a for loop
for (i in 1 : 5) {
print(i)
}
and I want it to print 1, 2, 3, 4, 5 sequentially for each loop iteration.
Instead, it waits for the whole loop to finish and then prints. It's strange
because my R console seems to have two modes of execution. One where it will
iterate for
list-seq(2,10,2)
list
[1] 2 4 6 8 10
list[-which(2==list)]
[1] 4 6 8 10
using the which() will let you remove things from a list that have a
specified value... I usually use the
blah- blah[-which(TRUE==is.na(blah)) ]
which will remove all NA values in your list
--
View this message
or an incompetent
Such harsh words Peter. You're not making this a friendly environment for
people to ask questions. Is there a less competent attribute mailing list so
that some of us don't offend you with our questions?
On Aug 13, 2010, at 2:11 PM, Peter Dalgaard wrote:
Andrea Franceschini
So I have a bunch of c(start,end) points and want to consolidate them into as
few c(start,end) as possible.
For example:
sample startend
A 5 10
B 7 18
C 14
D 16 20
I'd want the function to return the two distinct
Try to do this
list - seq(1,5,1)
list-list[-3]
list
[1] 1 2 4 5
list[-x] will remove the xth value in your list. Also you can do something
like
list[-c(1:4)]
[1] 5
To remove values at indexes 1-4
list[-c(1,4)]
[1] 2 3 5
To remove values at indexes 1 and 4
--
View this message in
- Original Message
From: Liaw, Andy andy_l...@merck.com
To: Stephen Liu sati...@yahoo.com; r-help@r-project.org
Sent: Sat, August 14, 2010 12:48:33 AM
Subject: RE: [R] Learning ANOVA
Note the names of the variables here. They don't match what you tried
to use in your boxplot() call
OK, I've added a 'horizontal' argument to panel.xyarea(), which is
consistent with the meaning in panel.xyplot(). It is available from
R-forge via SVN now, or as a built package within a day or 2 probably.
Questions like this are best sent to package maintainers directly, I think.
Regards
#
Hi Folks,
I'm relatively new to r. I'd like to have a user respond by pressing a 1 or a
2 and determining their choice and the time of response. Previous postings
have indicated that keyboard responses can be processed using scan and readline
but both seem to wait for the user to also press
Leo Vorthoren L.Vorthoren at nioo.knaw.nl writes:
I have been using generalized linear models in SPSS 18, in order to build
models and to calculate the P values. When I was building models in Excel
(using the intercept and Bs from SPSS), I noticed that the graphs differed
from my
Dear List,
Pls kindly advise what scaling is in plot.
Sometime it could be negative but sometimes it might be positive
.(I guess it is the proportion between the plot and the margin)
Thanks
Elaine
[[alternative HTML version deleted]]
__
Dear List,
I am running constrained correspondence analysis for abundance data of 7
birds.
However, I would like to check which bird prefers which environment gradient
by showing the species with different colors of the dots in cca plot
(package vegan).
Please kindly help and thank you
Elaine
Martin Teicher martin_teicher at hms.harvard.edu writes:
I'm relatively new to r. I'd like to have a user respond by
pressing a 1 or a 2 and determining their choice and
the time of response. Previous postings have indicated that
keyboard responses can be processed using
scan and readline
elaine kuo elaine.kuo.tw at gmail.com writes:
Pls kindly advise what scaling is in plot.
Sometime it could be negative but sometimes it might be positive
.(I guess it is the proportion between the plot and the margin)
Your question is unclear. Please give more context and/or details.
R usesType I sequential SS, not the default Type III marginal SS reported by
SPSS. There is a good blog post explaining this difference along with some
interesting comments --
http://myowelt.blogspot.com/2008/05/obtaining-same-anova-results-in-r-as-in.html
Best Wishes,
Martin H. Teicher
Dept
Yes, but ... the original poster said the coefficients differed too.
(The blog post
you refer to deals with ANOVA (i.e. linear models) rather than GLMs (generalized
linear models): it is true that the sequential/marginal
distinction still applies, but I don't think that can be the *only*
thing
Hi JesperHybel,
Thanks for your advice.
If you're trying to follow the youtube video you have a typing mistake here:
InsectSprays.aov -(test01$count ~ test01$spray)
I think this should be:
InsectSprays.aov -aov(test01$count ~ test01$spray)
Your advice works for me. Sorry I missed aov
Hi David
I do not know if you have done something like this.
I tried str(bp.plot) which gave the section about the regions (for colours) as:
$ panel.args.common:List of 8
..$ x : num [1:2500] 27 28 29 29.9 30.9 ...
..$ y : num [1:2500] 141 141 141 141 141 ...
..$ z : num
What your saying is true. The sequential/marginal difference can account for
the discrepancy in p values but not necessarily the coefficients. One thing
I've found that can lead to differences in coefficients and p values between R
and SPSS is whether or not you specify that a variable is a
On Aug 13, 2010, at 4:06 PM, fishkbob wrote:
list-seq(2,10,2)
list
[1] 2 4 6 8 10
list[-which(2==list)]
[1] 4 6 8 10
using the which() will let you remove things from a list that have a
specified value... I usually use the
blah- blah[-which(TRUE==is.na(blah)) ]
which will remove
On Aug 13, 2010, at 11:25 PM, Duncan Mackay wrote:
Hi David
I do not know if you have done something like this.
I had tried a few efforts like that, starting with an examination of
str(bp.plot) as you demonstrate.
I tried str(bp.plot) which gave the section about the regions (for
On Aug 13, 2010, at 6:57 PM, chantalm wrote:
So I have a for loop
for (i in 1 : 5) {
print(i)
}
and I want it to print 1, 2, 3, 4, 5 sequentially for each loop
iteration.
Instead, it waits for the whole loop to finish and then prints. It's
strange
because my R console seems to have two
Hi Chris,
Thanks for your advice which works for me here.
I'm reading;
An Introduction to R
http://h1.mg4.mail.yahoo.com/dc/launch?sysreq=ignore
NOT finish yet. Also I found many tutorials on Internet. I'll take me time
going through all of them.
I'm interesting reading tutorial with demo.
On Fri, 13 Aug 2010, fishkbob wrote:
So I have a bunch of c(start,end) points and want to consolidate them into as
few c(start,end) as possible.
For example:
sample startend
A 5 10
B 7 18
C 14
D 16 20
I'd want
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