Hi R users,
I am sort of new on those.
In the following logistic regression function tigol( 0.3 + 3*x + 5*z + 7*w
) , why the intercept was set 0.3, and the coefficients were set 3 ,5 and
7?
Thanks.
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Hello,
May i know whether it is possible to generate data twice from Weibull
distribution and use one as the start time and the
other as the end time, below is my code.
Any suggestion on how to estimate the parameters of Weibull distribution with
interval data will be highly appreciated.
Thank
Hello,
I have tried obtaining the value of standard error from the code below but i
get different values when i compare it with the
standard error obtained from the hessian matrix. Can somebody help me out?
Thank you
n=100;rr=1000
p1=1.2;b=1.5
sq11=sq21=0
for (i in 1:rr){
SL == Steve Lianoglou mailinglist.honey...@gmail.com
on Mon, 23 Apr 2012 01:10:31 -0400 writes:
SL On Mon, Apr 23, 2012 at 12:01 AM, Michael
SL comtech@gmail.com wrote:
yes, but that is not a good Review or Survey... thx
SL But the packages listed there do have their
Dear R users,
I want to subset a daily zoo series according to its month, find % of NA
in each month.
I am finding it difficult to subset the daily dataset into monthly for the
given operation.I am planning to do this for a huge dataset.
Thanks in advance.
Regards
Vikram
[[alternative
On Mon, 23 Apr 2012, Vikram Bahure wrote:
Dear R users,
I want to subset a daily zoo series according to its month, find % of NA
in each month.
I am finding it difficult to subset the daily dataset into monthly for the
given operation.I am planning to do this for a huge dataset.
Use
Hi Vikram,
maybe something like this?
require(zoo)
## a daily zoo series
z - zoo(1:200, as.Date(2012-01-01) + 1:200)
## add some NAs
z[ceiling(runif(10)*200)] - NA
## aggregate to monthly
aggregate(z, format(index(z), %Y-%m), length)
aggregate(z, format(index(z), %Y-%m), function(x)
Thanks for the help. :)
I was also looking at attach() but this one works perfect.
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-Original Message-
I am just trying to split a dataframe of 750 observations of
29 variables by Site, which is a vector in the dataframe
with five text names (ex. PtaCaracol).
A couple of methods.
i) First, look up ?split, which chops your data frame into a list of five data
Hi everyone.
I have a question about a work on R I have to do for my job.
I have temperature data coming from 70 weather stations. One data file
corresponds to one station for one year (so 70 files for one year). Each
file looks like this (important: each file contains NAs):
time
Hi,
Even your example should show why this is a bad way to fill in missing weather
data: you end up with a sequence for station 1 of 1, 2, 10, 4 even though
that's certainly wrong because Station 2 is reliably 7 units above Station 1.
Correlated doesn't mean identical.
There are other better
Hello,
Can anyone please suggest any packages in R that can be used to overlay gene
expression data on SNP (affymetrix) copy number ?
Thanks,
Ekta
Senior Research Associate
Bioinformatics Department
Jubilant Biosys Pvt Ltd,
#96, Industrial Suburb, 2nd Stage
Yeshwantpur, Bangalore 560 022
Ph No :
Hi,
On Mon, Apr 23, 2012 at 7:33 AM, Ekta Jain ekta_j...@jubilantbiosys.com wrote:
Hello,
Can anyone please suggest any packages in R that can be used to overlay gene
expression data on SNP (affymetrix) copy number ?
I guess you mean visually? If so, I'd suggest skimming through the
Small mistake in my subset example. I mean to remove the `$ID` part at
the end so that you can play with the whole subset-ted data.frame, and
not just get back the ID column. Instead of this:
R interesting - subset(DataFile, log2 = 7)$ID
do this:
R interesting - subset(DataFile, log2 = 7)
I
Hi,
So I've been figuring out how to use igraph in R and like it for it's speed
and simplicity. Now I have a graph built from an edgelist where vectors have
a $name attribute. I have another dataframe with attributes tied to a
vector ID, which is the same as the $name attribute of vectors
Dear all,
I've been getting different results from the sparse and dense version
of model.Matrix when used with sparse contrasts and interactions
between factors. The same happens when using model.matrix and
sparse.model.matrix. When calculating list.contrasts I get the same
results for sparse and
Hi, Jorge!
Help me please! I made a classification tree (rpart package) according to my
train data and set of variables. How can I validate my test data? I want to
check if the test data will classified properly by the same tree. Thanks
cheers
Maria
Tue, 10 Apr 2012 08:44:39 -0700 (PDT) оÑ
Dear all,
I have tow (several) bivariate distributions with a known mean and
variance-covariance structure (hence a known density function) that I would
like to compare in order to get an intersect that tells me something about how
different these distributions are (as t-statistics for
Hi Sarah,
Thank you for your answer.
Yes I know that my proposition is not necessary the better way to do it. But
my problem concerns only big gaps of course (more than half a day of missing
data, till several months of missing data).
I've already filled small gaps with the interpolation that you
Hi
I am looking for a efficient way to estimate all parameters in your
data.frame set using a specific function:
for example
ln(T)=b_0 + b_1*ln(Y_i*Y_j) + b_2*ln()+ ... + etc.
Thanks,
Ph
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Sent
On 23.04.2012 12:42, phillip03 wrote:
Hi
I am looking for a efficient way to estimate all parameters in your
data.frame set using a specific function:
for example
ln(T)=b_0 + b_1*ln(Y_i*Y_j) + b_2*ln()+ ... + etc.
Sounds like you are looking for lm().
Uwe Ligges
Thanks,
Ph
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Rpart has a built in cross-validation proceedure. the xerror and so on
are based on a ten fold cross validation, I believe. Read the manual
for more results. If you plot the fit with post and then look at the
postscript file it should have a misclassification rate under the
terminal nodes.
On 04/22/2012 05:00 AM, r-help-requ...@r-project.org wrote:
I am trying to run Weibull PH model in R.
Assume in the data set I have x1 a continuous variable and x2 a
categorical variable with two classes (0= sick and 1= healthy). I fit the
model in the following way.
Thanks for saying. :)
This morning I tried out some things with this code, and different variants
with it.
Works nice.
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I could not reply directly to the initial thread with the same title.
There are two sorts of Robust PCA, those that were devised before the
recent string of Low Rank approaches and then the new set of algorithms
that provide robust PCA in light of sparse but potentially large
errors/outliers
Hello,
I'm working with RStudio, which does not display enough lines in the
console that I can read the summary of my (due to the covariance-matrix
rather long) model. There are no ways around this, so I guess I need to
export the summary into a file in order to see it ...
I'm new to R, and R
Consider the following generic code for a survival model
survobj-Surv(data$Time,data$Satisfactory)
survmodel-survreg(survobj~x1+x2+x3+x4+x5+x6, data=data, dist=weibull)
survsum-summary(survmodel)
survsum
My question: Does anyone know what exactly survreg() does differently if
x1-factor(data$x1,
On 23-04-2012, at 15:20, Eiko Fried wrote:
Hello,
I'm working with RStudio, which does not display enough lines in the
console that I can read the summary of my (due to the covariance-matrix
rather long) model. There are no ways around this, so I guess I need to
export the summary into a
Hi there,
To see the results of my clustering graphically I was using clusplot. But it
only provides a look at the two most important components of the dataset.
I recently found the Mclust() function which produces very nice colored pair
plots for the clustered dataset.
see Graph:
Yes, the (start, stop] formalism is the easiest way to deal with time
dependent data.
Each individual only needs to have sufficient data to describe them, so
for if id number 4 is in house 1, their housemate #1 was eaten at time
2, and the were eaten at time 10, the following is sufficient
Another possibility for visual display of several kinds of data is RCytoscape,
for which an example can be seen here:
http://rcytoscape.systemsbiology.net/versions/current/gallery/TCGA/subnet.TCGA.02.0014.png
This portrays
1) gene expression (green: under-expression; red: over-expression)
On Apr 23, 2012, at 8:29 AM, wwreith wrote:
Consider the following generic code for a survival model
survobj-Surv(data$Time,data$Satisfactory)
survmodel-survreg(survobj~x1+x2+x3+x4+x5+x6, data=data, dist=weibull)
survsum-summary(survmodel)
survsum
My question: Does anyone know what
This thread reveals that R has some holes in the solution of some of the linear algebra
problems that may arise. It looks like Jim Ramsay used a quick and dirty approach to the
generalized eigenproblem by using B^(-1) %*% A, which is usually not too successful due to
issues with condition of B
On Mon, Apr 23, 2012 at 6:33 AM, Ekta Jain ekta_j...@jubilantbiosys.comwrote:
Hello,
Can anyone please suggest any packages in R that can be used to overlay
gene expression data on SNP (affymetrix) copy number ?
Hi Ekta,
If you mean visually, as Steve suggested, you could try packages like
Hi Rui,
Yes you're right. It's me again ^^
This post is the last part (I hope) of my job. You helped me a lot last time
for the correlation matrices.
I have to leave my work now, so I'll check and test your proposition
tomorrow. But it makes no doubt that it'll help me a lot again.
I'll tell
I want to invoke R on a Linux Web server from Java, in order to analyse
data in ways that would take too long to code, and run too slowly, in
Java. In particular, to do correspondence analyses. To this end, I've
installed R version 2.15.0 on my Web host's x86_64 GNU/Linux machine, and
tried
Hello All,
Started out awhile ago trying to select columns in a dataframe whose names
contain some variation of the word mutant using code like:
names(KRASyn)[grep(muta, names(KRASyn))]
The idea then would be to add together the various columns using code like:
KRASyn$Mutant_comb -
On Apr 23, 2012, at 12:10 PM, Paul Miller wrote:
Hello All,
Started out awhile ago trying to select columns in a dataframe whose
names contain some variation of the word mutant using code like:
names(KRASyn)[grep(muta, names(KRASyn))]
The idea then would be to add together the various
Hello Dr. Winsemius,
Unfortunately, I also have terms like krasmutated. So simply selecting words
that start with muta won't work in this case.
Thanks,
Paul
--- On Mon, 4/23/12, David Winsemius dwinsem...@comcast.net wrote:
From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R]
On 23/04/2012 12:05 PM, Jocelyn Ireson-Paine wrote:
I want to invoke R on a Linux Web server from Java, in order to analyse
data in ways that would take too long to code, and run too slowly, in
Java. In particular, to do correspondence analyses. To this end, I've
installed R version 2.15.0 on my
Hello,
I am having a problem where code that plots lines using a different data
frame plots bars with the current data frame (I am intended to plot lines).
The code specifies lines (see below), so I can't figure out why the results
are bars. I suspect that it may have something to do with the
I routinely write graphics into multi-page PDFs, but some graphics (i.e.
plots of large spatial datasets using levelplot()) can result in enormous
files. I'm curious if there is a better way. For example:
#First, make some data:
library(lattice)
d=expand.grid(x=1:1000,y=1:1000)
Hello,
jeff6868 wrote
Hi Sarah,
Thank you for your answer.
Yes I know that my proposition is not necessary the better way to do it.
But my problem concerns only big gaps of course (more than half a day of
missing data, till several months of missing data).
I've already filled small
I'm loading a nicely formatted csv file.
#!/usr/bin/env Rscript
kpi - read.csv(
# This is a dump of the username, date_joined and last_login columns
# from the auth_user Django table.
'data/2012-04-23.csv',
colClasses = c('character')
)
I'm running into an unexpected error using the glmnet and Matrix packages.
I have a matrix that is 8 million rows by 100 columns with 75% of the
entries being zero. When I run a vanilla glmnet logistic model on my server
with 300 GB of RAM, the task completes in 20 minutes:
x # 8 million x 100
Thanks Steve, your explanation of the == is very helpful, and I will look up
?by. Ben
-Original Message-
From: S Ellison [mailto:s.elli...@lgcgroup.com]
Sent: Mon 4/23/2012 3:19 AM
To: Ben Neal; r-help@r-project.org
Subject: RE: Splitting a dataframe by character vector
Hi,
I am relatively new to R. Have scourged the help files and the www but
havent been able to get a solution.
I have around 250 csv files, one file for each date. They have columns of
all types, numeric, string etc. The name of each file is the date in the
form of 'mmdd'. There is no column
Hello
I have two lists of numbers, each list is ~800 numbers long. I want to know
if the two lists are significantly different from each other.
Could anyone suggest what library in R to use?
I think maybe the mann-whitney test, as it is not parametric, but i am
unsure if it is suitable as my list
On 23/04/2012 17:33, Duncan Murdoch wrote:
On 23/04/2012 12:05 PM, Jocelyn Ireson-Paine wrote:
I want to invoke R on a Linux Web server from Java, in order to analyse
data in ways that would take too long to code, and run too slowly, in
Java. In particular, to do correspondence analyses. To
On 23/04/2012 10:49 AM, Adam Wilson wrote:
I routinely write graphics into multi-page PDFs, but some graphics (i.e.
plots of large spatial datasets using levelplot()) can result in enormous
files. I'm curious if there is a better way. For example:
#First, make some data:
library(lattice)
Below.
-- Bert
On Mon, Apr 23, 2012 at 9:10 AM, Paul Miller pjmiller...@yahoo.com wrote:
Hello All,
Started out awhile ago trying to select columns in a dataframe whose names
contain some variation of the word mutant using code like:
names(KRASyn)[grep(muta, names(KRASyn))]
The idea
On Apr 23, 2012, at 12:25 PM, Paul Miller wrote:
Hello Dr. Winsemius,
Unfortunately, I also have terms like krasmutated. So simply
selecting words that start with muta won't work in this case.
You are aware that negative indexing can be used with grep aren't you?
--
David.
Thanks,
But maybe ... (see below)
-- Bert
On Mon, Apr 23, 2012 at 9:25 AM, Paul Miller pjmiller...@yahoo.com wrote:
Hello Dr. Winsemius,
Unfortunately, I also have terms like krasmutated. So simply selecting
words that start with muta won't work in this case.
Thanks,
Paul
--- On Mon, 4/23/12,
On Apr 23, 2012, at 11:48 AM, Thomas Levine wrote:
I'm loading a nicely formatted csv file.
#!/usr/bin/env Rscript
kpi - read.csv(
# This is a dump of the username, date_joined and last_login
columns
# from the auth_user Django table.
'data/2012-04-23.csv',
We are aware that glmnet_1.7.3 does not pass for windows
and are looking into the problem. It has something to do
with the gcc compiler being slightly different on
windows versus linux/mac platforms. As soon as we have
resolved the issue, we will post a new version to CRAN
Trevor Hastie
Dear useRs,
I have used using the excellent mgcv package (version 1.7-12) to
create a generalized additive model (gam) including random effects -
represented with s(...,bs=re) - on the basis of dialect data.
My model contains two random-effect factors (Word and Key - the latter
representing a
Hello,
phillip03 wrote
Thank you Rui
Can you help me with my ifelse problem - I would like to add a list to my
data.frame where avgflow in those rows where ONLY my country pair both are
in euro
First of all, try to use better (much, much better) code writing.
What are you trying to do
On Apr 23, 2012, at 12:53 PM, phillip03 wrote:
So how would I use the lm() to estimate b_0 and b_1 for example
My Y_i and Y_j are data observations how does the lm() use my
data.frame ?
Have your read An Introduction to R. Section 11 would appear to
cover all the needed topics.
Building in Berend's suggestions I think this function should work for most
people (I'm going to wrap it into a package but figured people may want to
grab this directly):
# Please see http://www.netlib.org/lapack/double/dggev.f for a description
of inputs and outputs.
Rdggev -
This might do it for you:
for (i in fileNames){
input - read.table(i, .)
# you might want to use regular expressions to extract just the date.
input$fileName - i
write.table(i, )
}
On Mon, Apr 23, 2012 at 12:29 PM, Shivam shivamsi...@gmail.com wrote:
Hi,
I am
Hi Bert,
Yes, code like:
x - names(yourdataframe)
grepl(muta,x) !grepl(nonmuta|unmuta,x)
works perfectly.
Thanks very much for your help.
Paul
--- On Mon, 4/23/12, Bert Gunter gunter.ber...@gene.com wrote:
From: Bert Gunter gunter.ber...@gene.com
Subject: Re: [R] Selecting columns
Dear R-helpers,
I would like to test if the slope corresponding to a continuous variable in
my model (summary below) is different than one.
I would appreciate any ideas for how I could do this in R, after having
specified and run this model?
Many thanks,
Mark Na
Call:
lm(formula =
Hello, very new to R, playing with tables, and I am trying to do
x - subset(data, columnlabel == x)
for every element in my column that I could find by using
table (data [,columnlabel])
I'd appreciate any useful help and I'm sorry if I didn't get the terminology
perfect. Thanks.
--
View
Hi RUI
Thank you so much ! I know I have a lot to learn : / sorry for that.
If I want to make a new data.frame where it is the NONEURO avgflows. how do
I do that ?
Ph
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see file.rename()
--
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Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 4/22/12 1:25 AM, sagarnikam123 sagarnikam...@gmail.com wrote:
i want to cut file from e.g. abc folder put it into another location
with folder name e.g. xyz
This little example might help.
foo - data.frame(a=1:10, b=letters[1:0])
foo
a b
1 1 a
2 2 a
3 3 a
4 4 a
5 5 a
6 6 a
7 7 a
8 8 a
9 9 a
10 10 a
foo$date - '20120423'
foo
a b date
1 1 a 20120423
2 2 a 20120423
3 3 a 20120423
4 4 a 20120423
5 5 a 20120423
On 4/23/2012 9:24 AM, Matthias Rieber wrote:
Hello,
I've some problem with the ggplot2. Here's a small example:
--8--
library(ggplot2)
molten- data.frame(date=c('01','01','01','01',
'02','02','02','02'),
channel=c('red','red','blue','blue',
Are they the same with .RData being the newer format? Thanks,
...Tao
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
If I want to make a new data.frame where it is the NONEURO avgflows. how
do I do that ?
Exactly like above, but without the negation (the exclamation mark).
You must also start to use the help system, for instance:
?!
Rui Barradas
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a
foo$date - '20120423'
foo
a b date
1 1 a 20120423
2 2 a 20120423
3 3 a 20120423
4 4 a 20120423
5 5 a 20120423
6 6 a 20120423
7 7 a 20120423
8 8 a 20120423
9 9 a 20120423
10 10 a 20120423
In other words, immediately after reading the data into a data frame, add
Hi,
On 24 April 2012 05:00, Duncan Murdoch murdoch.dun...@gmail.com wrote:
On 23/04/2012 10:49 AM, Adam Wilson wrote:
I routinely write graphics into multi-page PDFs, but some graphics (i.e.
plots of large spatial datasets using levelplot()) can result in enormous
files. I'm curious if
Hi,
The following script (which I did not develop) is used to calculate and
plot a skewed normal curve. The script currently requires the user to
input six parameters, rather than reading these directly from a file.
I've been spinning wheels here, trying to figure out how to modify the
script
This is really a job for a database, and Excel is not a database (even
though many think it is). I have some clients that I have convinced
to create an Access database rather than use Excel (still MS product
so it can't be that scary, right?). They were often a little
reluctant at first because
Thank you!
Do you know why ifelse() sometimes returns NULL ?
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__
R-help@r-project.org
On 23-04-2012, at 21:37, phillip03 wrote:
Thank you!
Do you know why ifelse() sometimes returns NULL ?
Please provide a reproducible example for this phenomenon.
Berend
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R-help@r-project.org mailing list
On Mon, Apr 23, 2012 at 10:58:26AM -0700, cyclondude wrote:
Hello, very new to R, playing with tables, and I am trying to do
x - subset(data, columnlabel == x)
for every element in my column that I could find by using
table (data [,columnlabel])
Hi.
The following may be close to what
On Mon, Apr 23, 2012 at 04:02:45PM -0400, steve_fried...@nps.gov wrote:
Hi,
The following script (which I did not develop) is used to calculate and
plot a skewed normal curve. The script currently requires the user to
input six parameters, rather than reading these directly from a file.
Dear All,
I have just submitted a new version of the QCAGUI package on CRAN, it
should be propagated in a couple of days.
This version is nothing but a quick update to the latest Rcmdr base
package, and works (as usual) with the QCA package up to version 0.6-5
For the later versions of the QCA
Here is a method that uses negative look behind:
tmp - c('mutation','nonmutated','unmutated','verymutated','other')
grep((?!un)(?!non)muta, tmp, perl=TRUE)
[1] 1 4
it looks for muta that is not immediatly preceeded by un or non (but
it would match unusually mutated since the un is not
One option is to subtract the continuous variable from y before doing
the regression (this works with any regression package/function). The
probably better way in R is to use the 'offset' function:
formula = I(log(data$AB.obs + 1, 10)-log(data$SIZE,10)) ~
log(data$SIZE, 10) + data$Y
formula =
Hi
EMU1993-(for (i in 1:nrow(data)){
+ ifelse(year==1992,sum(avgflowEMU),0)
+ })
EMU1993
NULL
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That's not the ifelse() that's the for loop returning NULL
(everything's a function!). If you put the assignment inside you'll
get expected behavior.
x - (for(i in 1:5) i) # Strange
for(i in 1:5) x- i # Normal (but notice you only get the last value
because previous ones are overwritten)
Michael
On Apr 23, 2012, at 5:21 PM, R. Michael Weylandt wrote:
That's not the ifelse() that's the for loop returning NULL
(everything's a function!). If you put the assignment inside you'll
get expected behavior.
x - (for(i in 1:5) i) # Strange
for(i in 1:5) x- i # Normal (but notice you only get
Yes. That is what I was looking for. Is there a simple way to (in this
scenario)
out[[1]]
v1 v2
1 a 1
4 a 2
7 a 3
a - out[[1]]
for each one?
Thanks!
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Petr,
Thank you very much this works. A little more tweaking and I'll have what
I need.
Thanks
Steve Friedman Ph. D.
Ecologist / Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034
steve_fried...@nps.gov
Office (305) 224
There are, but it's generally considered better style to keep them all
in a single list and use lapply() if you want to do things to each
element.
Michael
On Mon, Apr 23, 2012 at 5:33 PM, cyclondude hans.thomps...@gmail.com wrote:
Yes. That is what I was looking for. Is there a simple way to
I recommend not putting POSIXlt vectors in data frames because of memory use
and added complexity of the resulting data frame. That is, use
colClasses = c('character', 'POSIXct', 'POSIXct')
instead. The POSIXlt values will still be created as temporary variables for
reading in, but the data
No, RData saves both the variable name and corresponding content of multiple
variables. rda saves content of one variable, with no associated name. The
latter allows for greater flexibility in importing the data later into
different working environments, the former is convenient for
Hi, r-help members.
I have a question about summing two density distributions. I have two
samples from which I've estimated hazard parameters for a Gompertz mortality
model. With those parameters, I can calculate the PDF (survival function
times hazard function) of ages-at-death in a birth
All,
I am trying to estimate the parameters of a bivariate Von Mises distributions.
I am looking for somebody to point me in the direction of an R package or
function that does this. I have noted the existing packages that allow for
obtaining the density values once the parameters have been
Hello everyone, I am currently using the mvpart package and would like to
change the color scheme it uses, and was hoping someone could help me out. All
of the papers I have found have used a grayscale but I can't seem to figure out
how they did that! Currently, mvpart plots barplots in a
Hi Jeff.
Can you point me toward the documentation for rda saves content of
one variable, with no associated name? I don't seem to find it in
?save ?load etc.
Thanks,
Ista
On Mon, Apr 23, 2012 at 5:58 PM, Jeff Newmiller
jdnew...@dcn.davis.ca.us wrote:
No, RData saves both the variable name and
I'd like to fit a multinomial log-linear model for 4 categories of the form:
log[(P(D=i | x)/P(D=0 | x)] = alpha + beta_i x for i = 1,2,3.
Is there a way to impose such a constraint in the multinom function of nnet
or another function of some library?
regards,
Hosotsubo
--
Moritaka
Hi,
I have a question on generating random variables based on zipf-mandelbrot
distribution.
So when I execute the following lines:
ZM = lnre (zm, alpha = 2/3, B=0.1)
zmsample = rlnre (ZM, n =100)
zmsample
It generates 100 random values based on a zipf-mandelbrot distribution as
below. But how
Lists of numbers of length ~1000 are no problem for the wilcox.test()
function (Mann-Whitney is a special case) if you leave the default
exact = NULL.
The choice of test is all yours.
Michael
On Mon, Apr 23, 2012 at 12:39 PM, aoife doherty aaral.si...@gmail.com wrote:
Hello
I have two lists
My bad, I was thinking of rds (?saveRDS). RData and rda are mentioned under
?data as alternate file extensions for the same data format. Sorry for posting
without checking first.
---
Jeff NewmillerThe
It is indeed the fact you're plotting factors, but unless you say what
as intended is, it's hard to provide exactly what you're seeking.
Perhaps this will help though:
X - factor(sample(letters[1:5], 15, TRUE))
Y - rnorm(15)
dats - data.frame(X, Y)
plot(Y ~ X, data = dats) # No good
plot(X ~ Y,
It depends how you want to ensure that condition -- if you just want
to censor at an upper bound of 6k, this is easy:
pmin(zmsample, 6000)
If you want to sample as before but it just happens to all be less
than 6000 -- that's not really a rigorous statement, but just go with
it -- intuitively,
From: dwinsem...@comcast.net
To: leanneheis...@hotmail.com
Subject: Re: [R] change color scheme in mvpart
Date: Mon, 23 Apr 2012 19:20:06 -0400
The fact that you are posting in HTML indicates that a) you have
either not read the Posting Guide or b) do not know enough about your
mailer to
Hi folks.
If I have the following in my data
eventpH1pH2
14.0 6.0
24.3 5.9
34.1 6.1
44.0 5.9
and on and on. for about 400 events
Is there a way I can get R to plot event vs. pH1 and event vs. pH2 and
then do a loess or
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