Dear all,
I am trying to learn lapply.
I would like, as a test case, to try the lapply alternative for the
Shadowlist-array(data=NA,dim=c(dimx,dimy,dimmaps))
for (i in c(1:dimx)){
Shadowlist[,,i]-i
}
---so I wrote the following---
returni -function(i,ShadowMatrix) {ShadowMatrix-i}
Hi,
I apologize if the solution is right in front of me, but I can't find anything
on how to convert a class of 'noquote' to 'matrix'. I've tried as.matrix and
I've tried coercing it by 'class(x)-matrix', but of course that didn't work.
I've been using the function 'symnum' which returns an
On 03/29/2011 10:49 PM, jouba wrote:
Dear all
I have an error mesage
« error message : the MLM estimator can not be used when data are incomplete »
When i use the function sem(package lavaan) and when i fill the paramters
estimator and missing
estimator=MLM, missing=ml
i understand
Dear Forum,
I have also problems Snowball (macos, fresh install of rJava, RWeka, RWekajars,
Snowball
from http://cran.ch.r-project.org/bin/macosx/leopard/ ):
library(Snowball)
example(SnowballStemmer)
SnwblS ## Test the supplied vocabulary for the default stemmer ('porter'):
SnwblS source -
Hi Alaios,
there are some problems with your code:
1. In the expression Shadowlist[,,i]-i, i corresponds to dimmaps, not
dimx. The for loop should be either
for (i in c(1:dimmaps)){
Shadowlist[,,i]-i
}
or
for (i in c(1:dimx)){
Shadowlist[i,,]-i
}
2. in lapply, the function must be
Hello Alex.
A few issues:
* you want seq(dimx) instead of seq(1:dimx) (d'oh)
* I think you have problems with your dimensions in the original code as
well: you use i, which runs up to dimx as an indexer for your third
dimension, of size dimmaps. If dimx dimmaps, you're in for unexpected
results.
Hi Alex,
lapply is not a substitute for for, so it not only does things
differenly, it does a different thing.
Shadowlist-array(data=NA,dim=c(dimx,dimy,dimmaps))
for (i in c(1:dimx)){
Shadowlist[,,i]-i
}
Note that your test case is not reproducible as you haven't defined
dimx, dimy,
alaios wrote:
I am trying to learn lapply.
I would like, as a test case, to try the lapply alternative for the
Shadowlistlt;-array(data=NA,dim=c(dimx,dimy,dimmaps))
for (i in c(1:dimx)){
Shadowlist[,,i]lt;-i
}
---so I wrote the following---
returni lt;-function(i,ShadowMatrix)
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On 29/03/11 18:00, Gabor Grothendieck wrote:
On Tue, Mar 29, 2011 at 9:56 AM, Robert Sugar robert.su...@ebi.ac.uk wrote:
Dear R Community,
One thing that always bugged me about R is the abundance of multi-level
nested statements, like:
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On 29/03/11 19:52, Philipp Pagel wrote:
On Tue, Mar 29, 2011 at 09:31:18AM -0700, blanco wrote:
I was just wondering if people use graphics from R straight into articles or
are they always edited in some way; fonts, headers, axis, color etc?
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On 30/03/11 02:47, Fernando Marmolejo Ramos wrote:
Dear R users
I?m aware that the package ?modest? is useful to find the mode in an array.
However, I?d like to know if someone has translated the ?mode? function
built-in
in MATLAB into R
On Fri, Mar 4, 2011 at 1:47 PM, Marius Hofert m_hof...@web.de wrote:
Dear expeRts,
I would like to add two points to a wireframe plot. The points have (x,y,z)
coordinates
where z is determined to be on the wireframe [same z-value]. Now something
strange
happens. One point is perfectly
Large snip.
Absolutely vector - no jpeg, png, ... although it takes
sometimes some convincing of co-authors...
That depends on the kind of graph. I aggree that you should try vector at
first. But when it generates very larges files (e.g. scatterplots with
thousands of points) then you
Hello Rainer and Fernando,
Actually, I think this function should involve the which.max (not max):
Here is a tiny function to perform this (with smarter handeling of multiple
modes and giving proper warning in such cases)
The.mode - function(x, show_all_modes = F)
{
x_freq - table(x)
On Tue, Mar 29, 2011 at 06:58:59PM -0400, Dimitri Liakhovitski wrote:
I have a tab-delimited .txt file (size 800MB) with about 3.4 million
rows and 41 columns. About 15 columns contain strings.
Tried to read it in in R 2.12.2 on a laptop that has Windows XP:
On 2011-03-29 19:12, Mark Ebbert wrote:
Hi,
I apologize if the solution is right in front of me, but I can't find anything on
how to convert a class of 'noquote' to 'matrix'. I've tried as.matrix and I've
tried coercing it by 'class(x)-matrix', but of course that didn't work. I've
been using
On Wed, Mar 30, 2011 at 08:48:55AM +, ONKELINX, Thierry wrote:
Large snip.
Absolutely vector - no jpeg, png, ... although it takes
That depends on the kind of graph. I aggree that you should try
vector at first. But when it generates very larges files (e.g.
scatterplots with
On Wed, 30 Mar 2011, Philipp Pagel wrote:
On Wed, Mar 30, 2011 at 08:48:55AM +, ONKELINX, Thierry wrote:
Large snip.
Absolutely vector - no jpeg, png, ... although it takes
That depends on the kind of graph. I aggree that you should try
vector at first. But when it generates very
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On 30/03/11 11:12, Philipp Pagel wrote:
On Wed, Mar 30, 2011 at 08:48:55AM +, ONKELINX, Thierry wrote:
Large snip.
Absolutely vector - no jpeg, png, ... although it takes
That depends on the kind of graph. I aggree that you should try
Hello!
Suppose I have three charts like below. The top chart is a general
overview and the bottom charts are related so some point of this chart.
To make clear this relationship I want to draw a line between (4,0.9) in
the top chart and (10,1) in the bottom-left one.
Currently I add it
I'd like to save some calculation outputs as a pdf, to incorporate with others
in a document. I've tried
pdf(filename)
name_of_object_to_output
dev.off()
but it doesn't seem to work, appears that this pdf function is for graphics?
Is there a way to output numerical objects to pdf?
Thanks
J
On Tue, Mar 29, 2011 at 01:42:18PM -0600, Greg Snow wrote:
Or we could expand a bit more:
require(TeachingDemos)
require(gtools)
n - 1000
rtrg - matrix(NA, n, 3)
for (i in 1:n) rtrg[i,] - diff(c(0, sort(runif(2)), 1))
rtrg2 - matrix(NA, n, 3)
for (i in 1:n) {
tmp - runif(3)
Hi, we are modelling dusky grouper distribution using underwater visual
census. Our response variable is the abundance of groupers but we want to
see differences in habitat related to maturity because dusky groupers use
different habitats when they're juveniles versus adults. So we're using the
%
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On 30/03/11 10:59, Tal Galili wrote:
Hello Rainer and Fernando,
Actually, I think this function should involve the which.max (not max):
Right - was not awarw of which.max - I would have used which(max(...)) -
which.max is much more elegant.
Hi there,
I am trying to create a violin plot with ggplot2 (which looks awesome
by the way). I am probably not understanding the code correctly by
this is what I am trying (this works if you want to copy and paste it
in R)
library(ggplot2)
p - rep(c(rep(condition_a, 4), rep(condition_b, 4)), 2)
Hello,
I'd like to implement a regression model for extremely zero-inflated
continuous data using a conditional approach, whereby zeroes are
modelled as coming from a binary distribution, while non-zero values
are modelled as log-normal.
So far, I've come across two solutions for this: one, in
Dear UseRs,
If I build an R package, is there a way to load it without having to install it?
Kind regards,
--
David Lindelöf, Ph.D.
+41 (0)79 415 66 41 or skype:david.lindelof
Better Software for Tomorrow's Cities:
http://computersandbuildings.com
Dear JP,
Please do not cross post between lists.
Here is a possible solution.
library(ggplot2)
p - rep(c(rep(condition_a, 4), rep(condition_b, 4)), 2)
q - c(rep(grp_1, 8), rep(grp_2, 8))
r - sample(1:5, 16, rep = T)
d - data.frame(p, q, r)
ggplot(d, aes(x = r)) + geom_ribbon(aes(ymax =
On 11-03-29 9:32 PM, Zhipeng Wang wrote:
Dear all,
I have the problem as the title shows. It is time series of measurements. I
want to estimate the value at time point when we have no actual measured
value (Only in the time range, not for prediction in future time).
Hope you could give me
Sorry for the cross post - but I will post your answer in the other place
too for completeness
And thanks for your answer... that is brilliant especially the second
transparent plot
Fantastic
On 30 March 2011 12:21, ONKELINX, Thierry thierry.onkel...@inbo.be wrote:
Dear JP,
Please do not
On Mar 29, 2011, at 4:45 PM, Kehl Dániel wrote:
Dear list members,
I want to draw surfaces of Dirichlet distributions with different
parameter settings.
My code is the following:
#begin code
a1 - a2 - a3 - 2
#a2 - .5
#a3 - .5
x1 - x2 - seq(0.01, .99, by=.01)
f - function(x1, x2){
On Mar 29, 2011, at 9:32 PM, Zhipeng Wang wrote:
Dear all,
I have the problem as the title shows. It is time series of
measurements. I
want to estimate the value at time point when we have no actual
measured
value (Only in the time range, not for prediction in future time).
Hope you
Hi:
You might want to consider hurdle models in the pscl package.
HTH,
Dennis
On Wed, Mar 30, 2011 at 2:41 AM, a11msp absorbt...@gmail.com wrote:
Hello,
I'd like to implement a regression model for extremely zero-inflated
continuous data using a conditional approach, whereby zeroes are
Hi Dennis,
Thanks - these were the first things I tried, but the problem is that
they refuse to work with non-count data...
Mikhail
On Wed, Mar 30, 2011 at 12:56 PM, Dennis Murphy djmu...@gmail.com wrote:
Hi:
You might want to consider hurdle models in the pscl package.
HTH,
Dennis
On
On Mar 30, 2011; 11:41am Mikhail wrote:
I'm wondering if there's any way to do the same in R (lme can't deal
with this, as far as I'm aware).
You can do this using the pscl package.
Regards, Mark.
--
View this message in context:
Dear all,
I just stumbled upon the fact, that when I perform a regression on
multivariate responses, that are not centred, I get a ricilulously high
R-squared value. After reading the code of summary.lm, I found a bug in
the function summary.lm:
mss is calculated by:
mss -sum((f -
Update:
turns out there was a sister posting to mine two years ago:
http://r.789695.n4.nabble.com/Zinb-for-Non-interger-data-td898206.html
It was then suggested to use a zero-inflated distribution from the
gamlss package. It turns out that they do have a zero-adjusted (albeit
not strictly
I need to change the font(s) used in mosaic from package vcd.
The help file and the vignette do not give very explicit examples for
doing that.
The easiest solution would be changing the font for everything
on the graph: var labels, var names, title, subtitle, and cell labels.
What is the easiest
On 28 March 2011 17:08, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2011-03-27 21:37, Alex Olssen wrote:
Hi everyone,
I am looking to do some manual maximum likelihood estimation in R. I
have done a lot of work in Stata and so I have been using output
comparisons to get a handle on what is
I'm not sure about .pdf, but look at ?sink to create a text file. You could
then print this as a .pdf if you so desired.
Rob
--
Robert W. Baer, Ph.D.
Professor of Physiology
Kirksville College of Osteopathic Medicine
A. T. Still University of Health
This is user error: that fit has class c(mlm, lm) and you should
be calling summary() on it, which will dispatch the mlm method.
For multiple-response linear models, there is also summary.manova.
On Wed, 30 Mar 2011, Stefan Schlager wrote:
Dear all,
I just stumbled upon the fact, that when
Hi,
I am trying to write a loop to recode my data from -999 to NA in R. What's
the most efficient way to do this? Below is what I'm presently doing, which
is inefficient. Thanks,
Chris
dat0 - read.table(time1.dat)
colnames(dat0) - c(e1dq, e1arcp, e1dev, s1prcp, s1nrcp, s1ints,
a1gpar,
Try:
dat0 - read.table('tim1.dat', na = -999)
On Wed, Mar 30, 2011 at 10:15 AM, Christopher Desjardins
cddesjard...@gmail.com wrote:
Hi,
I am trying to write a loop to recode my data from -999 to NA in R. What's
the most efficient way to do this? Below is what I'm presently doing, which
is
On 30.03.2011 15:15, Christopher Desjardins wrote:
Hi,
I am trying to write a loop to recode my data from -999 to NA in R. What's
the most efficient way to do this? Below is what I'm presently doing, which
is inefficient. Thanks,
Chris
I think read.table(na.string=-999.) is.
Uwe
Am 30.03.2011 09:15, schrieb Christopher Desjardins:
Hi,
I am trying to write a loop to recode my data from -999 to NA in R. What's
the most efficient way to do this? Below is what I'm presently doing, which
is inefficient. Thanks,
Chris
dat0- read.table(time1.dat)
colnames(dat0)- c(e1dq,
On Wed, 2011-03-30 at 08:15 -0500, Christopher Desjardins wrote:
Hi,
I am trying to write a loop to recode my data from -999 to NA in R. What's
the most efficient way to do this? Below is what I'm presently doing, which
is inefficient. Thanks,
Chris
dat0 - read.table(time1.dat)
dat0
It could be done in a large number of ways depending on how often you
need it etc.
You might take a look at defmacro in package gtools:
# library(gtools)
setNA - macro(df, var, values)
{
df$var[df$var %in% values] - NA
}
then instead of
dat0[dat0$e1dq==-999.,e1dq] - NA
you could
Take a look in ?Sweave
On Wed, Mar 30, 2011 at 6:51 AM, Maas James Dr (MED) j.m...@uea.ac.uk wrote:
I'd like to save some calculation outputs as a pdf, to incorporate with
others in a document. I've tried
pdf(filename)
name_of_object_to_output
dev.off()
but it doesn't seem to work,
Regression for the gamma distribution can be expressed as a generalized
linear model. Check Chapter 8 of McCullagh, P. Nelder, J. A. (1989),
Generalized linear models, Chapman Hall, London, UK.
Walter Anderson wandrso...@gmail.com
Sent by: r-help-boun...@r-project.org
03/29/2011 09:57
Philipp, you are a savior!
That's exactly what has been happening - and it was driving me crazy.
quote= fixed things.
Thank you very much!
Dimitri
On Wed, Mar 30, 2011 at 5:01 AM, Philipp Pagel p.pa...@wzw.tum.de wrote:
On Tue, Mar 29, 2011 at 06:58:59PM -0400, Dimitri Liakhovitski wrote:
I
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On 30/03/11 11:51, Maas James Dr (MED) wrote:
I'd like to save some calculation outputs as a pdf, to incorporate with
others in a document. I've tried
pdf(filename)
name_of_object_to_output
dev.off()
but it doesn't seem to work, appears
Try using a loop like the following
dat0 - read.table(time1.dat)
id - c(e1dq, e1arcp, e1dev, s1prcp, s1nrcp,s1ints,a1gpar, a1pias,
a1devt)
for (a in 1:length(id)) {
dat0[dat0$id[a]==-999.,as.character(id[a])] - NA
}
--
Muhammad Rahiz
Researcher DPhil Candidate (Climate Systems
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On 30/03/11 15:42, Rainer M Krug wrote:
On 30/03/11 11:51, Maas James Dr (MED) wrote:
I'd like to save some calculation outputs as a pdf, to incorporate with
others in a document. I've tried
pdf(filename)
name_of_object_to_output
dev.off()
Ah ... yes. I knew that but clearly didn't at the time of my question or
script writing.
Thanks,
Chris
On Wed, Mar 30, 2011 at 8:22 AM, Henrique Dallazuanna www...@gmail.comwrote:
Try:
dat0 - read.table('tim1.dat', na = -999)
Ah ... yes. I knew that but clearly didn't at the time of my
The latex() function in the Hmisc package will typeset your
objects. Embed that in a tex document and run pdflatex.
Rich
Sent from my iPhone
On Mar 30, 2011, at 5:51, Maas James Dr (MED) j.m...@uea.ac.uk wrote:
I'd like to save some calculation outputs as a pdf, to incorporate with
others
Dear everybody,
I have the following challenge. I have a data set with 2 subgroups,
dates (days), and corresponding values (see example code below).
Within each subgroup: I need to aggregate (sum) the values by week -
for weeks that start on a Monday (for example, 2008-12-29 was a
Monday).
I find
I'm working on predict.survreg and am confused about xlevels.
The model.frame method has the argument, but none of the standard
methods (model.frame.lm, model.frame.glm) appear to make use of it.
The documentation for model.matrix states:
xlev: to be used as argument of model.frame if data has
On Wed, 30 Mar 2011, Erich Neuwirth wrote:
I need to change the font(s) used in mosaic from package vcd.
The help file and the vignette do not give very explicit examples for
doing that.
The easiest solution would be changing the font for everything
on the graph: var labels, var names, title,
Dear colleagues,
I'm working with the 2008 Canada Election Studies
(http://www.queensu.ca/cora/_files/_CES/CES2008.sav.zip), trying to construct a
weighted national sample using the survey package.
Three weights are included in the national survey (a household weight, a
provincial weight and a
Dear All,
My question is:
how can I estimate VECM system with unrestricted trend (aka case 5)
option as a deterministic term?
As far as I know, ca.jo in urca package allows for restricted trend
only [vecm
- ca.jo(data, type = trace/eigen, ecdet = trend, K = n, spec =
transitory/longrun)].
I'm going to go ahead and shamelessly bump this question up the list.
I saw that out of the 34 posts yesterday, only 9 did not receive an
answer. Perhaps someone who finds this question trivial is checking
his e-mail right now :)
Werner
On Tue, Mar 29, 2011 at 10:20 AM, jovian
On Wed, 30 Mar 2011, Terry Therneau wrote:
I'm working on predict.survreg and am confused about xlevels.
The model.frame method has the argument, but none of the standard
methods (model.frame.lm, model.frame.glm) appear to make use of it.
But I see this in predict.lm:
m -
Use facetting:
sets - rbind(cbind(set=set1, set), cbind(set=set2, set2))
ggplot(sets, aes(x = time, y = hours)) +
geom_area(colour = 'red', fill = 'red', alpha = 0.5) +
geom_area(stat = 'smooth', span = 0.2, alpha = 0.3) +
ylim(0,40) +
facet_grid(set ~ .)
Best,
Ista
On Wed, Mar 30, 2011
On Mar 28, 2011, at 16:53 , Ben Bolker wrote:
Rubén Roa rroa at azti.es writes:
However, shouldn't _free parameters_ only be counted for degrees of
freedom and for calculation of AIC?
The sigma parameter is profiled out in a least-squares
linear regression, so it's not free, it's
Hello Greg,
you can exploit the argument 'dumvar' for this. See ?ca.jo
Best,
Bernhard
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] Im Auftrag von Grzegorz Konat
Gesendet: Mittwoch, 30. März 2011 16:46
An: r-help@r-project.org
On Mar 30, 2011, at 16:05 , Christopher Desjardins wrote:
dat0 - read.table('tim1.dat', na = -999)
Ah ... yes. I knew that but clearly didn't at the time of my question or
script writing.
Thanks,
Chris
Depending on where your data came from, you could get caught by the fact that
the
Amen. Ditto for -999.000, -999.00 and all of the other ones
that various (usually Fortran) programmers have used. Has the most
recent Fortran standard come around to understanding NA?
--
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler
HI!
Would anybody suggest what function/package/method can I use to obtain
forecasts for horizons longer than 1 period ahead?
I want to do multistep forecasts with multilayer feedforward networks. I
have tried several packages, but it turned out that the functions yield only
one-step
Dear all,
I have a function that predicts DV based on one predictor pred:
pred-c(0,300,780,1560,2340,13120)
DV-c(0,500,1000,1400,1700,1900)
## I define Function 1 that computes the predicted value based on pred
values and parameters a and b:
calc_DV_pred - function(a,b) {
On Wed, Mar 30, 2011 at 11:51 AM, peter dalgaard pda...@gmail.com wrote:
On Mar 30, 2011, at 16:05 , Christopher Desjardins wrote:
dat0 - read.table('tim1.dat', na = -999)
Ah ... yes. I knew that but clearly didn't at the time of my question or
script writing.
Thanks,
Chris
Depending
Hi,
How about something like:
sum.by.day - function(ff) {
by.day - split(ff$value,weekdays(ff$dates))
lapply(by.day,sum)
}
by.grp - split(myframe,myframe$group)
lapply(by.grp,sum.by.day)
Martyn
-Original Message-
From: r-help-boun...@r-project.org
Dear David,
I think that is a small bug too, maybe because the function is constant?
is there a nice way to put the c(0,2.1) argument optionally, only if all
the parameters are 1?
Should I post the problem somewhere else (developers maybe?)
thanks:
Daniel
2011-03-30 04:42 keltezéssel, David
Thank you, Martyn.
But it looks like this way we are getting sums by day - i.e., across
all Mondays, all Tuesdays, etc.
Maybe I did not explain well, sorry! The desired output would contain
sums for each WHOLE week - across all days that comprise that week -
Monday through Sunday.
Makes sense?
Not sure it's the case here, but numeric optimizers are well-known to
be subject to scaling issues.
-- Bert
On Wed, Mar 30, 2011 at 9:45 AM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Dear all,
I have a function that predicts DV based on one predictor pred:
On Wed, Mar 30, 2011 at 10:51 AM, peter dalgaard pda...@gmail.com wrote:
On Mar 30, 2011, at 16:05 , Christopher Desjardins wrote:
dat0 - read.table('tim1.dat', na = -999)
Ah ... yes. I knew that but clearly didn't at the time of my question or
script writing.
Thanks,
Chris
I see the logic now. I think that more sentences in the document would
be very helpful, however. What is written is very subtle.
I suggest the following small expansion for model.matrix.Rd:
\item{data}{a data frame. If the object has a \code{terms} attribute
then it is assumed to be the
On Mar 30, 2011, at 11:52 AM, Gabor Grothendieck wrote:
On Wed, Mar 30, 2011 at 11:51 AM, peter dalgaard pda...@gmail.com wrote:
On Mar 30, 2011, at 16:05 , Christopher Desjardins wrote:
dat0 - read.table('tim1.dat', na = -999)
Ah ... yes. I knew that but clearly didn't at the time
On Wed, 2011-03-30 at 09:55 -0700, Kehl Dániel wrote:
Dear David,
I think that is a small bug too, maybe because the function is constant?
is there a nice way to put the c(0,2.1) argument optionally, only if all
the parameters are 1?
Should I post the problem somewhere else (developers
It helped a lot indeed, thank you very much!
Now I understand why it was a problem for persp!
Daniel
2011-03-30 10:31 keltezéssel, Gavin Simpson írta:
On Wed, 2011-03-30 at 09:55 -0700, Kehl Dániel wrote:
Dear David,
I think that is a small bug too, maybe because the function is constant?
is
Try this:
pred - pred/1e06
DV - DV/1e03
opt1 - optim(fn=my.function, par=1.0)
opt2 - optim(fn=my.function, par=1.0, method=BFGS)
opt3 - optim(fn=my.function, par=1.0, method=L-BFGS-B, lower=0, upper=1)
opt1
opt2
opt3
Ravi.
---
Ravi Varadhan,
Actually, it works for the a=1 case, not for the others. It still gives
the invalid 'zlim argument' error.
I'll try to work it out maybe instead of NULL giving a c which is
dependent on the max(z).
Daniel
2011-03-30 10:42 keltezéssel, Kehl Dániel írta:
It helped a lot indeed, thank you very
Terry,
The fact that model.frame attaches xlevels to
the terms based on factors in the input data.frame
(and attaches dataClass based on the input data.frame),
but the subsequent call to model.matrix is responsible
for turning character vectors in the data.frame into
factors (and then into
Achim
I simply want to replace the font R uses on mosaic (whatever it is)
by a font of my choice (say Calibri or Arial)
because I need to embed the R charts in a PowerPoint
presentation and want the fonts to match.
And I want the most simple way of accomplishing this.
I worked my way through the
Thank you, Ravi - definitely better!
On Wed, Mar 30, 2011 at 2:06 PM, Ravi Varadhan rvarad...@jhmi.edu wrote:
Try this:
pred - pred/1e06
DV - DV/1e03
opt1 - optim(fn=my.function, par=1.0)
opt2 - optim(fn=my.function, par=1.0, method=BFGS)
opt3 - optim(fn=my.function, par=1.0,
Try this:
windowsFonts(calibri = windowsFont(Calibri))
mosaic(UCBAdmissions, labeling_args = list(
gp_labels = gpar(fontsize = 12, fontfamily = calibri),
gp_varnames = gpar(fontsize = 16, fontfamily = calibri)
))
On Wed, Mar 30, 2011 at 3:25 PM, Erich Neuwirth
erich.neuwi...@univie.ac.at
Hi,
If you want grid graphics:
For data.frames and matrices, gridExtra has a grid.table() function.
For strings (paragraph), Rgraphics has a function too, whose name i
forget. It could be possible to combine the two and define a method to
display lists as well.
HTH,
baptiste
On 30 March
On Wed, 2011-03-30 at 11:12 -0700, Kehl Dániel wrote:
Actually, it works for the a=1 case, not for the others. It still gives
the invalid 'zlim argument' error.
I'll try to work it out maybe instead of NULL giving a c which is
dependent on the max(z).
Sorry, I misread the helpfile - the
On Wed, 30 Mar 2011, Erich Neuwirth wrote:
Achim
I simply want to replace the font R uses on mosaic (whatever it is)
by a font of my choice (say Calibri or Arial)
because I need to embed the R charts in a PowerPoint
presentation and want the fonts to match.
Ah, ok, sorry I misread your mail.
Try this:
aggregate(value ~ group + format(dates, %Y.%W), myframe, FUN = sum)
On Wed, Mar 30, 2011 at 11:23 AM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Dear everybody,
I have the following challenge. I have a data set with 2 subgroups,
dates (days), and corresponding
Wow - thanks all for your helpful replies. Awesome forum.
Am I right to assume that you use the postscript function to create .ps and
.pdf files from R?
blanco
--
View this message in context:
Hello, everyone!
Does anyone know how make some symbols have special means in R? For example,
we know that + in R means the sum of the two operand on its left and
right. I want to define some operators in R by myself. Is this possible?
Regards!
--
Chuanlong Du
Department of Statistcis
Iowa
Hello!
Does any one know how to modify attributes of files (hide, read only and
etc) in Windows Systems using R? I tried to use shell to call system
command, but it seems that it doesn't work well. Sometimes it works but
sometimes not.
Regards!
--
Chuanlong Du
Department of Statistcis
Iowa
#
Noble America Announcement for Summer Internship 2011
##
Organization Name: Noble America, http://www.thisisnoble.com/
Location: Stamford, Connecticut, USA
Period: 10-12 Weeks for
Hello, everyone!
Does anyone know whether there's a function in R which can save the content
in R console to some file? I'm using Windows system and the usual R console
instead of Rstudio.
Regards!
--
Chuanlong Du
Department of Statistcis
Iowa State University
Ames, IA, US 50011
Dear Marc,
Your answer on post
https://stat.ethz.ch/pipermail/r-help/2005-March/067634.html
has a broken link.
Thank you,
W
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hello Bernhard,
Thank You very much. Unfortunately I'm still not really sure how should I
use dummy vars in this context...
If I have a system of three variables (x, y, z), lag order = 2 and 1
cointegrating relation, what should I do? I mean, what kind of 'pattern'
should be used to create those
I knew there had to be a simple solution. Thank you!
On Mar 30, 2011, at 3:04 AM, Peter Ehlers wrote:
On 2011-03-29 19:12, Mark Ebbert wrote:
Hi,
I apologize if the solution is right in front of me, but I can't find
anything on how to convert a class of 'noquote' to 'matrix'. I've tried
On Mar 30, 2011, at 11:04 AM, Chuanlong Du wrote:
Hello, everyone!
Does anyone know how make some symbols have special means in R? For
example,
we know that + in R means the sum of the two operand on its left and
right. I want to define some operators in R by myself. Is this
possible?
On Mar 30, 2011, at 11:51 AM, Wayne Lee wrote:
Dear Marc,
Your answer on post
https://stat.ethz.ch/pipermail/r-help/2005-March/067634.html
has a broken link.
Thank you,
W
Wayne, here is the original thread being referenced from March of 2005:
On Wed, Mar 30, 2011 at 09:56:09AM -0700, blanco wrote:
Wow - thanks all for your helpful replies. Awesome forum.
Am I right to assume that you use the postscript function to create .ps and
.pdf files from R?
almost:
postscript(..., onefile=FALSE) # for eps
pdf() # for PDF
And don't
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