Re: [R] ggplot2: Controlling width of line

Not sure why you are making this so complicated. In what way is the following not meeting your expectations? ggplot( data=matz , aes( x = X1 , y = value , col=X2 , lty=X2 , shape=X2 , size=mylwd ) ) + geom_line() +

Re: [R] how to work with time of day (independent of date)

Sys.setenv( TZ="Etc/GMT+8" ) executed before converting to POSIXct works for me, though using that string with the tz parameter also works. You should read ?Sys.timezone. For windows, look at the files in C:\Program Files\R\R-3.2.2\share\zoneinfo and note that PST is not defined though PST8PDT

Re: [R] User-defined functions in dplyr

So in this case, "create_bins" returns a vector and I still get the same error. create_bins <- function(x, nBins) { Breaks <- unique(quantile(x$pred, probs = seq(0, 1, 1/nBins))) bin <- cut(x$pred, breaks = Breaks, include.lowest = TRUE) bin } ### Using dplyr (fails) nBins = 10 by_group

Re: [R] Achieve independent fine user control of ggplot geom settings when using groups in multiple geom's

I'd recommend reading the ggplot2 book - learning more about how scales work in ggplot2 will help you understand why this isn't possible. Hadley On Thu, Oct 29, 2015 at 6:31 PM, sbihorel wrote: > Thank for your reply, > > I may accept your point about the

Re: [R] monte carlo simulations in permanova in vegan package

Thank you Jari, It seems now that my question is morphing more into a statistical one, and perhaps not appropriate for R-help list, so apologies. Yes we are talking about the latest versions of the vegan and permute packages. When there are an insufficient number of permutations available due

Re: [R] How to direct R to read commands from a text file

I should think this thread contains all you need: http://stackoverflow.com/questions/18306362/run-r-script-from-command-line B. On Oct 30, 2015, at 11:07 PM, Gregory Coats wrote: > All of the R commands that I want to issue are in a text file that concludes > with the R

Re: [R] If else

Using numeric for missing sounds like asking for trouble. But if you must, something like mydata$confusingWillCauseProblemsLater <- ifelse( is.na(mydata$sex), 0, as.numeric(factor(mydata$sex, levels = c("M", "F" should do it. Best, Ista On Fri, Oct 30,

[R] How to direct R to read commands from a text file

All of the R commands that I want to issue are in a text file that concludes with the R command quit (save = “yes”), and is called R_commands.txt. I can start R, and then manually issue source (“R_commands.txt”). But I would prefer to issue, from the bash command line, a one line command,

[R] If else

Hi all, Iam trying to change character to numeric but have probelm mydata <- read.table(header=TRUE, text=', sep=" " id sex 1 NA 2 NA 3 M 4 F 5 M 6 F 7 F ') if sex is missing then sex=0; if sex is"M" then sex=1; if sex is"F" then

Re: [R] If else

I am trying to change the mydata$sex from character to numeric I want teh out put like id sex 1 NA 0 2 NA 0 3 M 1 4 F 2 5 M1 6 F 2 7 F2 mydata$sex1 <- 0 if(mydata$sex =="M " ){ mydata$sex1<-1 } else { mydata$sex1<-2

Re: [R] [FORGED] If else

On 31/10/15 14:15, Val wrote: Hi all, Iam trying to change character to numeric but have probelm mydata <- read.table(header=TRUE, text=', sep=" " id sex 1 NA 2 NA 3 M 4 F 5 M 6 F 7 F ') if sex is missing then sex=0; if

[R] A simple crop/clip of a png map

I have a 5.76" x 5.75" png image which I would like to crop to some inch size. To use as a report header (after placing some title text on it). So how to use R to crop a nice rectangle from my image? Thanks for your thoughts Jim Burke [[alternative HTML version deleted]]

[R] Nested ANOVA yields surprising results

Dear R users: All textbook references that I consult say that in a nested ANOVA (e.g., A/B), the F statistic for factor A should be calculated as F_A = MS_A / MS_(B within A). But when I run this simple example: set.seed(1) A <- factor(rep(1:3, each=4)) B <- factor(rep(1:2, 3, each=2)) Y <-

[R] How to add legend to 2 different data frame overplot?

Hi, I am trying to do add a legend to an overplot, something like this: ggplot() + geom_density(data = df1, aes(x = x), fill = "green", show_guide = FALSE) + geom_area(data = df2, aes(x = x), fill = "yellow", show_guide = FALSE) + scale_color_manual(values = c("green", "yellow"),

Re: [R] Achieve independent fine user control of ggplot geom settings when using groups in multiple geom's

Thanks Hadley, I will certainly read your book. Unfortunately, what you just confirmed as the developer of ggplot means that ggplot is non-starter for what I want to build. Too bad, I was starting to appreciate some of its advantages over lattice. About your book, in case I do not find a

[R] ggplot2: Controlling width of line

Hi, I was trying to increase the size of certain lines in my plot (samples 'B' and 'D' in example below). However, when I try to modify the line size, I seem to screw up the linetypes. Also, is there a way to reflect the line size in the legend? Here is some sample code for illustration:

Re: [R] Nested effects (was: "no subject")

On 31/10/15 03:32, Wagenaar, Daniel (wagenadl) wrote: Dear R users: All textbook references that I consult say that in a nested ANOVA (e.g., A/B), the F statistic for factor A should be calculated as F_A = MS_A / MS_(B within A). But when I run this simple example: set.seed(1) A =

Re: [R] User-defined functions in dplyr

The error message is not very helpful and the stack trace is pretty inscrutable as well > dplyr::group_by(df, models) %>% dplyr::summarize(create_bins) Error: not a vector > traceback() 14: stop(list(message = "not a vector", call = NULL, cppstack = NULL)) 13: .Call("dplyr_summarise_impl", PACKAGE

[R] (no subject)

Dear R users: All textbook references that I consult say that in a nested ANOVA (e.g., A/B), the F statistic for factor A should be calculated as F_A = MS_A / MS_(B within A). But when I run this simple example: set.seed(1) A = factor(rep(1:3, each=4)) B = factor(rep(1:2, 3, each=2)) Y =

Re: [R] User-defined functions in dplyr

dplyr::mutate is probably what you want instead of dplyr::summarize: create_bins3 <- function (xpred, nBins) { Breaks <- unique(quantile(xpred, probs = seq(0, 1, 1/nBins))) bin <- cut(xpred, breaks = Breaks, include.lowest = TRUE) bin } dplyr::group_by(df, models) %>%

[R] Error: Invalid First Argument in DPlyr

I'm getting an "invalid first argument" error for the following. However, con is an actual connection and is set up properly. So what does this error actually refer to? library(dplyr) con <- RSQLServer::src_sqlserver("***", database = "***") myData <- con %>% tbl("table") %>% group_by(

Re: [R] (no subject)

Maybe you want summary(aov(Y ~ A + Error(A:B))) Kevin On Fri, Oct 30, 2015 at 9:32 AM, Wagenaar, Daniel (wagenadl) < wagen...@ucmail.uc.edu> wrote: > Dear R users: > > All textbook references that I consult say that in a nested ANOVA (e.g., > A/B), the F statistic for factor A should be

Re: [R] how to work with time of day (independent of date)

On 10/30/2015 11:17 AM, Mark Leeds wrote: Daniel: Just to complete my solution, here's the code for doing the mean. Didn't expect this to take 3 emails !!! Have a good weekend. temp <- tapply(f$value, f$justtimes, mean) finalDF <- data.frame(chrontimes = times(rownames(temp)), values = temp)

Re: [R] how to work with time of day (independent of date)

Bill, Your final words, "changes in spring and fall" reminds me of a problem I have yet to solve. Most of my data is logged in standard time (no daylight times) but often I see the note "daylight time encountered switching to UTC" even when I've specified "tz="PST". I hope I've been

Re: [R] Error: Invalid First Argument in DPlyr

You need to divide and conquer... find out which step is breaking the pipe by terminating it early at various points and if the problem is still not clear one you know which step is broken then give us a reproducible example. I am not familiar with RSQLServer specifically, but the version of

[R] how to work with time of day (independent of date)

I have a data frame with date/times represented as charaacter strings and and a value at that date/time. I want to get the mean value for each time of day, across days, and then plot time of day on the x-axis and means on the y-axis. R doesn't appear to have a built-in time of day time type

Re: [R] monte carlo simulations in permanova in vegan package

Thank you Jari, It seems now that my question is morphing more into a statistical one, and perhaps not appropriate for R-help list, so apologies. Yes we are talking about the latest versions of the vegan and permute packages. When there are an insufficient number of permutations available due

Re: [R] how to work with time of day (independent of date)

is this what you want: > df <- structure(list(date = structure(1:8, .Label = c("2015-10-29 00:50:00", + "2015-10-29 09:30:00", "2015-10-29 21:10:00", "2015-10-30 00:50:00", + "2015-10-30 09:30:00", "2015-10-30 21:10:00", "2015-10-31 00:50:00", + "2015-10-31 10:30:00"), class = "factor"), value =

Re: [R] how to work with time of day (independent of date)

You can use difftime objects to get the amount of time since the start of the current day. E.g., > dateTime <- as.POSIXlt( c("2015-10-29 00:50:00", + "2015-10-29 09:30:00", "2015-10-29 21:10:00", "2015-10-30 00:50:00", + "2015-10-30 09:30:00", "2015-10-30 21:10:00", "2015-10-31 00:50:00",

Re: [R] how to work with time of day (independent of date)

I get confused by this also, but I believe your time zone is US/Pacific, which specifies both the offset from UTC and the dates on which we switch between 'standard' (winter) and 'daylight savings' (summer). I think you would have to create a new time zone entry that is always UTC+8 hours, or

Re: [R-es] Sustitución NAs

Hola, Esta una forma de hacerlo. Fíjate que por la forma que has dado los datos, tienes blancos antes y después de cada cadena y por no cambiarlo, en vez de utilizar "is.na(datIn$COLEGIO)" he tenido que hacer lo que ves datIn$COLEGIO== " NA " #- > Lines <- " + | NOMBRE |

[R-es] Sustitución NAs

Hola a todos. Pongo esta tabla sencilla a ver si alguien puede echarme un cable. En la columna COLEGIO salen unos NAs.  | NOMBRE  | LOCALIDAD | COLEGIO | | JUAN | SANTANDER | A | | ALBERTO | LA RIOJA | C  | | MANUEL | MADRID | B | | MARTA | MADRID | NA | | IRENE | VALLADOLID | NA | | LUCAS |

[R-es] Seleccionar dos tklistbox a la vez

Buenas, Quiero, usando la libreria tcltk, poder seleccionar a la vez en dos listbox, pero s�lo me deja en uno u el otro, pero no los dos a la vez. He probado cambiando los selectmode a sus diferentes opciones (multiple, browse,single), pero cuando voy a seleccionar el segundo, me quita la

Re: [R-es] Seleccionar dos tklistbox a la vez

Era una bobaa, es añadir el exportselection="FALSE" Gracias igualmente From: j.para.fernan...@hotmail.com To: r-help-es@r-project.org Date: Fri, 30 Oct 2015 12:22:18 +0100 Subject: [R-es] Seleccionar dos tklistbox a la vez Buenas, Quiero, usando la libreria tcltk, poder seleccionar a la

[R-es] Paquete que autocargue

Buenas, Estoy creando un paquete y me gustar�a crear un acceso directo en el escritorio que al pulsar sobre el, abra R, cargue el paquete [ library(mipaquete) ] y ejecute la funcion inicio() �Es posible hacerlo? Gracias [[alternative HTML