Did you read the install instructions? I don't even know what this package does
but it does have special instructions for installation.
---
Jeff NewmillerThe . . Go Live...
Thanks for the further tips! I'll look at the R Internals manual,
the other built-in devices, and the RSvgDevice package. And I'm
still looking for the S source code, but I have a feeling that I'll
wind up writing the device before I find the source code.
It may be useful to look at existing
Hi all,
Using filled.contour...
foo - matrix(seq(0.1, 0.9, 0.1), ncol = 3)
filled.contour(foo)
how can I set the key axis to give percentages?
And is there a way to automatically label the key axis except for placing text
there?
Thanks
Haiko
Haiko Lietz
GESIS - Leibniz Institute for the
On Mon, 18 Aug 2014 08:51:57 AM Lietz, Haiko wrote:
Hi all,
Using filled.contour...
foo - matrix(seq(0.1, 0.9, 0.1), ncol = 3)
filled.contour(foo)
how can I set the key axis to give percentages?
And is there a way to automatically label the key axis except for
placing
text there?
The knots are deleted anyway (Deleting unnecessary knots ...). It
seems to make no difference.
On 08/14/2014 06:06 PM, David Winsemius wrote:
On Aug 14, 2014, at 7:17 AM, Jan Stanstrup wrote:
Thank you very much for this snippet!
I used it on my data and indeed it does give intervals
Hi all, i have this data.frame with 3 columns: campaña, visitas,
compras.
This is the actual data.frame:
Campaña Visitas Compras
1 facebook-Ads1 524 2
2 faceBOOK-Ads1 487 24
3 fcebook-ads12258 4
4
Hello,
As you can read in the small code below, I do not represent directly my data
but its inverse in the limits of my radial plot and I would like to reorder
grid labelling from the upper value at the center and the lower one at the
graph's border. In my example I would like to have 40 at
Another approach using reshape2:
library(reshape2)
# Construct data/ add column of row numbers
set.seed(42)
mydf - data.frame(t(replicate(100, sample(c(red, blue,
+ green, yellow, NA), 4
mydf - data.frame(rows=1:100, mydf)
colnames(mydf) - c(row, rank1, rank2, rank3, rank4)
On 18/08/2014 9:35 AM, Hugues François wrote:
Hello,
As you can read in the small code below, I do not represent directly my data
but its inverse in the limits of my radial plot and I would like to reorder
grid labelling from the upper value at the center and the lower one at the
gsub will work on a column of a data.frame, not an entire data.frame.
gsub(pattern = facebook-Ads1, FBAds, DataGoogle1$Campaña)
[1] FBAds faceBOOK-Ads1 fcebook-ads12 Email1
mail1
[6] referral1
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Mon, Aug 18, 2014 at 2:13 AM, Omar André
Hello,
Try reading your data with option stringsAsFactors = FALSE. It seems
that your strings are being read as factors, which are coded as integers.
DataGoogle1 - read.csv(file = DataGoogle2.csv, header = T,
stringsAsFactors = FALSE)
Hope this helps,
Rui Barradas
Em 18-08-2014 10:13,
Hello,
Thanks for your answer. Of course I read the help but I didn't understand how
to retrieve data from radial.lim. Maybe it is trivial for you but not for me.
Attached to this message you will find some test data but you will need to cast
them using reshape and this line (assuming you
On 18/08/2014 12:25 PM, Hugues François wrote:
Hello,
Thanks for your answer. Of course I read the help but I didn't understand how
to retrieve data from radial.lim. Maybe it is trivial for you but not for me.
Attached to this message you will find some test data but you will need to cast
Really sorry for this mistake... I have several graph to do for different
weather station and mylim and sta are elements to loop on each one. For the
example, the code should be the one below.
Sometimes I feel dumb since I have read the pretty thing but I didn't
understand the syntax
On 18/08/2014 1:00 PM, Hugues François wrote:
Really sorry for this mistake... I have several graph to do for different
weather station and mylim and sta are elements to loop on each one. For the
example, the code should be the one below.
Sometimes I feel dumb since I have read the pretty
I had that result sometimes when testing as well. You don't offer any code so
there's nothing I can do to follow-up.
--
David.
On Aug 18, 2014, at 4:56 AM, Jan Stanstrup wrote:
The knots are deleted anyway (Deleting unnecessary knots ...). It seems to
make no difference.
On
Hello All,
I have a question regarding building multiple models and then scoring new
data with these models. I have been tasked with converting existing SAS
modeling code into equivalent R code, but unfortunately I rarely use R so
I'm in unfamiliar territory. I've think I've found a good way to
Hi all,
I am using prcomp to do Principle Components Analysis and have run into a
problem regarding the scale of the axes on my plots. I am using prcomp to
analyze a set of 25 morphological measurements taken on each of 161
individual frogs. I used the biplot function to produce a figure of PC1
Hi there,
I have several saved data files (e.g., A.RData, B.RData and C.RData). In
each file, there are some objects with same names but different
contents. Now, I need to compare those objects through plotting.
However, I can't find a way to load them into a workspace. The only
thing I can
Hi,
There is a scale factor associated with biplot when plotting the PCA
result. Please read the help page of biplot.princomp or/and the source
code of this function.
HIH,
Jinsong
On 2014/8/18 16:31, John Romansic wrote:
Hi all,
I am using prcomp to do Principle Components Analysis and
At the risk of being old-fashioned, I suggest doing this in a
for-loop. Why struggle to fit this into the dplyr framework when a
straight-forward loop will do the trick?
This is untested in the absence of example data, but something along
the lines of
models - list()
predictions - list()
for(g
Have you tried the 'envir' argument to load()? E.g.,
envA - new.environment()
load(A.RData, envir=envA)
envB - new.environment()
load(B.RData, envir=envB)
plot(A$object, B$object)
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Mon, Aug 18, 2014 at 5:30 PM, Jinsong Zhao
On 19/08/14 14:20, William Dunlap wrote:
Have you tried the 'envir' argument to load()? E.g.,
envA - new.environment()
load(A.RData, envir=envA)
envB - new.environment()
load(B.RData, envir=envB)
plot(A$object, B$object)
Did you mean
plot(envA$object, envB$object)
Rolf,
Yes, I meant to write envA$object, etc, but did not read it twice
before running off to dinner. Thanks.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Mon, Aug 18, 2014 at 7:52 PM, Rolf Turner r.tur...@auckland.ac.nz wrote:
On 19/08/14 14:20, William Dunlap wrote:
Have you tried
I'm making a thesis with bonimial negative bivariate regression, please help me
to be delivered program. thank you.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On 2014/8/18 19:20, William Dunlap wrote:
Have you tried the 'envir' argument to load()? E.g.,
envA - new.environment()
load(A.RData, envir=envA)
envB - new.environment()
load(B.RData, envir=envB)
plot(A$object, B$object)
Bill Dunlap
TIBCO Software
wdunlap tibco.com
Hola a todos, he escrito al autor del código y me ha respondido lo siguiente:
To be honest, a group of collaborators have recently rewritten and improved
this entire code for prediction and will soon release a nice package to do it
all.
Creo que podemos dar el tema por cerrado y quedo a la
Hola Comunidad grandiosa
Estoy trabajando con el paquete survival.
1.)
Y estoy queriendo usar el paquete xtable en sweave y dice que es
incompatible con (por ejemplo summary(coxph))
2.) y como no me sale estoy tratando de llamar a un valor de summary(coxph)
con /Sexpr tampoco funciona.
Bueno si
Hola Ernesto,
Te sugiero trabajar con el paquete texreg:
Philip Leifeld (2013). texreg: Conversion of Statistical Model Output in
R to
LaTeX and HTML Tables. Journal of Statistical Software, 55(8), 1-24. URL
http://www.jstatsoft.org/v55/i08/.
Saludos,
Jorge.-
2014-08-19 9:26 GMT+10:00
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