Solution:
http://stackoverflow.com/questions/28447247/change-in-google-maps-api-v3-on-feb-10-2015-breaks-existing-maps-created-using
https://maps.google.com/maps/api/js?sensor=falsev=3.18
De: Janue Miret, Jofre
Enviat el: diumenge, 15 / febrer / 2015
On 17/02/2015 11:03 PM, Hadley Wickham wrote:
On Tue, Feb 17, 2015 at 6:02 PM, Hervé Pagès hpa...@fredhutch.org wrote:
On 02/17/2015 02:10 PM, Erich Neuwirth wrote:
AFAIK dplyr imports magrtittr.
So dplyr ses %% from migrittr, it does not have its own version.
But it has its own man page so
Hi List,
I am trying to assign a large expression. It has about 140 lines of code, so
of course this is cumbersome:
list('10001'=list(panel=c(PanelOne=944), seltype='Equal'),
'10002'=list(panel=c(PanelOne=454), seltype='Equal'),
'10003'=list(panel=c(PanelOne=1210), seltype='Equal'),
Hi Ben and JS,
Thanks for the reply.
I tried using: hessian(func = h_x, x, method = complex), it gives zero,
that's good.
# R code
hess.h - hessian(func = h_x, x, method = complex)
mat - h_x(x)*hess.h - grad(h_x, x) %o% grad(h_x, x)
mat
[,1][,2] [,3][,4]
[1,] 2060602
Dear Aron,
- Set the build tools in RStudio to build a package (via Tools - Project
options - Build tools)
- Use the Build pane to Build and then Check the package
Best regards,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team
Have a look at FAQ 7.31
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie Kwaliteitszorg / team Biometrics Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belgium
To call in the statistician after the experiment is done may
Hello,
I am working on a research project at the University of Maryland and as
part of this project I am trying to perform a bayesian analysis. I am
facing difficulty specifying priors using the MCMClogit package. My
question is how do we specify a column vector as a prior mean and a square
dear friends - sorry to ask another simple question -
I have dates set up as this:
dates #[1] 2003-01-21 01:08:00
To handle it I did
as.POSIXlt(dates) 2003-01-21 01:08:00 CET
but noticed that during write.table it was apparently better to take it
further
Thanks! That’s perfect. Key is to load the local github repo into an Rstudio
project first.
--
Aron Lindberg
Doctoral Candidate, Information Systems
Weatherhead School of Management
Case Western Reserve University
aronlindberg.github.io
On Wed, Feb 18, 2015 at 11:39 AM, Thierry
On 18 Feb 2015, at 18:45 , Troels Ring tr...@gvdnet.dk wrote:
dear friends - sorry to ask another simple question -
I have dates set up as this:
dates #[1] 2003-01-21 01:08:00
To handle it I did
as.POSIXlt(dates) 2003-01-21 01:08:00 CET
but noticed that during write.table it was
Hello,
Try
as.POSIXlt(1043107680, origin = 1970-01-01, tz = CET)
Hope this helps,
Rui Barradas
Em 18-02-2015 17:45, Troels Ring escreveu:
dear friends - sorry to ask another simple question -
I have dates set up as this:
dates #[1] 2003-01-21 01:08:00
To handle it I did
as.POSIXlt(dates)
David's almost works except it catches the MONTH column, just add an
empty metacharacter tho.
c(DAY,
MONTH,
YEAR,
SA_TUES,
SA_MON,
SU_WED,
CH_TUES,
CH_WED,
CH_MON,
AR_TUES,
AR_WED,
AR_MON,
SA_THUR,
SU_FRI,
CH_THUR,
CH_FRI,
AR_THUR,
AR_FRI)- columns
sa_ind - grep(SA_,columns)
days - gsub(SA_,,
Thanks a lot and thanks to Rui
Troels
Den 18-02-2015 kl. 20:14 skrev peter dalgaard:
On 18 Feb 2015, at 18:45 , Troels Ring tr...@gvdnet.dk wrote:
dear friends - sorry to ask another simple question -
I have dates set up as this:
dates #[1] 2003-01-21 01:08:00
To handle it I did
This question is getting pretty deep into numerical analysis theory. The usual
approach has already been mentioned... don't expect high accuracy in all
problems. Your specific problem could have a special technique somewhere, but
don't be surprised if we are not experts in your specific
On Feb 18, 2015, at 12:27 PM, Kate Ignatius wrote:
Hi,
I've got a complicated grep problem (or not)... I currently have a
file with the headings as follows:
Lets assume these values are in a character vector named 'dat'.
SA_TUES
SA_MON
SU_WED
CH_TUES
CH_WED
CH_MON
AR_TUES
AR_WED
Thanks Thierry for the pointer, that's explains the problem.
Is there anything I can do about the matrix instability or numerical
inaccuracy?
Mike
On Wed, Feb 18, 2015 at 11:57 AM, Thierry Onkelinx thierry.onkel...@inbo.be
wrote:
Have a look at FAQ 7.31
ir. Thierry Onkelinx
Instituut voor
Hi,
I've got a complicated grep problem (or not)... I currently have a
file with the headings as follows:
DAY
MONTH
YEAR
SA_TUES
SA_MON
SU_WED
CH_TUES
CH_WED
CH_MON
AR_TUES
AR_WED
AR_MON
SA_THUR
SU_FRI
CH_THUR
CH_FRI
AR_THUR
AR_FRI
I want to grep out all columns that have SA at the beginning
On Feb 18, 2015, at 1:13 PM, C W wrote:
Thanks Thierry for the pointer, that's explains the problem.
Is there anything I can do about the matrix instability or numerical
inaccuracy?
There are matrix methods in the Rmpfr package that support increased precision,
but it is implemented with
On Feb 18, 2015, at 1:54 PM, David Winsemius dwinsem...@comcast.net wrote:
On Feb 18, 2015, at 1:13 PM, C W wrote:
Thanks Thierry for the pointer, that's explains the problem.
Is there anything I can do about the matrix instability or numerical
inaccuracy?
There are matrix methods
On Feb 18, 2015, at 2:15 PM, Spencer Graves spencer.gra...@prodsyse.com
wrote:
On Feb 18, 2015, at 1:54 PM, David Winsemius dwinsem...@comcast.net
mailto:dwinsem...@comcast.net wrote:
On Feb 18, 2015, at 1:13 PM, C W wrote:
Thanks Thierry for the pointer, that's explains the
Hi All,
In short: what’s a good workflow for forking/rewriting/testing code in packages?
I’m trying to contribute to a package on Github. So I fork it and then clone my
forked repo into my desktop, and then I open the files I want to edit in
RStudio.
However, to actually test that the code
Some observations -- no solution here though:
1) the code is not executable. I tried. Maybe that makes it reproducible!
Typos such as stat mod, undefined Q etc.
2) My experience is that any setup with a ?apply approach that doesn't
then check to see that the structure of the data is correct
C W tmrsg11 at gmail.com writes:
Hi list,
I am running the following R code, the answer should be zero. But R gives
a very small negative number, what should I do?
##R code
library(numDeriv)
h_x - function(x){
a = x[1]
b = x[2]
c = x[3]
d = x[4]
(a^2 + c^2 + d^2) *
Dear R helpers,
I am currently trying to analyze data with a cox proportional hazard survival
analysis. For one of my datasets, the proportional hazards assumption is
violated. Reading the literature, it seems that the weighted version of cox PH
(function coxphw() ) is a good alternative in
Dear All,
Apologies for mailing it to the whole crowd. This is Mittal, presently working
in a Project where we have build a platform for displaying recommendations and
the results are based on the statistical models.
I have gone through the CRAN repository to look out for an package which
Tirsdag 17. februar 2015 15.50.27 skrev David Winsemius:
On Feb 17, 2015, at 3:58 AM, Knut Hansen wrote:
Dear list,
I have a vector:
my.vector - c(A, B, C, D, E, F, G)
and two other:
vec1 - c(p, q, r, s, t)
vec2 - c(x, y, z)
I want to substitute elements b and e in
Hi,
Since all entries in your hessian matrix and grad vector are integers, I
suggest you execute the following for mat assignment.
mat - round(h_x(x),digits=0)*round(hess.h,digits=0) - round(grad(h_x,
x),digits=0) %o% round(grad(h_x, x),digits=0)
mat
[,1] [,2] [,3]
You did not put the altered columns back into the data.frame,
so glm() never saw them. Does the following work?
func - function(x,y,z) {
#x is a data frame
#y is a formula for the regression
#z vector of names of columns of x to convert to factors
for (name in z) {
x[[name]] -
Hello,
I am passing a df to a function and then want to declare factors (based on
a vector of column names in the df) for a logistic regression. I am having
trouble - R doesn't seem to recognize the factors as declared in the
function? Below is my code. Does anyone have any ideas?
MyFunction -
Thanks! That was helpful. Although I think there was a typo in the last line:
selected - sort(unique(unlist(all_ind)))
but I figured it out :)
K.
On Wed, Feb 18, 2015 at 4:10 PM, Federico Lasa fel...@gmail.com wrote:
David's almost works except it catches the MONTH column, just add an
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